Question Number 138376 by KwesiDerek last updated on 12/Apr/21 $$\boldsymbol{\mathrm{log}}_{\mathrm{4}} \left(\boldsymbol{\mathrm{x}}+\mathrm{2}\right)+\boldsymbol{\mathrm{log}}_{\mathrm{3}} \left(\boldsymbol{\mathrm{x}}−\mathrm{2}\right)=\mathrm{1} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 72835 by Maclaurin Stickker last updated on 03/Nov/19 $${In}\:{an}\:{arithmetic}\:{progression}\:{the} \\ $$$${ninth}\:{term}\:{is}\:{greater}\:{than}\:{the}\:{second} \\ $$$${term}\:{and}\:{the}\:{sum}\:{of}\:{the}\:{first}\:{term} \\ $$$${with}\:{the}\:{fifth}\:{term}\:{is}\:\mathrm{20}.\:{What}\:{is} \\ $$$${the}\:{fifth}\:{term}? \\ $$ Answered by $@ty@m123 last…
Question Number 138367 by KwesiDerek last updated on 12/Apr/21 $$\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}^{−\mathrm{2}} =\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}}}} \\ $$$$\boldsymbol{\mathrm{x}}^{\mathrm{16}} +\boldsymbol{\mathrm{x}}^{−\mathrm{16}} =? \\ $$ Commented by Kamel last updated on 12/Apr/21…
Question Number 7287 by sarathon last updated on 21/Aug/16 $$\mathrm{7}{a}_{\mathrm{1}} +\mathrm{7}^{\mathrm{2}} {a}_{\mathrm{2}} +\centerdot\centerdot\centerdot+\mathrm{7}^{{n}} {a}_{{n}} =\mathrm{3}^{{n}} −\mathrm{1} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{a}_{{n}} }{\mathrm{3}^{{n}−\mathrm{1}} }=? \\ $$ Commented…
Question Number 138362 by mohammad17 last updated on 12/Apr/21 $${prove}\:{that}\: \\ $$$$ \\ $$$$\left(\mathrm{1}+{i}\right)^{{n}} +\left(\mathrm{1}−{i}\right)^{{n}} =\mathrm{2}^{\frac{{n}+\mathrm{1}}{\mathrm{2}}} \\ $$ Commented by Dwaipayan Shikari last updated on…
Question Number 138355 by mohammad17 last updated on 12/Apr/21 Commented by mohammad17 last updated on 12/Apr/21 $${help}\:{me}\:{sir} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 138350 by abenarhodym last updated on 12/Apr/21 $$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right) \\ $$ Answered by Ñï= last updated on 12/Apr/21 $$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}} \left(\mathrm{2}^{\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{2}}} \right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{2}^{\mathrm{2}}…
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Question Number 138338 by mohammad17 last updated on 12/Apr/21 Commented by mohammad17 last updated on 12/Apr/21 $${help}\:{me}\:{sirlease} \\ $$ Answered by mr W last updated…