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Question-171014

Question Number 171014 by Beginner last updated on 06/Jun/22 Answered by greougoury555 last updated on 06/Jun/22 $$\:=\:\int\left(\frac{\mathrm{1}}{\mathrm{7}}{e}^{\mathrm{7}{x}} +\mathrm{3}{e}^{−\mathrm{2}{x}} \right){dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{49}}{e}^{\mathrm{7}{x}} −\frac{\mathrm{3}}{\mathrm{2}}{e}^{−\mathrm{2}{x}} +{c}\: \\ $$…

what-numbers-is-that-of-which-the-third-Part-exceeds-the-fifth-part-by-4-

Question Number 39928 by equationeditor last updated on 13/Jul/18 $${what}\:{numbers}\:{is}\:{that}\:{of}\:{which}\:{the}\:{third}\:{Part}\:{exceeds}\:{the}\:{fifth}\:{part}\:{by}\:\mathrm{4} \\ $$ Commented by MrW3 last updated on 13/Jul/18 $${let}\:{x}\:{be}\:{the}\:{number} \\ $$$$\frac{{x}}{\mathrm{3}}−\frac{{x}}{\mathrm{5}}=\mathrm{4} \\ $$$$\frac{\mathrm{2}{x}}{\mathrm{15}}=\mathrm{4} \\…

App-Updates-Support-added-for-Hindi-Language-Select-Hindi-from-font-menu-Drawing-Added-option-to-draw-an-arc-at-a-point-connecting-two-lines-angle-and-explementary-angle-We-can-add

Question Number 105462 by Tinku Tara last updated on 29/Jul/20 $$\mathrm{App}\:\mathrm{Updates}: \\ $$$$\bullet\:\mathrm{Support}\:\mathrm{added}\:\mathrm{for}\:\mathrm{Hindi}\:\mathrm{Language} \\ $$$$\:\:\:\mathrm{Select}\:\mathrm{Hindi}\:\mathrm{from}\:\mathrm{font}\:\mathrm{menu}. \\ $$$$\bullet\:\mathrm{Drawing}:\:\mathrm{Added}\:\mathrm{option}\:\mathrm{to}\:\mathrm{draw} \\ $$$$\:\:\:\:\mathrm{an}\:\mathrm{arc}\:\mathrm{at}\:\mathrm{a}\:\mathrm{point}\:\mathrm{connecting}\:\mathrm{two} \\ $$$$\:\:\:\:\mathrm{lines}\:\left(\mathrm{angle}\:\mathrm{and}\:\mathrm{explementary}\:\mathrm{angle}\right) \\ $$$$\mathrm{We}\:\mathrm{can}\:\mathrm{add}\:\mathrm{more}\:\mathrm{languages}.\: \\ $$$$\mathrm{More}\:\mathrm{languages}:\:\mathrm{If}\:\mathrm{u}\:\mathrm{provide}\:\mathrm{us}…

Question-170977

Question Number 170977 by 0731619 last updated on 05/Jun/22 Commented by mr W last updated on 05/Jun/22 $$\mathrm{4}=\sqrt{\mathrm{16}} \\ $$$$=\sqrt{\mathrm{13}+\mathrm{3}} \\ $$$$=\sqrt{\mathrm{13}+\sqrt{\mathrm{9}}} \\ $$$$=\sqrt{\mathrm{13}+\sqrt{\mathrm{5}+\mathrm{4}}} \\…

k-1-k-n-1-k-2-any-help-pleaze-

Question Number 105431 by bachamohamed last updated on 28/Jul/20 $$\:\underset{\boldsymbol{{k}}=\mathrm{1}} {\overset{\boldsymbol{{k}}=\boldsymbol{{n}}} {\sum}}\left(\frac{\mathrm{1}}{\boldsymbol{{k}}}\right)^{\mathrm{2}} =? \\ $$$$\boldsymbol{{any}}\:\boldsymbol{{help}}\:\boldsymbol{{pleaze}} \\ $$ Commented by Dwaipayan Shikari last updated on 28/Jul/20…