Question Number 137667 by aurpeyz last updated on 05/Apr/21 $${y}={log}_{\mathrm{2}} \left({x}^{\mathrm{5}} +\mathrm{4}\right)\:{find}\:\frac{{dy}}{{dx}} \\ $$ Answered by Dwaipayan Shikari last updated on 05/Apr/21 $${y}=\frac{{log}\left({x}^{\mathrm{5}} +\mathrm{4}\right)}{{log}\left(\mathrm{2}\right)}\Rightarrow\frac{{dy}}{{dx}}=\frac{\mathrm{1}}{{log}\left(\mathrm{2}\right)}.\frac{\mathrm{5}{x}^{\mathrm{4}} }{{x}^{\mathrm{5}}…
Question Number 137659 by JulioCesar last updated on 05/Apr/21 Commented by JulioCesar last updated on 05/Apr/21 $${help}\:{me} \\ $$ Commented by MJS_new last updated on…
Question Number 137652 by ZiYangLee last updated on 05/Apr/21 $$\mathrm{Given}\:\mathrm{that}\:\alpha,\beta,\gamma\:\mathrm{are}\:\mathrm{the}\:\mathrm{three}\:\mathrm{roots}\:\mathrm{of}\: \\ $$$$\mathrm{the}\:\mathrm{equation}\:\left({x}−\mathrm{59}\right)^{\mathrm{3}} +\left(\mathrm{2}{x}−\mathrm{64}\right)^{\mathrm{3}} =\left(\mathrm{3}{x}−\mathrm{123}\right)^{\mathrm{3}} , \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\alpha+\beta+\gamma. \\ $$ Answered by mitica last updated on…
Question Number 72093 by naka3546 last updated on 24/Oct/19 $${a},\:{b},\:{c},\:{d},\:{e},\:{f},\:{g},\:{h},\:{i},\:{j}\:\:\:{are}\:\:\:{different}\:\:{nonnegative}\:\:{integers}\:. \\ $$$${Find}\:\:{all}\:\:{numbers}\:\:{that}\:\:{satisfy} \\ $$$$\:\:\:\:\:{a}\:×\:{bc}\:×\:{def}\:\:=\:\:{ghij} \\ $$ Commented by prakash jain last updated on 24/Oct/19 $${abcdef}={ghij}?…
Question Number 72086 by wo1lxjwjdb last updated on 24/Oct/19 $$\left(\mathrm{sin}^{−\mathrm{1}} \left({x}\right)\right)^{{v}} +\left(\mathrm{cos}^{−\mathrm{1}} \left({x}\right)^{{v}} \right) \\ $$$${for}\:{any}\:{value}\:{v}\:{what}\:{is}\:{it}\: \\ $$$${in}\:{terms}\:{of}\:{pi} \\ $$$$ \\ $$ Terms of Service…
Question Number 137615 by mohammad17 last updated on 04/Apr/21 $$\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} {ln}\left(\frac{\mathrm{1}+{tanx}}{\mathrm{1}−{tanx}}\right)^{{xcos}\left(\mathrm{8}{x}\right)} {dx} \\ $$ Commented by mohammad17 last updated on 04/Apr/21 $${hwo}\:{is}\:{can}\:{solve}\:{this}\:? \\ $$…
Question Number 137594 by Ñï= last updated on 04/Apr/21 $$\left({x}+\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}\right)\left({y}+\sqrt{{y}^{\mathrm{4}} +\mathrm{4}}\right)=\mathrm{9} \\ $$$${x}\sqrt{{y}^{\mathrm{4}} +\mathrm{4}}+{y}\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}=? \\ $$ Answered by bemath last updated on 04/Apr/21…
Question Number 137591 by Ñï= last updated on 04/Apr/21 $${a}=\sqrt[{\mathrm{3}}]{\mathrm{4}}+\sqrt[{\mathrm{3}}]{\mathrm{2}}+\sqrt[{\mathrm{3}}]{\mathrm{1}} \\ $$$$\frac{\mathrm{3}}{{a}}+\frac{\mathrm{3}}{{a}^{\mathrm{2}} }+\frac{\mathrm{1}}{{a}^{\mathrm{3}} }=? \\ $$ Commented by mr W last updated on 05/Apr/21 $$=\mathrm{1}…
Question Number 137590 by Ñï= last updated on 04/Apr/21 $${x}=\mathrm{1}+\frac{\pi+\left(\pi+\mathrm{1}\right)^{\mathrm{2}} +\left(\pi+\mathrm{2}\right)^{\mathrm{3}} +\left(\pi+\mathrm{3}\right)^{\mathrm{4}} }{\mathrm{4}+\mathrm{5}^{\mathrm{2}} +\mathrm{6}^{\mathrm{3}} +\mathrm{7}^{\mathrm{4}} } \\ $$$$\sqrt{{x}+\mathrm{2}\sqrt{{x}−\mathrm{1}}}+\sqrt{{x}−\mathrm{2}\sqrt{{x}−\mathrm{1}}}=? \\ $$ Commented by mindispower last updated…
Question Number 72048 by ahmadshahhimat775@gmail.com last updated on 23/Oct/19 Answered by mind is power last updated on 23/Oct/19 $$\mathrm{a}_{\mathrm{2}} =\frac{\mathrm{6}}{\mathrm{1}+\mathrm{3}}=\frac{\mathrm{3}}{\mathrm{2}}=\frac{\mathrm{3}.\mathrm{2}^{\mathrm{0}} }{\mathrm{2}}=\frac{\mathrm{2}+\mathrm{1}}{\mathrm{2}}=\frac{\mathrm{2}+\mathrm{2}^{\mathrm{0}} }{\mathrm{2}} \\ $$$$\mathrm{a}_{\mathrm{3}} =\frac{\mathrm{3}}{\mathrm{1}+\frac{\mathrm{3}}{\mathrm{2}}}=\frac{\mathrm{6}}{\mathrm{5}}\:=\frac{\mathrm{3}.\mathrm{2}}{\mathrm{3}.\mathrm{2}−\mathrm{1}}=\frac{\mathrm{4}+\mathrm{2}}{\mathrm{4}+\mathrm{2}−\mathrm{1}}=\frac{\mathrm{2}+\mathrm{2}^{\mathrm{2}}…