Question Number 75902 by Mr. K last updated on 20/Dec/19 Commented by Mr. K last updated on 20/Dec/19 $${find}\:{the}\:{area}\:{of}\:{the}\:{square} \\ $$ Answered by mr W…
Question Number 141431 by mohammad17 last updated on 18/May/21 $$\mathrm{2}\int_{\mathrm{0}} ^{\:\mathrm{1}} \int_{\mathrm{0}} ^{\:\mathrm{2}} \left({x}+\mathrm{2}{y}\right)^{\mathrm{8}} \:{dxdy} \\ $$ Answered by mathmax by abdo last updated on…
Question Number 141423 by naka3546 last updated on 18/May/21 $$\mathrm{tan}\:\left({x}+{y}\right)=\:\frac{\mathrm{12}}{\mathrm{5}} \\ $$$$\mathrm{sin}\:\left({x}−{y}\right)\:=\:\frac{\mathrm{3}}{\mathrm{5}} \\ $$$${x}+{y}\:,\:{x}−{y}\:\:{are}\:\:{acute}\:\:{angles}\:. \\ $$$$\mathrm{tan}\:{x}\:\mathrm{tan}\:{y}\:=\:\:? \\ $$ Answered by mr W last updated on…
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Question Number 75851 by aliesam last updated on 18/Dec/19 Answered by MJS last updated on 18/Dec/19 $$\mathrm{10}\frac{\mathrm{8}+\mathrm{6i}}{\mathrm{3}−\mathrm{i}}=\mathrm{18}+\mathrm{26i}=\left(\mathrm{3}+\mathrm{i}\right)^{\mathrm{3}} \\ $$$$\left({x}+{y}\mathrm{i}\right)^{\mathrm{3}} ={x}^{\mathrm{3}} −\mathrm{3}{xy}^{\mathrm{2}} +\left(\mathrm{3}{x}^{\mathrm{2}} {y}−{y}^{\mathrm{3}} \right)\mathrm{i} \\…
Question Number 75826 by liki last updated on 18/Dec/19 Commented by liki last updated on 18/Dec/19 $$…{plz}\:{help}\:{me}\:{part}\:\left({c}\right). \\ $$ Answered by mr W last updated…
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Question Number 75818 by naka3546 last updated on 18/Dec/19 $${Given}\:\:{the}\:\:{increasing}\:\:{sequence}\:: \\ $$$$\mathrm{1},\:\mathrm{4},\:\mathrm{8},\:\mathrm{13},\:… \\ $$$${a}.\:{Find}\:\:{U}_{\mathrm{2019}} \\ $$$${b}.\:{Find}\:\:{S}_{\mathrm{2019}} \\ $$$${U}_{{n}} \:\:{is}\:\:{nth}−{term}\:\:{of}\:\:{the}\:\:{sequence} \\ $$$${S}_{{n}} \:\:{is}\:\:{sum}\:\:{of}\:\:{n}\:−\:{term}\:\:{of}\:\:{the}\:\:{sequence} \\ $$$${Arithmetic}\:\:{Sequence}\:\:{Degree}\:\:{Two} \\…
Question Number 141340 by physicstutes last updated on 17/May/21 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{function}\:{f}\:\mathrm{defined}\:\mathrm{by} \\ $$$$\:{f}\left({x}\right)\:=\:\begin{cases}{\frac{\mathrm{2}{e}^{{x}} }{{e}^{{x}} −\mathrm{1}},{x}\neq\:\mathrm{0}}\\{\mathrm{0},\:{x}\:=\:\mathrm{0}}\end{cases} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{study}\:\mathrm{the}\:\mathrm{differentiability}\:\mathrm{of}\:{f}\:\mathrm{at}\:{x}\:=\:\mathrm{0}. \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{point}\:\left(\mathrm{0},\mathrm{1}\right)\:\mathrm{is}\:\mathrm{the}\:\mathrm{centre}\:\mathrm{of}\:\mathrm{symetry}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{curve}\:\mathrm{of}\:{f}. \\ $$ Terms of Service…