Question Number 106654 by mohammad17 last updated on 06/Aug/20 Answered by bemath last updated on 06/Aug/20 $$\mathrm{total}\:\mathrm{area}\:=\:\mathrm{2}\underset{\mathrm{0}} {\overset{\mathrm{2}} {\int}}\left(\mathrm{4}−\mathrm{x}^{\mathrm{2}} \right)\mathrm{dx}\: \\ $$$$=\:\mathrm{2}\mid\left(\mathrm{4x}−\frac{\mathrm{1}}{\mathrm{3}}\mathrm{x}^{\mathrm{3}} \right)\mid_{\mathrm{0}} ^{\mathrm{2}} =\mathrm{2}\left(\mathrm{8}−\frac{\mathrm{8}}{\mathrm{3}}\right)=\frac{\mathrm{32}}{\mathrm{3}}…
Question Number 106648 by Tinku Tara last updated on 06/Aug/20 $$\mathrm{App}\:\mathrm{Updates}: \\ $$$$\mathrm{Please}\:\mathrm{update}\:\mathrm{to}\:\mathrm{latest}\:\mathrm{version}\:\mathrm{of} \\ $$$$\mathrm{app}\:\mathrm{2}.\mathrm{132}.\:\mathrm{It}\:\mathrm{fixes}\:\mathrm{some}\:\mathrm{bugs}\:\mathrm{and} \\ $$$$\mathrm{characters}\:\mathrm{drawing}\:\mathrm{is}\:\mathrm{also}\:\mathrm{improved} \\ $$$$\mathrm{so}\:\mathrm{characters}\:\mathrm{will}\:\mathrm{now}\:\mathrm{appear}\:\mathrm{smooth}. \\ $$$$\mathrm{Download}\:\mathrm{from}\:\mathrm{playstore}. \\ $$ Commented by…
Question Number 106644 by ZiYangLee last updated on 06/Aug/20 $$\mathrm{Let}\:\mathrm{P}\left(\mathrm{x}\right)\:\mathrm{be}\:\mathrm{a}\:\mathrm{polynomial}\:\mathrm{of}\:\mathrm{degree}\:\mathrm{n} \\ $$$$\mathrm{with}\:\mathrm{real}\:\mathrm{coefficients}. \\ $$$$\mathrm{Prove}\:\mathrm{that}\:\underset{\mathrm{k}=\mathrm{0}} {\overset{\mathrm{n}} {\sum}}\frac{\mathrm{P}^{\left(\mathrm{k}\right)} \left(\mathrm{0}\right)}{\left(\mathrm{k}+\mathrm{1}\right)!}=\underset{\mathrm{k}=\mathrm{0}} {\overset{\mathrm{n}} {\sum}}\frac{\left(−\mathrm{1}\right)^{\mathrm{k}} \mathrm{P}^{\left(\mathrm{k}\right)} \left(\mathrm{1}\right)}{\left(\mathrm{k}+\mathrm{1}\right)!} \\ $$$$ \\ $$…
Question Number 41108 by mondodotto@gmail.com last updated on 02/Aug/18 $$\boldsymbol{\mathrm{evaluate}}\:\int\boldsymbol{{x}}^{\boldsymbol{{i}}} \boldsymbol{{dx}} \\ $$$$\boldsymbol{\mathrm{where}}\:\boldsymbol{{i}}=\sqrt{−\mathrm{1}} \\ $$ Answered by MJS last updated on 02/Aug/18 $$\int{x}^{{z}} {dx}=\frac{\mathrm{1}}{{z}+\mathrm{1}}{x}^{{z}+\mathrm{1}} \\…
Question Number 172171 by Giantyusuf last updated on 23/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 172152 by Giantyusuf last updated on 23/Jun/22 Answered by Rasheed.Sindhi last updated on 23/Jun/22 $${h}:\:{first}\:{digit}\left({hundred}\right) \\ $$$${t}:\:{second}\:{digit}\left({ten}\right) \\ $$$${u}:\:{third}\:{digit}\left({unit}\right) \\ $$$${t}=\mathrm{4}{u} \\ $$$${h}={t}−\mathrm{3}=\mathrm{4}{u}−\mathrm{3}…
Question Number 172151 by Giantyusuf last updated on 23/Jun/22 $$\mathrm{3}^{{x}} =\mathrm{10}−{log}_{\mathrm{2}} {x} \\ $$$${find}\:{x} \\ $$ Answered by aleks041103 last updated on 23/Jun/22 $$\mathrm{3}^{{x}} \:{is}\:{monotounously}\:{increasing}.…
Question Number 106609 by DeepakMahato last updated on 06/Aug/20 $${Prove}\:{that} \\ $$$$\left(\mathrm{1}−{sin}^{\mathrm{2}} \theta\right){sec}^{\mathrm{2}} \theta=\mathrm{1} \\ $$ Commented by mohammad17 last updated on 06/Aug/20 $${when}:\mathrm{1}−{sin}^{\mathrm{2}} \theta={cos}^{\mathrm{2}}…
Question Number 106604 by mohammad17 last updated on 06/Aug/20 Commented by bemath last updated on 06/Aug/20 $$\mathrm{Q4}\left(\mathrm{5}\right)\:\underset{{x}\rightarrow\mathrm{1}/\mathrm{2}} {\mathrm{lim}}\:\frac{\mathrm{6}\sqrt{\mathrm{x}}−\mathrm{6}\sqrt{\mathrm{2x}−\mathrm{1}}}{\mathrm{x}−\mathrm{1}}\:=\:\frac{\frac{\mathrm{6}}{\:\sqrt{\mathrm{2}}}−\mathrm{0}}{−\frac{\mathrm{1}}{\mathrm{2}}} \\ $$$$=\:−\frac{\mathrm{12}}{\:\sqrt{\mathrm{2}}}\:=\:−\mathrm{6}\sqrt{\mathrm{2}}\:\:\:\:\:@\mathrm{bemath}@ \\ $$ Answered by Dwaipayan…
Question Number 106596 by mathdave last updated on 06/Aug/20 Answered by john santu last updated on 06/Aug/20 $$\:\:\:\:\:@\mathrm{JS}@ \\ $$$$\left(\mathrm{2}^{\mathrm{x}} −\mathrm{1}\right)\left(\mathrm{x}+\mathrm{3}\right)\left(\mathrm{x}−\mathrm{1}\right)=\mathrm{0} \\ $$$$\rightarrow\begin{cases}{\left.\mathrm{x}=−\mathrm{3};\:\mathrm{x}=\mathrm{1}\:;\:\mathrm{x}\:=\:\mathrm{0}\:\right\}\:}\end{cases} \\ $$$$…