Question Number 141323 by mathocean1 last updated on 17/May/21 Answered by mr W last updated on 17/May/21 Commented by mr W last updated on 17/May/21…
Question Number 10250 by jaikar last updated on 31/Jan/17 Commented by jaikar last updated on 31/Jan/17 $${please}\:{Q}\:{no}.\:\mathrm{10} \\ $$$$ \\ $$ Answered by ridwan balatif…
Question Number 141311 by SOMEDAVONG last updated on 17/May/21 $$\mathrm{Show}\:\mathrm{that}\:,\mathrm{C}_{\mathrm{n}} ^{\mathrm{k}} +\mathrm{C}_{\mathrm{n}} ^{\mathrm{k}−\mathrm{1}} =\mathrm{C}_{\mathrm{n}+\mathrm{1}} ^{\mathrm{n}−\mathrm{k}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 75748 by naka3546 last updated on 16/Dec/19 $$\frac{\mathrm{4}\:\mathrm{sin}\:\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right)\:+\:\mathrm{sec}\:\left(\frac{\pi}{\mathrm{14}}\right)}{\mathrm{cot}\:\left(\frac{\pi}{\mathrm{7}}\right)}\:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 75701 by vishalbhardwaj last updated on 15/Dec/19 $$\mathrm{please}\:\mathrm{tell}\:\mathrm{me}\::\left(\infty\right)^{\mathrm{0}\:} \mathrm{is}\:\mathrm{not}\:\mathrm{defined}\:? \\ $$ Commented by malwaan last updated on 16/Dec/19 $${yes} \\ $$$${but}\:\mathrm{0}^{\infty} \:=\:\mathrm{0} \\…
Question Number 141197 by paulpadas last updated on 16/May/21 $${Write}\:{the}\:{next}\:{three}\:{terms}\:\mathrm{1},\:\frac{\mathrm{3}}{\mathrm{7}},\:\frac{\mathrm{8}}{\mathrm{3}},\:\_\_\_,\:\_\_\_,\:\_\_\_,\:… \\ $$ Answered by MJS_new last updated on 16/May/21 $$\mathrm{zillions}\:\mathrm{of}\:\mathrm{possible}\:\mathrm{answers}. \\ $$$$\mathrm{I}\:\mathrm{like}\:\mathrm{this}\:\mathrm{one} \\ $$$${a}_{{n}} =−\frac{\mathrm{3}}{\mathrm{10}}−\frac{\mathrm{38}{n}−\mathrm{25}}{\mathrm{10}\left(\mathrm{5}{n}^{\mathrm{2}}…
Question Number 10108 by ridwan balatif last updated on 24/Jan/17 Answered by nume1114 last updated on 24/Jan/17 $${from}\:{Vieta}'{s}\:{fomula}: \\ $$$$\begin{cases}{{x}_{\mathrm{1}} +{x}_{\mathrm{2}} =\mathrm{2}}\\{{x}_{\mathrm{1}} {x}_{\mathrm{2}} =−\mathrm{5}}\end{cases} \\…
Question Number 75623 by liki last updated on 14/Dec/19 Commented by liki last updated on 14/Dec/19 $$…\boldsymbol{{Please}}\:\boldsymbol{{anyone}}\:\boldsymbol{{to}}\:\boldsymbol{{help}}\:\boldsymbol{{me}}\:\boldsymbol{{this}}\:\boldsymbol{{Qn}}\:! \\ $$ Answered by $@ty@m123 last updated on…
Question Number 141163 by Niiicooooo last updated on 16/May/21 Answered by mindispower last updated on 16/May/21 $$\zeta\left({n}\right)=\mathrm{1}+\underset{{k}\geqslant\mathrm{2}} {\sum}\frac{\mathrm{1}}{{k}^{{n}} } \\ $$$${k}^{{n}} \geqslant{nk}^{\mathrm{2}} \:{easy}\:{to}\:{see}\:{that}\:,{k}\geqslant\mathrm{2} \\ $$$${for}\:{n}>>\mathrm{2}…
Question Number 75627 by liki last updated on 14/Dec/19 Answered by $@ty@m123 last updated on 14/Dec/19 $$\boldsymbol{{Initially}}, \\ $$$${Length}={l} \\ $$$${Breadth}={b} \\ $$$$\therefore\:{Diagonal}\:\:\:\boldsymbol{{d}}=\sqrt{{l}^{\mathrm{2}} +{b}^{\mathrm{2}} }\:\:……\left(\mathrm{1}\right)…