Question Number 167372 by LEKOUMA last updated on 14/Mar/22 $${Calculate}\: \\ $$$$\int_{−\mathrm{2}} ^{\mathrm{2}} \left(\mid{x}\mid+{x}\right){e}^{−\mid{x}\mid} {dx} \\ $$ Answered by Mathspace last updated on 14/Mar/22 $${I}=\int_{−\mathrm{2}}…
Question Number 36291 by Rio Mike last updated on 31/May/18 $$\mathrm{find}\:\mathrm{the}\:\mathrm{image}\:\mathrm{of}\:\:\left(−\mathrm{2},\mathrm{3}\right)\:\mathrm{after}\:\mathrm{the} \\ $$$$\mathrm{reflection}\:\mathrm{on}\:\mathrm{the} \\ $$$$\left.\mathrm{a}\left.\right)\:\mathrm{x}−\mathrm{axis}\:\:\:\:\:\mathrm{b}\right)\:\mathrm{y}−\mathrm{axis} \\ $$ Answered by Joel579 last updated on 31/May/18 $$\left.{a}\right)\:\left(−\mathrm{2},−\mathrm{3}\right)…
Question Number 36290 by Rio Mike last updated on 31/May/18 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{between}\:\mathrm{the}\:\mathrm{lines} \\ $$$$\:\:\:{l}_{\mathrm{1}} :\mathrm{y}\:−\:\mathrm{x}\:−\mathrm{4}\:=\:\mathrm{0}\:\mathrm{and}\:{l}_{\mathrm{2}} :\mathrm{2}{x}\:−\:{y}\:=\:\mathrm{7}\: \\ $$$$\mathrm{and}\:\mathrm{hence}\:\mathrm{the}\:\mathrm{perpendicular}\: \\ $$$$\mathrm{distance}\:\mathrm{from}\:\mathrm{one}\:\mathrm{point}\:\mathrm{on}\:{l}_{\mathrm{1}} \\ $$$$\mathrm{to}\:{l}_{\mathrm{2}} . \\ $$$$ \\…
Question Number 101794 by 175mohamed last updated on 04/Jul/20 Answered by mahdi last updated on 04/Jul/20 $$\mathrm{0}<…<\frac{\mathrm{1}}{\mathrm{5}}<\frac{\mathrm{1}}{\mathrm{4}}<\frac{\mathrm{1}}{\mathrm{3}}\:\:\:\:\:\:\:\:\:\frac{\mathrm{2}}{\mathrm{3}}<\frac{\mathrm{3}}{\mathrm{4}}<\frac{\mathrm{4}}{\mathrm{5}}<…<\mathrm{1} \\ $$$$\Rightarrow\left(\mathrm{0},\mathrm{1}\right) \\ $$ Terms of Service Privacy…
Question Number 167330 by LEKOUMA last updated on 13/Mar/22 $${Calculate} \\ $$$$\int\frac{\mathrm{1}}{{x}+\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}}{dx} \\ $$ Answered by greogoury55 last updated on 13/Mar/22 $$=\int\:\frac{\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}−{x}}{{x}+\mathrm{1}}\:{dx}\: \\…
Question Number 36239 by Rio Mike last updated on 30/May/18 $$\mathrm{the}\:\mathrm{opposite}\:\mathrm{side}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{is}\: \\ $$$$\:{x}\:+\:{y},\mathrm{and}\:\mathrm{the}\:\mathrm{hypotenuse}\:\mathrm{is}\:\mathrm{3}{x}+{y} \\ $$$$\mathrm{Given}\:\mathrm{that}\:\mathrm{that}\:\mathrm{A}\:\mathrm{is}\:\mathrm{an}\:\mathrm{acute}\:\mathrm{angle} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{Cos}\:\mathrm{A} \\ $$ Commented by Rasheed.Sindhi last updated on…
Question Number 101768 by 175mohamed last updated on 04/Jul/20 Commented by mr W last updated on 04/Jul/20 $${type}\:{your}\:{question}\:{please}! \\ $$ Terms of Service Privacy Policy…
Question Number 101762 by 175mohamed last updated on 04/Jul/20 Commented by mr W last updated on 04/Jul/20 $$\mathrm{2}×\mathrm{2}^{\mathrm{20}} =\mathrm{2}^{\mathrm{21}} \:{g}\:\approx\:\mathrm{2097}\:{kg}\:\approx\:\mathrm{2}.\mathrm{1}\:{to}\:! \\ $$ Commented by IRAN_majid…
Question Number 101767 by 175mohamed last updated on 04/Jul/20 Commented by mr W last updated on 04/Jul/20 $${a}\:{CD}\:{can}\:{cover}\:{a}\:{wall}\:{area}\:{of} \\ $$$$\mathrm{2}×\frac{{D}}{\mathrm{2}}×\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}×{D}=\frac{\sqrt{\mathrm{3}}{D}^{\mathrm{2}} }{\mathrm{2}} \\ $$$${number}\:{of}\:{CDs}\:{needed}\:{to}\:{cover} \\ $$$$\mathrm{6}{m}×\mathrm{4}{m}\:{wall}\:{area}:…
Question Number 36218 by Rio Mike last updated on 30/May/18 $$\mathrm{proof}\:\mathrm{that}\: \\ $$$$\:\mathrm{2}\left(\sqrt{{n}}\:−\:\mathrm{1}\right)\:<\:\mathrm{1}\:+\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\:+\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}+…+ \\ $$$$\frac{\mathrm{1}}{\:\sqrt{{n}}}\:<\:\mathrm{2}\sqrt{\mathrm{n}} \\ $$ Commented by abdo mathsup 649 cc last updated…