Question Number 74623 by liki last updated on 27/Nov/19 Commented by liki last updated on 27/Nov/19 $$….\:{I}\:{need}\:{help}\:{plz}… \\ $$ Answered by mr W last updated…
Question Number 140153 by dhgt last updated on 04/May/21 $${Q}\mathrm{135930} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 74582 by Maclaurin Stickker last updated on 26/Nov/19 $${Find}\:{all}\:{values}\:{of}\:{x}: \\ $$$$\left(\mathrm{2}^{{x}} \right)^{{x}^{\mathrm{2}} −\mathrm{8}} =\mathrm{32} \\ $$ Answered by MJS last updated on 26/Nov/19…
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Question Number 140089 by otchereabdullai@gmail.com last updated on 04/May/21 $$\mathrm{Given}\:\mathrm{that}\:\mathrm{log}_{\mathrm{4}} \left(\mathrm{y}−\mathrm{1}\right)+\mathrm{log}_{\mathrm{4}} \left(\frac{\mathrm{x}}{\mathrm{y}}\right)=\mathrm{k} \\ $$$$\mathrm{and}\:\mathrm{log}_{\mathrm{2}} \left(\mathrm{y}+\mathrm{1}\right)−\mathrm{log}_{\mathrm{2}} \mathrm{x}=\mathrm{k}−\mathrm{1} \\ $$$$\mathrm{Show}\:\mathrm{that}\:\mathrm{y}^{\mathrm{2}} =\mathrm{1}+\mathrm{8}^{\mathrm{k}} \\ $$$$\mathrm{Hence}\:\mathrm{deduce}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{y}\:\mathrm{and}\:\mathrm{x}\: \\ $$$$\mathrm{when}\:\mathrm{k}=\mathrm{1} \\ $$…
Question Number 74555 by necxxx last updated on 26/Nov/19 $${Good}\:{day}\:{friends}.{I}\:{saw}\:{a}\:{post}\:{on}\:{a} \\ $$$${group}\:{chat}\:{where}\:{someone}\:{said}\:{he}\:{needs} \\ $$$${help}\:{on}\:{functional}\:{iteration}.\:{He}\:{said} \\ $$$${he}\:{needs}\:{some}\:{solvings}\:{with}\:{overleaf} \\ $$$${and}\:{also}\:{to}\:{play}\:{the}\:{report}\:{on}\:{latex}.{He}\:{is} \\ $$$${highly}\:{willing}\:{to}\:{pay}\:{so}\:{I}\:{thought}\:{to}\:{myself} \\ $$$${to}\:{post}\:{it}\:{here}\:{just}\:{incase}\:{there}'{s} \\ $$$${someone}\:{that}\:{can}\:{pick}\:{up}\:{the}\:{offer}. \\…
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Question Number 140075 by mohammad17 last updated on 04/May/21 $${if}\:{z}=\frac{{x}^{\mathrm{2}} }{{y}}+\mathrm{3}{y}\:\:\:{find}\:{the}\:{absolute}\:{and}\:{relative} \\ $$$${error}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 8991 by Chantria last updated on 11/Nov/16 $${prove} \\ $$$$\:\:\:\:{a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} \geqslant\mathrm{3}{abc}\:;\:\forall{a},{b},{c}\geqslant\mathrm{0} \\ $$ Answered by aydnmustafa1976 last updated on 14/Nov/16 $${A}.{M}\geqslant{G}.{M}\:\:\:\left(\:{a}^{\mathrm{3}}…