Question Number 104775 by MAB last updated on 23/Jul/20 $${let}\:{P}_{{n}} \:{an}\:{n}-{polynomial}. \\ $$$${let}\:{a}_{\mathrm{1}} ,…,{a}_{{n}} \:{its}\:{simple}\:{roots}\: \\ $$$${let}\:{m}_{{k}} \:{the}\:{slope}\:{of}\:{the}\:{tangent}\:{to}\:{P}_{{n}} \:{at} \\ $$$${the}\:{point}\:\left({a}_{{k}} ,\mathrm{0}\right) \\ $$$${prove}\:{that} \\…
Question Number 170305 by MathsFan last updated on 20/May/22 $$\boldsymbol{\mathrm{A}}\:\boldsymbol{\mathrm{number}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{two}}\:\boldsymbol{\mathrm{digits}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{equal}}\:\boldsymbol{\mathrm{to}} \\ $$$$\boldsymbol{\mathrm{four}}\:\boldsymbol{\mathrm{times}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{sum}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{its}}\:\boldsymbol{\mathrm{digits}}.\:\boldsymbol{\mathrm{The}} \\ $$$$\boldsymbol{\mathrm{number}}\:\boldsymbol{\mathrm{formed}}\:\boldsymbol{\mathrm{by}}\:\boldsymbol{\mathrm{reversing}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{order}} \\ $$$$\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{digit}}\:\boldsymbol{\mathrm{is}}\:\mathrm{27}\:\boldsymbol{\mathrm{greater}}\:\boldsymbol{\mathrm{than}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{given}} \\ $$$$\boldsymbol{\mathrm{number}}.\:\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{number}} \\ $$ Answered by Rasheed.Sindhi last updated…
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Question Number 104760 by mohammad17 last updated on 23/Jul/20 Answered by Dwaipayan Shikari last updated on 23/Jul/20 $${a}_{{n}} ={a}_{\mathrm{1}} +\left({n}−\mathrm{1}\right){d}=\mathrm{5}+\left({n}−\mathrm{1}\right)\mathrm{25} \\ $$$$\mathrm{130}=\mathrm{5}+\left({n}−\mathrm{1}\right)\mathrm{25} \\ $$$${n}=\mathrm{6} \\…
Question Number 170298 by mokys last updated on 19/May/22 $$\int\:\frac{\mathrm{1}}{\:\sqrt[{\mathrm{4}}]{\mathrm{1}+{x}^{\mathrm{4}} }}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 104759 by mohammad17 last updated on 23/Jul/20 Answered by bobhans last updated on 24/Jul/20 $${vol}\:=\:\frac{\mathrm{1}}{\mathrm{6}}\left(\mid\:\:{det}\begin{pmatrix}{\mathrm{1}\:\:\:\:\:−\mathrm{1}\:\:\:\:\:\:\:\mathrm{4}}\\{\mathrm{2}\:\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\mathrm{1}}\\{\mathrm{0}\:\:\:\:\:\:\:\:\:\mathrm{2}\:\:\:\:\:\:\:\:\:\mathrm{3}}\end{pmatrix}\:\mid\right) \\ $$$$=\:\frac{\mathrm{1}}{\mathrm{6}}\mid\mathrm{1}.\left(−\mathrm{2}\right)−\left(−\mathrm{1}\right)\left(\mathrm{6}\right)+\mathrm{4}\left(\mathrm{4}\right)\:\mid\: \\ $$$$=\:\frac{\mathrm{1}}{\mathrm{6}}\left(−\mathrm{2}+\mathrm{6}+\mathrm{16}\right)\:=\:\frac{\mathrm{10}}{\mathrm{3}}\:\blacksquare\: \\ $$ Terms of…
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Question Number 104752 by mohammad17 last updated on 23/Jul/20 Commented by qwertyu last updated on 23/Jul/20 $${S}_{{n}} =\frac{\mathrm{51}+\mathrm{21}}{\mathrm{2}}\:\centerdot\:\mathrm{31}\:=\:\mathrm{1116} \\ $$ Answered by Dwaipayan Shikari last…