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Question-168119

Question Number 168119 by Beginner last updated on 03/Apr/22 Answered by mr W last updated on 04/Apr/22 $${l}={length}\:{of}\:{rod}=\mathrm{24}\:{cm} \\ $$$${I}=\frac{{Ml}^{\mathrm{2}} }{\mathrm{12}}+{M}\left(\frac{{l}}{\mathrm{2}}−{x}\right)^{\mathrm{2}} \\ $$$${I}\frac{{d}^{\mathrm{2}} \theta}{{dt}^{\mathrm{2}} }=−{Mg}\left(\frac{{l}}{\mathrm{2}}−{x}\right)\mathrm{sin}\:\theta\:\approx−{Mg}\left(\frac{{l}}{\mathrm{2}}−{x}\right)\theta…

let-A-1-A-2-A-n-a-regular-polygon-of-n-sides-with-length-l-each-let-X-a-point-such-that-A-1-X-x-l-where-0-lt-x-lt-1-as-shown-what-is-the-length-of-the-shortest-path-begins-fromX-touching-all-s

Question Number 102576 by MAB last updated on 10/Jul/20 $${let}\:{A}_{\mathrm{1}} {A}_{\mathrm{2}} …{A}_{{n}} \:\:{a}\:{regular}\:{polygon}\:{of}\:{n}\:{sides} \\ $$$${with}\:{length}\:{l}\:{each},\:{let}\:{X}\:{a}\:{point}\:{such} \\ $$$${that}\:{A}_{\mathrm{1}} {X}={x}\centerdot{l}\:{where}\:\mathrm{0}<{x}<\mathrm{1}\:\left({as}\:{shown}\right) \\ $$$${what}\:{is}\:{the}\:{length}\:{of}\:{the}\:{shortest}\:{path} \\ $$$${begins}\:{fromX}\:{touching}\:{all}\:{sides}\:{once} \\ $$$${and}\:{ends}\:{at}\:{X} \\…

App-updates-Version-2-094-has-been-uploaded-to-playstore-Enhancements-paste-plain-text-Auto-wrapping-of-lines-settings-New-construct-as-shown-below-strike-thru-underline-under

Question Number 102572 by Tinku Tara last updated on 10/Jul/20 $$\mathrm{App}\:\mathrm{updates}:\: \\ $$$$\mathrm{Version}\:\mathrm{2}.\mathrm{094}\:\mathrm{has}\:\mathrm{been}\:\mathrm{uploaded} \\ $$$$\mathrm{to}\:\mathrm{playstore}: \\ $$$$\mathrm{Enhancements}: \\ $$$$\bullet\:\mathrm{paste}\:\mathrm{plain}\:\mathrm{text} \\ $$$$\bullet\:\mathrm{Auto}\:\mathrm{wrapping}\:\mathrm{of}\:\mathrm{lines}\:\left(\mathrm{settings}\right) \\ $$$$\bullet\:\mathrm{New}\:\mathrm{construct}\:\mathrm{as}\:\mathrm{shown}\:\mathrm{below}. \\ $$$$\:\:\:\:\mathrm{strike}\:\mathrm{thru}…

Question-168093

Question Number 168093 by leicianocosta last updated on 02/Apr/22 Answered by nurtani last updated on 03/Apr/22 $${sin}\:\mathrm{60}°\:=\:\frac{\mathrm{2}}{{d}} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}}\:=\:\frac{\mathrm{2}}{{d}}\: \\ $$$$\sqrt{\mathrm{3}}\:{d}\:=\:\mathrm{4}\Rightarrow\:{d}\:=\:\frac{\mathrm{4}}{\:\sqrt{\mathrm{3}}}\:\centerdot\:\frac{\sqrt{\mathrm{3}}}{\:\sqrt{\mathrm{3}}}\:=\:\frac{\mathrm{4}}{\mathrm{3}}\sqrt{\mathrm{3}}\:{m}\:\left({b}\right) \\ $$ Terms of…