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Question Number 39255 by tanmay.chaudhury50@gmail.com last updated on 04/Jul/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 39253 by tanmay.chaudhury50@gmail.com last updated on 04/Jul/18 Commented by tanmay.chaudhury50@gmail.com last updated on 04/Jul/18 $${posting}\:{formula}… \\ $$ Commented by math khazana by abdo…
Question Number 104789 by 175mohamed last updated on 23/Jul/20 $${if}\:{y}^{\left({n}\right)} \:{is}\:{the}\:{derivative}\:{of}\:{the}\:{function}\:{y} \\ $$$${of}\:{the}\:{order}\:{n},\:{then} \\ $$$$\int{y}^{\left({n}\right)} {dx}\:=…….. \\ $$ Commented by mr W last updated on…
Question Number 104783 by 175mohamed last updated on 23/Jul/20 $${find}\:\frac{{d}^{{n}} {y}}{{dx}^{{n}} }\:{for}\:\:\:\:{f}\left({x}\overset{} {\right)}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}−{x}}} \\ $$ Answered by Dwaipayan Shikari last updated on 23/Jul/20 $${f}\left({x}\right)=\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}−{x}}} \\…
Question Number 104777 by Anindita last updated on 23/Jul/20 Answered by Aziztisffola last updated on 23/Jul/20 $$\mathrm{3}.\mathrm{5}+\mathrm{4}.\mathrm{5}=\mathrm{8} \\ $$$$+\:\:\:\:\:\:\:\:\:+ \\ $$$$\mathrm{9}.\mathrm{5}−\mathrm{3}.\mathrm{5}=\mathrm{6} \\ $$$$\mathrm{13}\:\:\:\:\:\:\:\:\mathrm{8} \\ $$…
Question Number 170311 by Mastermind last updated on 20/May/22 $$\mathrm{5}\frac{{dy}}{{dx}}={tan}\left(\mathrm{2}{x}+\mathrm{2}{y}+\mathrm{6}\right) \\ $$$$ \\ $$$${Mastermind} \\ $$ Answered by mr W last updated on 20/May/22 $${t}=\mathrm{2}{x}+\mathrm{2}{y}+\mathrm{6}…
Question Number 104768 by Anindita last updated on 23/Jul/20 $$\left(\frac{\mathrm{1}}{\mathrm{8}}\boldsymbol{\div}\frac{\mathrm{1}}{\mathrm{8}}\right)\left(\frac{\mathrm{1}}{\mathrm{7}}\boldsymbol{\div}\frac{\mathrm{1}}{\mathrm{7}}\right)\left(\frac{\mathrm{2}}{\mathrm{3}}\boldsymbol{\div}\frac{\mathrm{2}}{\mathrm{3}}\right)=\:? \\ $$ Answered by Skabetix last updated on 24/Jul/20 $$=\frac{\mathrm{8}}{\mathrm{8}}\:×\:\frac{\mathrm{7}}{\mathrm{7}}\:\:×\:\frac{\mathrm{3}}{\mathrm{3}}\:=\:\mathrm{1}\:×\:\mathrm{1}\:×\:\mathrm{1}=\:\mathrm{1} \\ $$ Terms of Service…
Question Number 39231 by LX Z last updated on 04/Jul/18 $$\left({sin}^{−\mathrm{1}} {x}\right)^{\mathrm{2}} +\:\:\left({sin}^{−\mathrm{1}} {y}\right)^{\mathrm{2}} +\:\:\mathrm{2}\left({sin}^{−\mathrm{1}} {x}\right) \\ $$$$\left({sin}^{−\mathrm{1}} {y}\right)=\:\pi^{\mathrm{2}} ,{then}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} \:{is}\:{equal}\:{to}? \\ $$ Answered…
Question Number 39222 by behi83417@gmail.com last updated on 04/Jul/18 Commented by math khazana by abdo last updated on 04/Jul/18 $$\left.\mathrm{1}\right)\:\:{f}\:{is}\:{defined}\:{on}\:\left[\mathrm{0},\mathrm{1}\left[\right.\right. \\ $$$${f}^{'} \left({x}\right)=\frac{\frac{−\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{1}−{x}}}\left(\mathrm{1}−\sqrt{{x}}\right)\:−\sqrt{\mathrm{1}−{x}}\left(\frac{−\mathrm{1}}{\mathrm{2}\sqrt{{x}}}\right)}{\left(\mathrm{1}−\sqrt{{x}}\right)^{\mathrm{2}} } \\…