Question Number 182779 by Noorzai last updated on 14/Dec/22 Commented by Rasheed.Sindhi last updated on 14/Dec/22 $$\mathrm{M}+\mathrm{L}=\mathrm{7} \\ $$ Answered by TheSupreme last updated on…
Question Number 117207 by Lordose last updated on 10/Oct/20 $$\boldsymbol{\mathrm{C}}\mathrm{an}\:\mathrm{anyone}\:\mathrm{recommend}\:\mathrm{a}\:\mathrm{pdf}\:\mathrm{for} \\ $$$$\mathrm{learning}\:\mathrm{hypergeometric}\:\mathrm{functions}? \\ $$ Commented by Eric002 last updated on 10/Oct/20 https://www.google.com/url?sa=t&source=web&rct=j&url=https://mathworld.wolfram.com/HypergeometricFunction.html&ved=2ahUKEwiqwonDl6rsAhXRzYUKHRk_CCkQFjAOegQIChAE&usg=AOvVaw2xQoinPcbJ6__csZMr8zEG Commented by Eric002…
Question Number 51673 by wishyman last updated on 29/Dec/18 Commented by wishyman last updated on 29/Dec/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 117205 by AbduraufKodiriy last updated on 10/Oct/20 $$\int_{\mathrm{0}} ^{\:\mathrm{2}\pi} \frac{\boldsymbol{{cos}}^{\mathrm{2}} \mathrm{3}\boldsymbol{{x}}}{\mathrm{1}−\mathrm{2}\boldsymbol{{a}}\centerdot\boldsymbol{{cosx}}+\boldsymbol{{a}}^{\mathrm{2}} }\boldsymbol{{dx}}\:−\:?\:\left(\boldsymbol{{a}}\in\boldsymbol{{C}}/\left\{−\mathrm{1};\:\mathrm{1}\right\}\right) \\ $$$$\boldsymbol{{I}}\:\boldsymbol{{need}}\:\boldsymbol{{a}}\:\boldsymbol{{solution}}\:\boldsymbol{{through}}\:\boldsymbol{{complex}}\:\boldsymbol{{analysis}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 51643 by Tawa1 last updated on 29/Dec/18 $$\mathrm{If}\:\:\:\mid\mathrm{z}\mid\:=\:\mathrm{1},\:\:\:\:\mathrm{prove}\:\mathrm{that}\:\:\:\:\:\frac{\mathrm{z}\:−\:\mathrm{1}}{\overset{−} {\mathrm{z}}\:−\:\mathrm{1}}\:\:\:\:\:\:\left(\mathrm{z}\:\neq\:\mathrm{1}\right)\:\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{pure}\:\mathrm{imaginary} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 $${z}={rcos}\theta+{irsin}\theta={r}\left({cos}\theta+{isin}\theta\right) \\ $$$$\mid{z}\mid={r}=\mathrm{1} \\ $$$$\frac{{z}−\mathrm{1}}{\overset{−}…
Question Number 51630 by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 Commented by…
Question Number 51628 by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 $${above}\:{questions}\:{asked}\:{in}\:{B}.{STAT}\:\:{entrance}\:{exam} \\…
Question Number 51621 by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18 Commented by…
Question Number 51571 by Tawa1 last updated on 28/Dec/18 $$\mathrm{If}\:\:\:\alpha\:−\:\mathrm{j}\beta\:\:=\:\:\frac{\mathrm{1}}{\mathrm{a}\:−\:\mathrm{jb}}\:\:,\:\:\:\:\:\:\mathrm{where}\:\:\:\alpha,\:\beta,\:\mathrm{a},\:\mathrm{b}\:\:\mathrm{are}\:\mathrm{real},\:\mathrm{express}\:\:\mathrm{b}\:\:\mathrm{in}\:\mathrm{terms} \\ $$$$\mathrm{of}\:\:\alpha,\:\beta\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{Answer}:\:\:\:\:\:\:\:\:\:\:\frac{−\:\beta}{\alpha^{\mathrm{2}} \:+\:\beta^{\mathrm{2}} \:−\:\mathrm{2}\alpha\:+\:\mathrm{1}} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 28/Dec/18 $${a}−{ib}=\frac{\mathrm{1}}{\alpha−{i}\beta} \\…
Question Number 182576 by peeeter last updated on 11/Dec/22 Terms of Service Privacy Policy Contact: info@tinkutara.com