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Question-107728

Question Number 107728 by mathdave last updated on 12/Aug/20 Answered by john santu last updated on 12/Aug/20 $$\:\:\:\:\:\:\:\:\:\:\:\:\frac{\clubsuit\mathcal{JS}\clubsuit}{\ldots} \\ $$$${let}\:{f}\left({x}\right)={x}^{\mathrm{2020}} +{ax}^{\mathrm{2}} +{bx}+{c}\: \\ $$$$\left(\mathrm{1}\right){f}\left(\mathrm{2}\right)=\:\mathrm{2}^{\mathrm{2020}} +\mathrm{4}{a}+\mathrm{2}{b}+{c}\:=\:\mathrm{0}…

1-solve-the-D-E-dy-dx-y-tan-x-y-2-sec-x-2-find-x-k-1-25-x-x-3-k-1-3-solve-Z-2-4Z-0-

Question Number 107729 by  M±th+et+s last updated on 12/Aug/20 $$\left.\mathrm{1}\right)\:{solve}\:{the}\:{D}.{E}\:\:\:: \\ $$$$\frac{{dy}}{{dx}}−{y}\:{tan}\left({x}\right)=−{y}^{\mathrm{2}} {sec}\left({x}\right)\: \\ $$$$ \\ $$$$\left.\mathrm{2}\right){find}\:{x} \\ $$$$\underset{{k}=\mathrm{1}} {\overset{\mathrm{25}} {\prod}}\left({x}+\frac{{x}}{\mathrm{3}^{{k}} }\right)=\mathrm{1} \\ $$$$ \\…

Question-107718

Question Number 107718 by mohammad17 last updated on 12/Aug/20 Answered by Aziztisffola last updated on 12/Aug/20 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\overset{−} {\mathrm{z}}_{\mathrm{n}} =\overline {\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\mathrm{z}_{\mathrm{n}} }=\:\overset{−}…

integrate-e-x-2-x-2-dx-

Question Number 42182 by mondodotto@gmail.com last updated on 19/Aug/18 $$\boldsymbol{\mathrm{integrate}}\:\:\int\boldsymbol{\mathrm{e}}^{\boldsymbol{{x}}^{\mathrm{2}} } \boldsymbol{{x}}^{\mathrm{2}} \:\boldsymbol{{dx}} \\ $$ Commented by mondodotto@gmail.com last updated on 19/Aug/18 $$\boldsymbol{\mathrm{please}}\:\boldsymbol{\mathrm{help}}\:\boldsymbol{\mathrm{this}} \\ $$…

2tanx-5-tanx-2cotx-5-cotx-8-0-

Question Number 42170 by lucha116 last updated on 19/Aug/18 $$\left(\mathrm{2}{tanx}−\mathrm{5}\right){tanx}+\left(\mathrm{2}{cotx}−\mathrm{5}\right){cotx}−\mathrm{8}=\mathrm{0} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 19/Aug/18 $$\left(\mathrm{2}{a}−\mathrm{5}\right){a}+\left(\frac{\mathrm{2}}{{a}}−\mathrm{5}\right)\frac{\mathrm{1}}{{a}}−\mathrm{8}=\mathrm{0} \\ $$$$\left(\mathrm{2}{a}^{\mathrm{2}} −\mathrm{5}{a}\right)+\left(\frac{\mathrm{2}−\mathrm{5}{a}}{{a}}\right)\frac{\mathrm{1}}{{a}}−\mathrm{8}=\mathrm{0} \\ $$$$\mathrm{2}{a}^{\mathrm{2}}…