Question Number 174194 by mokys last updated on 26/Jul/22 Answered by Mathspace last updated on 27/Jul/22 $$\left.\mathrm{1}\right)\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{\mathrm{10}} {x}\:{cos}^{\mathrm{10}} {x}\:{dx} \\ $$$${we}\:{kmow}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{\mathrm{2}{p}−\mathrm{1}}…
Question Number 174192 by Best1 last updated on 26/Jul/22 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {cosxe}^{\left({cosxdx}\right)} {dx}\:\:\:????? \\ $$ Commented by Best1 last updated on 27/Jul/22 $${help} \\ $$…
Question Number 108652 by mohammad17 last updated on 18/Aug/20 Commented by mohammad17 last updated on 18/Aug/20 $${sir}\:{are}\:{you}\:{can}\:{help}\:{me}\:{pleas}\:? \\ $$ Answered by Aziztisffola last updated on…
Question Number 174191 by Best1 last updated on 26/Jul/22 $$\:\:\:\:\:{intgrate}\:\int\left({x}+\mathrm{2}\right){cos}\left({x}^{\mathrm{2}} +\mathrm{4}{x}\right){dx}? \\ $$ Commented by mokys last updated on 26/Jul/22 $$=\:\frac{\mathrm{1}}{\mathrm{2}}\:{sin}\left({x}^{\mathrm{2}} +\mathrm{4}{x}\right)+{c} \\ $$ Commented…
Question Number 174190 by Best1 last updated on 26/Jul/22 Answered by MikeH last updated on 26/Jul/22 $$\left(\mathrm{19}\right)\:−{x}+\mathrm{2}{y}−\mathrm{1}=\mathrm{0} \\ $$$$\Rightarrow{d}\:=\:\mid\frac{−\left(\mathrm{2}\right)+\mathrm{2}\left(\mathrm{1}\right)−\mathrm{1}}{\:\sqrt{\left(−\mathrm{1}\right)^{\mathrm{2}} +\left(\mathrm{2}\right)^{\mathrm{2}} }}\mid\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}\:=\:\frac{\sqrt{\mathrm{5}}}{\mathrm{5}} \\ $$ Terms of…
Question Number 108637 by mathdave last updated on 18/Aug/20 Answered by bemath last updated on 18/Aug/20 $$\:\:\:\frac{\angle{bemath}\angle}{\multimap} \\ $$$$\int\:{dx}\:+\:\int\:\frac{\mathrm{2}{dx}}{\left({x}−\mathrm{3}\right)}+\int\:\frac{\mathrm{3}{dx}}{{x}−\mathrm{2}}= \\ $$$${x}\:+\mathrm{2ln}\:\mid{x}−\mathrm{3}\mid+\mathrm{3ln}\:\mid{x}−\mathrm{2}\mid+\:{C} \\ $$ Answered by…
Question Number 43092 by ajfour last updated on 07/Sep/18 Commented by tanmay.chaudhury50@gmail.com last updated on 07/Sep/18 $${i}\:{imagined}\:{spectacled}\:{curly}\:{haired}\:{boy}…{excellent}… \\ $$ Commented by ajfour last updated on…
Question Number 174153 by daus last updated on 26/Jul/22 Commented by mr W last updated on 26/Jul/22 $${the}\:{question}\:{meant}\:{maybe}\:\sqrt{{c}}+\sqrt{{d}}. \\ $$ Answered by mr W last…
Question Number 43080 by Rio Michael last updated on 07/Sep/18 Commented by math1967 last updated on 07/Sep/18 $${Nice} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated…
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