Question Number 153716 by Rankut last updated on 09/Sep/21 Commented by Rankut last updated on 09/Sep/21 $${help}\:\:{please} \\ $$ Answered by mr W last updated…
Question Number 153696 by SANOGO last updated on 09/Sep/21 Answered by puissant last updated on 09/Sep/21 $${x}_{{n}} =\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{{n}^{\mathrm{2}} +{k}} \\ $$$${Calcul}\:{des}\:\mathrm{5}\:{premiers}\:{termes}.. \\ $$$$\rightarrow\:{x}_{\mathrm{1}}…
Question Number 153698 by mathocean1 last updated on 09/Sep/21 $${solve}\:{in}\:\mathbb{R} \\ $$$$\begin{cases}{{x}^{\mathrm{3}} −{y}^{\mathrm{3}} =\mathrm{19}}\\{{xy}=\mathrm{6}}\end{cases} \\ $$ Answered by amin96 last updated on 09/Sep/21 $$\left({x}−{y}\right)\left({x}^{\mathrm{2}} +{xy}+{y}^{\mathrm{2}}…
Question Number 153676 by SANOGO last updated on 09/Sep/21 Answered by som(math1967) last updated on 09/Sep/21 $$\mathrm{1}.\:\boldsymbol{{a}}>\mathrm{0},\boldsymbol{{b}}>\mathrm{0} \\ $$$$\:\left(\boldsymbol{{a}}−\boldsymbol{{b}}\right)^{\mathrm{2}} \geqslant\mathrm{0}\:\:\:\left[\boldsymbol{{if}}\:\boldsymbol{{a}}=\boldsymbol{{b}}\:\boldsymbol{{then}}\left(\boldsymbol{{a}}−\boldsymbol{{b}}\right)=\mathrm{0}\right] \\ $$$$\Rightarrow\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)^{\mathrm{2}} −\mathrm{4}\boldsymbol{{ab}}\geqslant\mathrm{0} \\ $$$$\Rightarrow\:\left(\frac{\boldsymbol{{a}}+\boldsymbol{{b}}}{\mathrm{2}}\right)^{\mathrm{2}}…
Question Number 153671 by RB95 last updated on 09/Sep/21 Commented by RB95 last updated on 09/Sep/21 $${Salut} \\ $$$${Quelqu}'{un}\:{peut}\:{m}'{aider}\:{svp}? \\ $$ Terms of Service Privacy…
Question Number 22598 by Sahib singh last updated on 20/Oct/17 $${Wow}\:{guys}.\:{You}\:{people}\:{are} \\ $$$${amazing}.{Its}\:{my}\:{pleasure}\:{to} \\ $$$$\left.{be}\:{a}\:{part}\:{of}\:{this}\:{forum}.\:\::\right) \\ $$$$\: \\ $$ Commented by math solver last updated…
Question Number 153651 by Skabetix last updated on 08/Sep/21 Answered by Skabetix last updated on 08/Sep/21 $${bonjour}\:{trouver}\:{la}\:{valeur}\:{logique}\:{sans}\:{utiliser}\:{la}\:{table}\:{de}\:{verite} \\ $$$$ \\ $$ Answered by Jonathanwaweh last…
Question Number 22567 by mondodotto@gmail.com last updated on 20/Oct/17 Answered by Rasheed.Sindhi last updated on 20/Oct/17 $$\mathrm{840}=\mathrm{2}^{\mathrm{3}} .\mathrm{3}.\mathrm{5}.\mathrm{7} \\ $$$$\therefore\:\mathrm{The}\:\mathrm{numbers}\:\left(\mathrm{of}\:\mathrm{which}\:\mathrm{840}\:\mathrm{is}\:\mathrm{lcm}\right) \\ $$$$\mathrm{may}\:\mathrm{have}\:\mathrm{factors}\:\mathrm{2},\mathrm{3},\mathrm{5},\mathrm{7}\:\mathrm{all}\:\mathrm{or}\:\mathrm{some} \\ $$$$\mathrm{of}\:\mathrm{them}. \\…
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Question Number 22561 by Bruce Lee last updated on 20/Oct/17 $$\boldsymbol{\mathrm{Solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{all}}\:\boldsymbol{\mathrm{integer}}\:\boldsymbol{{x}},\boldsymbol{{y}}\:\in\boldsymbol{{Z}} \\ $$$$\:\:\:\:\:\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} =\mathrm{19} \\ $$ Answered by $@ty@m last updated on 20/Oct/17 $${Case}−\mathrm{1}.\:{Let}\:{x}=\mathrm{0}…