Question Number 212600 by MrGaster last updated on 18/Oct/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{certificate}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{n}}{\mathrm{1}+{n}^{\mathrm{2}} {x}^{\mathrm{2}} }{e}^{{x}^{\mathrm{3}} } {dx}=\frac{\pi}{\mathrm{2}}. \\ $$ Answered by…
Question Number 212595 by MrGaster last updated on 18/Oct/24 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{1}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{2}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{2}}+\frac{\mathrm{3}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{3}}+\ldots+\frac{{n}^{\mathrm{2}} }{{n}^{\mathrm{2}} +{n}}−\frac{{n}}{\mathrm{3}}\right)=? \\ $$ Answered by Berbere last…
Question Number 212584 by MrGaster last updated on 18/Oct/24 Commented by mr W last updated on 18/Oct/24 $${it}\:{seems}\:{that}\:{you}\:{are}\:{using}\:{machine} \\ $$$${translation}\:{for}\:{your}\:{posts}.\:{can}\:{you} \\ $$$${please}\:{recheck}\:{the}\:{translation} \\ $$$${and}\:{fix}\:{the}\:{mistakes}\:{in}\:{them}\:{before} \\…
Question Number 212556 by MrGaster last updated on 17/Oct/24 $$\mathrm{Q}:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{most}\:\mathrm{disgusting}\:\mathrm{mathm} \\ $$$$\mathrm{proble}\:\mathrm{you}\:\mathrm{have}\:\mathrm{ever}\:\mathrm{done}.? \\ $$ Commented by MATHEMATICSAM last updated on 17/Oct/24 $$\mathrm{1}+\mathrm{1}=? \\ $$ Answered…
Question Number 212554 by MrGaster last updated on 17/Oct/24 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}{x}^{\mathrm{2}} \left[{e}^{\left(\mathrm{1}+\frac{\mathrm{1}}{{x}}\right)^{{x}} } −\left(\mathrm{1}+\frac{\mathrm{1}}{{x}}\right)^{{ex}} \right]=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212545 by MrGaster last updated on 17/Oct/24 $$\underset{{n}\rightarrow\infty} {\mathrm{llim}}\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\sqrt{\mathrm{1}+\frac{{i}}{{n}^{\mathrm{3}} }}−\mathrm{1}\right)=? \\ $$ Answered by lepuissantcedricjunior last updated on 17/Oct/24 $$\underset{\boldsymbol{{n}}\rightarrow+\infty} {\mathrm{lim}}\underset{\boldsymbol{{i}}=\mathrm{1}}…
Question Number 212579 by MrGaster last updated on 18/Oct/24 $$\mathrm{Have}\:\mathrm{you}\:\mathrm{ever}\:\mathrm{wondered}\:\mathrm{why}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{ofd} \\ $$$$\mathrm{igits}\:\mathrm{in}\:\mathrm{decimal}\:\mathrm{system}\:\mathrm{is}\:\mathrm{a}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{3a} \\ $$$$\mathrm{nd}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{digits}\:\mathrm{in}\:\mathrm{decimal}\:\mathrm{system}\: \\ $$$$\mathrm{isa}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{9}\:\mathrm{Prove}\:\mathrm{the}\:\mathrm{abovei} \\ $$$$\mathrm{propertes}. \\ $$ Terms of Service Privacy Policy…
Question Number 212513 by MrGaster last updated on 16/Oct/24 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{certificate}: \\ $$$$\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}{n}} −\mathrm{1} \\ $$$$\mathrm{Can}\:\mathrm{always}\:\mathrm{be}\:{x}+\mathrm{1}\:\mathrm{be}\:\mathrm{divisible}\:\:\:\:\:\:\:\:\: \\ $$ Answered by A5T last updated on 16/Oct/24 $${x}\equiv−\mathrm{1}\left({mod}\:{x}+\mathrm{1}\right)\Rightarrow{x}^{\mathrm{2}{n}}…
Question Number 212497 by MrGaster last updated on 15/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212492 by MrGaster last updated on 15/Oct/24 $$\mathrm{Given}\:\mathrm{that}\:{x}\:\in\:\mathbb{R}\left(\right. \\ $$$$\:\left(\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{real}\:\mathrm{numbers}\right)\mathrm{d} \\ $$$$\mathrm{an}\:{n}\:\in\:\mathbb{N}^{\ast} \\ $$$$\left(\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{positive}\:\mathrm{naturalu}\right. \\ $$$$\left.\mathrm{nmbers}\right)\:\mathrm{prove}\:\mathrm{that}\:: \\ $$$$\mid\mathrm{cos}\:{x}\mid+\mid\mathrm{cos}\:\mathrm{2}{x}\mid+\mid\mathrm{cos}\:\mathrm{3}{x}\mid+\ldots+\mid\mathrm{cos}\left({n}+\mathrm{1}\right){x}\mid\geq\frac{{n}}{\mathrm{2}} \\ $$ Terms of Service…