Question Number 107247 by ZiYangLee last updated on 09/Aug/20 Answered by abdomathmax last updated on 09/Aug/20 $$\mathrm{let}\:\mathrm{f}\left(\mathrm{t}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{e}^{−\mathrm{x}} −\mathrm{e}^{−\mathrm{2x}} }{\mathrm{x}}\:\mathrm{e}^{−\mathrm{tx}} \:\mathrm{dx}\:\mathrm{with}\:\mathrm{t}\geqslant\mathrm{0} \\ $$$$\mathrm{we}\:\mathrm{hsve}\:\mathrm{f}^{'} \left(\mathrm{t}\right)\:=−\int_{\mathrm{0}}…
Question Number 41699 by mondodotto@gmail.com last updated on 11/Aug/18 $$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{perpendicular}}\:\boldsymbol{\mathrm{distance}}\:\boldsymbol{\mathrm{btn}} \\ $$$$\boldsymbol{\mathrm{two}}\:\boldsymbol{\mathrm{lines}}\:\boldsymbol{{y}}=\mathrm{2}\boldsymbol{{x}}−\mathrm{3} \\ $$$$\boldsymbol{\mathrm{and}}\:\boldsymbol{{y}}=\mathrm{3}\boldsymbol{{x}}−\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 172749 by saly last updated on 01/Jul/22 Commented by saly last updated on 01/Jul/22 $$\:\:\:\:\:\:{Hepl}\:{me}\:\:{C},{D},{E} \\ $$ Commented by kaivan.ahmadi last updated on…
Question Number 172740 by SANOGO last updated on 30/Jun/22 Commented by Rasheed.Sindhi last updated on 30/Jun/22 $${Could}\:{you}\:{please}\:{translate}\:{into} \\ $$$$\mathcal{E}{nglish}? \\ $$ Answered by JDamian last…
Question Number 41671 by mondodotto@gmail.com last updated on 11/Aug/18 $$\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{p}}=\mathrm{6}.\mathrm{4}×\mathrm{10}^{\mathrm{4}} \:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{q}}=\mathrm{3}.\mathrm{2}×\mathrm{10}^{\mathrm{5}} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{values}}\:\boldsymbol{\mathrm{of}} \\ $$$$\left(\boldsymbol{\mathrm{i}}\right)\boldsymbol{\mathrm{p}}×\boldsymbol{\mathrm{q}} \\ $$$$\left(\boldsymbol{\mathrm{ii}}\right)\boldsymbol{\mathrm{p}}+\boldsymbol{\mathrm{q}} \\ $$$$\boldsymbol{\mathrm{write}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{answers}}\:\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{standard}}\:\boldsymbol{\mathrm{form}} \\ $$ Terms of Service Privacy…
Question Number 107202 by hgrocks last updated on 09/Aug/20 Answered by EmericGent last updated on 09/Aug/20 $$\int_{\mathrm{0}} ^{\mathrm{1}/\mathrm{2}} \:\frac{{ln}\:\mathrm{1}-{t}}{{t}}\:{dt}\:=\:-\int_{\mathrm{0}} ^{\mathrm{1}/\mathrm{2}} \underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{t}^{{k}-\mathrm{1}} }{{k}}\:{dt} \\…
Question Number 107198 by abony1303 last updated on 09/Aug/20 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{given}\:\mathrm{equation}: \\ $$$$\left(\mathrm{x}+\frac{\mathrm{x}}{\mathrm{3}^{\mathrm{1}} }\right)\centerdot\left(\mathrm{x}+\frac{\mathrm{x}}{\mathrm{3}^{\mathrm{2}} }\right)\centerdot\left(\mathrm{x}+\frac{\mathrm{x}}{\mathrm{3}^{\mathrm{3}} }\right)\centerdot\left(\mathrm{x}+\frac{\mathrm{x}}{\mathrm{3}^{\mathrm{4}} }\right)\centerdot…\centerdot\left(\mathrm{x}+\frac{\mathrm{x}}{\mathrm{3}^{\mathrm{25}} }\right)=\mathrm{1} \\ $$$$\left.\mathrm{A}\left.\right)\left.\frac{\mathrm{3}^{\mathrm{51}} }{\mathrm{2}\centerdot\left(\mathrm{3}^{\mathrm{50}} −\mathrm{1}\right)}\left.\:\:\mathrm{B}\right)\frac{\mathrm{3}^{\mathrm{52}} }{\mathrm{2}\centerdot\left(\mathrm{3}^{\mathrm{51}} −\mathrm{1}\right)}\:\:\mathrm{C}\right)\:\frac{\mathrm{3}^{\mathrm{50}} }{\mathrm{2}\centerdot\left(\mathrm{3}^{\mathrm{50}} −\mathrm{1}\right)}\:\:\mathrm{D}\right)\:\frac{\mathrm{3}^{\mathrm{51}}…
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