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The-distance-moved-by-a-particle-in-t-seconds-is-given-by-s-t-3-3t-1-where-s-is-in-metres-Find-the-velocity-and-Asseleration-after-3-seconds-Show-all-steps-with-short-statements-on-how-the-a

Question Number 37860 by Rio Mike last updated on 18/Jun/18 $${The}\:{distance}\:{moved}\:{by}\:{a}\:{particle} \\ $$$${in}\:{t}\:{seconds}\:{is}\:{given}\:{by} \\ $$$${s}=\:{t}^{\mathrm{3}} \:+\:\mathrm{3}{t}\:+\:\mathrm{1}\:{where}\:{s}\:{is}\:{in}\: \\ $$$${metres}.{Find}\:{the}\:{velocity}\:{and}\: \\ $$$${Asseleration}\:{after}\:\mathrm{3}\:{seconds}. \\ $$$$ \\ $$$${Show}\:{all}\:{steps}\:{with}\:{short}\:{statements} \\…

Resolve-1-x-y-ydx-x-2-dy-0-2-2x-y-dx-4x-2y-3-dy-0-

Question Number 168910 by LEKOUMA last updated on 21/Apr/22 $${Resolve} \\ $$$$\left.\mathrm{1}\right)\:\left({x}−{y}\right){ydx}−{x}^{\mathrm{2}} {dy}=\mathrm{0} \\ $$$$\left.\mathrm{2}\right)\left(\mathrm{2}{x}−{y}\right){dx}+\left(\mathrm{4}{x}−\mathrm{2}{y}+\mathrm{3}\right){dy}=\mathrm{0} \\ $$ Commented by LEKOUMA last updated on 21/Apr/22 $${The}\:{question}\:{is}\:{to}\:{following}\:{differential}…

let-f-x-e-2x-arctan-x-2-1-calculate-f-n-x-2-find-f-n-0-3-developp-f-at-integr-serie-

Question Number 37838 by math khazana by abdo last updated on 18/Jun/18 $${let}\:{f}\left({x}\right)=\:{e}^{−\mathrm{2}{x}} \:{arctan}\left({x}^{\mathrm{2}} \right) \\ $$$$\left.\mathrm{1}\right){calculate}\:{f}^{\left({n}\right)} \left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{3}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$…

The-side-of-a-square-is-increasing-at-a-rate-of-0-1cms-1-Find-the-rate-of-increase-of-the-perimeter-of-the-square-when-the-length-of-side-is-4cm-

Question Number 37795 by Rio Mike last updated on 17/Jun/18 $${The}\:{side}\:{of}\:{a}\:{square}\:{is}\:{increasing} \\ $$$${at}\:{a}\:{rate}\:{of}\:\mathrm{0}.\mathrm{1}{cms}^{−\mathrm{1}} .\:{Find}\:{the} \\ $$$${rate}\:{of}\:{increase}\:{of}\:{the}\:{perimeter} \\ $$$${of}\:{the}\:{square}\:{when}\:{the}\:{length}\:{of} \\ $$$${side}\:{is}\:\mathrm{4}{cm}. \\ $$ Answered by tanmay.chaudhury50@gmail.com…