Question Number 36103 by mondodotto@gmail.com last updated on 28/May/18 $$\boldsymbol{\mathrm{convert}}\:\mathrm{0}.\mathrm{26999999}…\boldsymbol{\mathrm{into}}\:\boldsymbol{\mathrm{fraction}}\: \\ $$$$\frac{\boldsymbol{\mathrm{a}}}{\boldsymbol{\mathrm{b}}}\:\boldsymbol{\mathrm{where}}\:\boldsymbol{\mathrm{a}}\neq\mathrm{0} \\ $$ Answered by MJS last updated on 28/May/18 $$=\frac{\mathrm{26}}{\mathrm{100}}+\frac{\mathrm{9}}{\mathrm{900}}=\frac{\mathrm{27}}{\mathrm{100}} \\ $$ Commented…
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Question Number 167145 by mkam last updated on 07/Mar/22 $$\int\:\frac{{dx}}{{x}^{\mathrm{2}} −\mathrm{3}\sqrt{{x}}+\mathrm{10}} \\ $$ Commented by MJS_new last updated on 07/Mar/22 $$\mathrm{1}^{\mathrm{st}} \:\mathrm{step}\:{t}=\sqrt{{x}}\:\rightarrow\:{dx}=\mathrm{2}{tdt}\:\Rightarrow \\ $$$$\mathrm{2}\int\frac{{t}}{{t}^{\mathrm{4}} −\mathrm{3}{t}+\mathrm{10}}{dt}…
Question Number 167144 by mathocean1 last updated on 07/Mar/22 $${Calculate}\: \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{{sin}\left(\mathrm{1}\right)}{{cos}\left({k}\right){cos}\left({k}−\mathrm{1}\right)} \\ $$ Answered by mathsmine last updated on 07/Mar/22 $${sin}\left(\mathrm{1}\right)={sin}\left({k}−\left(\boldsymbol{{k}}−\mathrm{1}\right)\right)=\boldsymbol{{sin}}\left(\boldsymbol{{k}}\right)\boldsymbol{{cos}}\left(\boldsymbol{{k}}−\mathrm{1}\right)−{sin}\left({k}−\mathrm{1}\right){cos}\left({k}\right) \\…
Question Number 167126 by MathsFan last updated on 07/Mar/22 $$ \\ $$Assuming one of the WiFi towers of a building is 20km high, and has…
Question Number 167120 by DAVONG last updated on 07/Mar/22 Answered by TheSupreme last updated on 07/Mar/22 $$\frac{{sin}\left(\frac{\pi}{\mathrm{2}}\left(\mathrm{1}−{cos}\left({x}\right)\right)\right)}{\mathrm{1}−{cos}\left({x}\right)}=\frac{\pi}{\mathrm{2}}\frac{\mathrm{1}−{cos}\left({x}\right)}{\mathrm{1}−{cos}\left({x}\right)}=\frac{\pi}{\mathrm{2}} \\ $$ Answered by Mathspace last updated on…
Question Number 36024 by bshahid010@gmail.com last updated on 27/May/18 Commented by abdo mathsup 649 cc last updated on 27/May/18 $${let}\:{use}\:{the}\:{changement}\:\:{x}\:=\mathrm{1}+{t}\:{so} \\ $$$$\frac{{m}}{{x}^{{m}} \:−\mathrm{1}}\:−\frac{{p}}{{x}^{{p}} \:−\mathrm{1}}\:=\frac{{m}}{\left(\mathrm{1}+{t}\right)^{{m}} \:−\mathrm{1}}\:−\:\frac{{p}}{\left(\mathrm{1}+{t}\right)^{{p}}…
Question Number 101551 by mhmd last updated on 03/Jul/20 Answered by bobhans last updated on 03/Jul/20 $$\left.\left(\mathrm{Q2}\right)\:\mathrm{The}\:\mathrm{area}\:=\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\underset{\mathrm{0}} {\overset{{x}} {\int}}\:{dy}\:{dx}\:=\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\left({y}\right)\right]_{\mathrm{0}} ^{{x}} \:\:{dx}…
Question Number 101546 by mhmd last updated on 03/Jul/20 Commented by mhmd last updated on 03/Jul/20 $${help}\:{me}\:{sir} \\ $$ Answered by bobhans last updated on…