Question Number 104461 by Study last updated on 21/Jul/20 Answered by OlafThorendsen last updated on 21/Jul/20 $$\mathrm{C}_{\mathrm{4}} \mathrm{H}_{\mathrm{10}} +\mathrm{Mg}\left(\mathrm{OH}\right)\mathrm{Cl} \\ $$ Terms of Service Privacy…
Question Number 104460 by Anindita last updated on 21/Jul/20 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{reading}\:\mathrm{books}\:\mathrm{is}\:\mathrm{1248} \\ $$$$\mathrm{in}\:\mathrm{a}\:\mathrm{library}.\:\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{story} \\ $$$$\mathrm{books}\:\mathrm{is}\:\mathrm{936}.\:\mathrm{The}\:\mathrm{librarians}\:\mathrm{bought} \\ $$$$\mathrm{more}\:\mathrm{reading}\:\mathrm{books}.\:\mathrm{Now}\:\frac{\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{Reading}\:\mathrm{books}}{\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{story}\:\mathrm{books}\:} \\ $$$$=\:\frac{\mathrm{11}}{\mathrm{5}}.\:\mathrm{How}\:\mathrm{many}\:\mathrm{reading}\:\mathrm{books}\:\mathrm{were} \\ $$$$\mathrm{bought}\:? \\ $$ Answered by Ritu…
Question Number 104452 by Anindita last updated on 21/Jul/20 $$\mathrm{If}\:\mathrm{A}:\mathrm{B}\:=\:\mathrm{3}:\mathrm{4},\:\mathrm{B}:\mathrm{C}\:=\:\mathrm{6}:\mathrm{7}\:\mathrm{then} \\ $$$$\mathrm{A}:\mathrm{B}:\mathrm{C}\:=\:?\:\mathrm{A}:\mathrm{C}\:=\:?\: \\ $$ Answered by bemath last updated on 21/Jul/20 $${A}\::\:{B}\::\:{C}\:=\:\mathrm{9}\::\:\mathrm{12}\::\:\mathrm{14} \\ $$ Answered…
Question Number 169986 by weltr last updated on 13/May/22 $$\left({x}\:+\:\mathrm{2}\right)^{\mathrm{2}{x}\:−\:\mathrm{3}} \:>\:\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 169973 by Best1 last updated on 13/May/22 Answered by alephzero last updated on 13/May/22 $${P}_{\mathrm{a}} \:=\:{P}_{\mathrm{rectangle}} −{a}+{P}_{\mathrm{semicircle}} \:= \\ $$$$=\:\mathrm{2}\left({a}+{b}\right)−{a}+\frac{\pi{d}}{\mathrm{2}}\:= \\ $$$$=\:\mathrm{2}\left(\mathrm{1}.\mathrm{6}+\mathrm{2}.\mathrm{8}\right)−\mathrm{1}.\mathrm{6}+\frac{\mathrm{1}.\mathrm{6}\pi}{\mathrm{2}} \\…
Question Number 169974 by Best1 last updated on 13/May/22 Commented by Best1 last updated on 13/May/22 $${please}\:{help}\:{me} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 169969 by Beginner last updated on 13/May/22 Answered by mr W last updated on 13/May/22 Commented by ajfour last updated on 13/May/22 $${u}=\sqrt{\mathrm{2}{gh}}…
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Question Number 169944 by mokys last updated on 13/May/22 Commented by mokys last updated on 13/May/22 $$?????????? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 169942 by Best1 last updated on 13/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com