Question Number 170468 by MathsFan last updated on 24/May/22 $$\:\mathrm{G}{iven}\:{that}\:{log}_{\mathrm{4}} \left({y}−\mathrm{1}\right)+{log}_{\mathrm{4}} \left(\frac{{x}}{{y}}\right)={m} \\ $$$$\:{and}\:{log}_{\mathrm{2}} \left({y}+\mathrm{1}\right)−{log}_{\mathrm{2}} {x}={m}−\mathrm{1}, \\ $$$$\:{show}\:{that}\:{y}^{\mathrm{2}} =\mathrm{1}−\mathrm{8}^{{m}} \\ $$ Answered by cortano1 last…
Question Number 170474 by mokys last updated on 24/May/22 $$\int\:\sqrt{\mathrm{1}+{n}^{\mathrm{2}} {x}^{\mathrm{2}{n}−\mathrm{2}} }\:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 170461 by khadee last updated on 24/May/22 $${find}\:{tbe}\:{domain}\:{and}\:{range}\:{of}\:{the}\:{following}\:{functions} \\ $$$${y}=\mathrm{4}{x}/{x}^{\mathrm{2}} −\mathrm{4} \\ $$ Commented by mokys last updated on 24/May/22 $$ \\ $$$${x}^{\mathrm{2}}…
Question Number 170463 by mokys last updated on 24/May/22 Commented by mokys last updated on 24/May/22 $${true}\:{or}\:{false} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 170459 by MathsFan last updated on 24/May/22 $${Factorize}\:\mathrm{10}{x}^{\mathrm{2}} {y}^{\mathrm{2}} +\mathrm{13}{x}^{\mathrm{2}} {y}−\mathrm{3}{x}^{\mathrm{2}} {y}−\mathrm{3}{x}^{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 170458 by MathsFan last updated on 24/May/22 $${If}\:{the}\:{line}\:{y}={mx}+{c}\:{is}\:{a}\:{tangent}\:{of} \\ $$$${a}\:{circle}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={r}^{\mathrm{2}} .\:{Show}\:{that},\: \\ $$$$\:{c}^{\mathrm{2}} ={r}^{\mathrm{2}} \left(\mathrm{1}+{m}^{\mathrm{2}} \right) \\ $$ Answered by greougoury555…
Question Number 104905 by mohammad17 last updated on 24/Jul/20 Answered by OlafThorendsen last updated on 24/Jul/20 $${x}^{\mathrm{4}} +{x}^{\mathrm{3}} +{x}^{\mathrm{2}} +{x}+\mathrm{1}\:=\:\mathrm{0} \\ $$$$\frac{\mathrm{1}−{x}^{\mathrm{5}} }{\mathrm{1}−{x}}\:=\:\mathrm{0} \\ $$$${x}^{\mathrm{5}}…
Question Number 170435 by MathsFan last updated on 23/May/22 $$\boldsymbol{{A}}\:\boldsymbol{{line}}\:\boldsymbol{{is}}\:\boldsymbol{{formed}}\:\boldsymbol{{by}}\:\boldsymbol{{joining}}\:\boldsymbol{{the}} \\ $$$$\boldsymbol{{points}}\:\boldsymbol{{A}}\left(\mathrm{7},\mathrm{0}\right)\:\boldsymbol{{and}}\:\boldsymbol{{B}}\left(\mathrm{0},\mathrm{2}\right).\:\boldsymbol{{Obtain}} \\ $$$$\boldsymbol{{the}}\:\boldsymbol{{equation}}\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{straight}}\:\boldsymbol{{line}} \\ $$$$\boldsymbol{{joining}}\:\boldsymbol{{AC}}\:\boldsymbol{{such}}\:\boldsymbol{{that}}\:\boldsymbol{{the}}\:\boldsymbol{{x}}−\boldsymbol{{axis}} \\ $$$$\boldsymbol{{bisects}}\:\boldsymbol{{the}}\:\boldsymbol{{angle}}\:\boldsymbol{{BAC}}. \\ $$ Answered by MikeH last updated…
Question Number 170426 by daus last updated on 23/May/22 Answered by Rasheed.Sindhi last updated on 23/May/22 $$\frac{\mathrm{1}}{\mathrm{3}.\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{5}.\mathrm{7}}+\frac{\mathrm{1}}{\mathrm{7}.\mathrm{9}}+… \\ $$$$=\underset{{n}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{\left(\mathrm{2}{k}+\mathrm{1}\right)\left(\mathrm{2}{k}+\mathrm{3}\right)} \\ $$$$\:\:\:\:\:\:\:\frac{\mathrm{1}}{\left(\mathrm{2}{k}+\mathrm{1}\right)\left(\mathrm{2}{k}+\mathrm{3}\right)}=\frac{{A}}{\mathrm{2}{k}+\mathrm{1}}+\frac{{B}}{\mathrm{2}{k}+\mathrm{3}} \\ $$$$\:\:\:\:\:\:\:{A}\left(\mathrm{2}{k}+\mathrm{3}\right)+{B}\left(\mathrm{2}{k}+\mathrm{1}\right)=\mathrm{1}…
Question Number 104876 by mathocean1 last updated on 24/Jul/20 $${A}\:{ballot}\:{box}\:{contains}\:\mathrm{7}\:{balls}\left(\mathrm{3}\:{are}\:\right. \\ $$$$\left.{black}\right).\:{we}\:{draw}\:{successively}\:{and} \\ $$$${reputing}\left({inside}\right)\:\mathrm{5}\:{balls}. \\ $$$${What}\:{is}\:{the}\:{number}\:{of}\:{possibilities}\: \\ $$$${to}\:{have}\:{one}\:{black}\:{ball}? \\ $$ Terms of Service Privacy Policy…