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Question-183135

Question Number 183135 by Tawa11 last updated on 21/Dec/22 Answered by TheSupreme last updated on 21/Dec/22 $$\frac{\Delta{y}}{\Delta{h}}=\frac{{y}\left({x}+{h}\right)−{y}\left({x}\right)}{{h}}=\frac{\mathrm{2}\left({x}+{h}\right)^{\mathrm{2}} −\mathrm{2}{x}^{\mathrm{2}} +\mathrm{5}{h}}{{h}}= \\ $$$$=\frac{\mathrm{2}{h}\left(\mathrm{2}{x}+{h}\right)+\mathrm{5}{h}}{{h}}=\mathrm{4}{x}+\mathrm{5}+\mathrm{2}{h} \\ $$$${x}=\mathrm{2} \\ $$$$\frac{\Delta{y}}{\Delta{h}}=\mathrm{13}+\mathrm{2}{h}\:…

Question-183117

Question Number 183117 by Subhabrata last updated on 20/Dec/22 Answered by Rasheed.Sindhi last updated on 21/Dec/22 $$\begin{array}{|c|c|c|c|c|c|c|c|c|}{{Class}}&\hline{{x}_{{i}} }&\hline{{f}_{{i}} }&\hline{{x}_{{i}} {f}_{{i}} }\\{\mathrm{30}−\mathrm{39}}&\hline{\mathrm{34}.\mathrm{5}}&\hline{\mathrm{2}}&\hline{\mathrm{69}}\\{\mathrm{40}−\mathrm{49}}&\hline{\mathrm{44}.\mathrm{5}}&\hline{\mathrm{3}}&\hline{\mathrm{133}.\mathrm{5}}\\{\mathrm{50}−\mathrm{59}}&\hline{\mathrm{54}.\mathrm{5}}&\hline{\mathrm{11}}&\hline{\mathrm{599}.\mathrm{5}}\\{\mathrm{60}−\mathrm{69}}&\hline{\mathrm{64}.\mathrm{5}}&\hline{\mathrm{20}}&\hline{\mathrm{1290}}\\{\mathrm{70}−\mathrm{79}}&\hline{\mathrm{74}.\mathrm{5}}&\hline{{f}_{\mathrm{5}} }&\hline{\mathrm{74}.\mathrm{5}{f}_{\mathrm{5}} }\\{\mathrm{80}−\mathrm{89}}&\hline{\mathrm{84}.\mathrm{5}}&\hline{\mathrm{25}}&\hline{\mathrm{2112}.\mathrm{5}}\\{\mathrm{90}−\mathrm{99}}&\hline{\mathrm{94}.\mathrm{5}}&\hline{\mathrm{7}}&\hline{\mathrm{661}.\mathrm{5}}\\{}&\hline{}&\hline{\underset{=\mathrm{68}+{f}_{\mathrm{5}} } {\Sigma{f}_{{i}}…

Question-52025

Question Number 52025 by Tawa1 last updated on 02/Jan/19 Commented by Abdo msup. last updated on 03/Jan/19 $$\left.\mathrm{8}\right)\left({x}+\mathrm{1}\right)^{\mathrm{6}} +\left({x}−\mathrm{1}\right)^{\mathrm{6}} =\mathrm{0}\:\Leftrightarrow\frac{\left({x}−\mathrm{1}\right)^{\mathrm{6}} }{\left({x}+\mathrm{1}\right)^{\mathrm{6}} }\:=−\mathrm{1}\:\Leftrightarrow \\ $$$$\left(\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\right)^{\mathrm{6}} \:=−\mathrm{1}\:\:{let}\:\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\:={z}\:\Rightarrow{z}^{\mathrm{6}}…

A-bullet-of-mass-1kg-is-fired-and-get-embedded-into-a-block-of-wood-of-mass-1kg-initially-at-rest-the-velocity-of-the-bullet-before-collision-is-90m-s-1-What-is-the-velocity-of-the-system-after-colli

Question Number 183036 by Mastermind last updated on 18/Dec/22 $$\mathrm{A}\:\mathrm{bullet}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{1kg}\:\mathrm{is}\:\mathrm{fired}\:\mathrm{and}\:\mathrm{get} \\ $$$$\mathrm{embedded}\:\mathrm{into}\:\mathrm{a}\:\mathrm{block}\:\mathrm{of}\:\mathrm{wood}\:\mathrm{of} \\ $$$$\mathrm{mass}\:\mathrm{1kg}\:\mathrm{initially}\:\mathrm{at}\:\mathrm{rest}\:\mathrm{the}\:\mathrm{velocity} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{bullet}\:\mathrm{before}\:\mathrm{collision}\:\mathrm{is}\:\mathrm{90m}/\mathrm{s} \\ $$$$\left.\mathrm{1}\right)\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{system} \\ $$$$\mathrm{after}\:\mathrm{collision}? \\ $$$$\left.\mathrm{2}\right)\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{kinetic}\:\mathrm{energy}\:\mathrm{before} \\ $$$$\mathrm{and}\:\mathrm{after}\:\mathrm{the}\:\mathrm{collision}. \\…

A-Golfer-practising-on-a-range-with-an-accelerated-tree-4-9m-above-the-fairway-is-able-to-strike-a-ball-so-that-it-leaves-the-club-with-a-horizontal-velocity-of-20m-s-Assume-the-acceleration-due-to

Question Number 183039 by Mastermind last updated on 18/Dec/22 $$\mathrm{A}\:\mathrm{Golfer}\:\mathrm{practising}\:\mathrm{on}\:\mathrm{a}\:\mathrm{range} \\ $$$$\mathrm{with}\:\mathrm{an}\:\mathrm{accelerated}\:\mathrm{tree}\:\mathrm{4}.\mathrm{9m}\:\mathrm{above} \\ $$$$\mathrm{the}\:\mathrm{fairway}\:\mathrm{is}\:\mathrm{able}\:\mathrm{to}\:\mathrm{strike}\:\mathrm{a}\:\mathrm{ball} \\ $$$$\mathrm{so}\:\mathrm{that}\:\mathrm{it}\:\mathrm{leaves}\:\mathrm{the}\:\mathrm{club}\:\mathrm{with}\:\mathrm{a}\: \\ $$$$\mathrm{horizontal}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{20m}/\mathrm{s}. \\ $$$$\left(\mathrm{Assume}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{due}\:\mathrm{to}\:\right. \\ $$$$\mathrm{gravity}\:\mathrm{is}\:\mathrm{9}.\mathrm{8m}/\mathrm{s}^{\mathrm{2}} \:\mathrm{and}\:\mathrm{the}\:\mathrm{effect}\:\mathrm{of}\:\mathrm{air} \\ $$$$\mathrm{resistance}\:\mathrm{maybe}\:\mathrm{ignored}\:\mathrm{unless}…