Question Number 160917 by LEKOUMA last updated on 09/Dec/21 $${Calculate} \\ $$$$\left.{a}\right)\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\left(\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\right)^{{x}^{\mathrm{2}} } \\ $$$$\left.{b}\right)\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{2}^{\frac{\mathrm{1}}{{x}}} −\mathrm{1}}{\mathrm{2}^{\frac{\mathrm{1}}{{x}}} +\mathrm{1}} \\ $$ Answered by jama last…
Question Number 160900 by LEKOUMA last updated on 08/Dec/21 $${Calculate} \\ $$$$\left.\mathrm{1}\right)\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{{x}+\mathrm{1}}{\mathrm{2}{x}+\mathrm{1}}\right)^{{x}^{\mathrm{2}} } \\ $$$$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\left(\frac{\mathrm{sin}\:{x}}{\mathrm{sin}\:{a}}\right)^{\frac{\mathrm{1}}{{x}−{a}}} \\ $$ Commented by cortano last updated on…
Question Number 160844 by Tawa11 last updated on 07/Dec/21 Answered by mr W last updated on 08/Dec/21 Commented by mr W last updated on 08/Dec/21…
Question Number 160823 by sdfg last updated on 07/Dec/21 Commented by sdfg last updated on 07/Dec/21 $${please}\:{help}\:{me} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 95259 by mhmd last updated on 24/May/20 $${find}\:{all}\:{roots}\:\left(\sqrt{\mathrm{6}}\:−\sqrt{\mathrm{2}}{i}\right)^{\frac{\mathrm{1}}{\mathrm{3}}} {by}\:{using}\:{demover}\:{theorem}\:? \\ $$ Commented by mhmd last updated on 24/May/20 $${help}\:{me}\:? \\ $$ Answered by…
Question Number 29700 by 803jaideep@gmail.com last updated on 11/Feb/18 $$\mathrm{32}^{\mathrm{32}^{\mathrm{32}} } \:/\mathrm{7}…\mathrm{find}\:\mathrm{remainder} \\ $$ Answered by Tinkutara last updated on 13/Feb/18 Commented by Tinkutara last…
Question Number 29680 by 803jaideep@gmail.com last updated on 11/Feb/18 $$\mathrm{i}^{\mathrm{i}\:} \:\:\mathrm{what}\:\mathrm{is}\:\mathrm{iota}\:\mathrm{to}\:\mathrm{power}\:\mathrm{iota} \\ $$ Answered by sma3l2996 last updated on 11/Feb/18 $${i}^{{i}} =\left({e}^{{i}\pi/\mathrm{2}} \right)^{{i}} ={e}^{−\pi/\mathrm{2}} \\…
Question Number 29648 by byaw last updated on 11/Feb/18 $$\mathrm{How}\:\mathrm{many}\:\mathrm{arrangements}\:\mathrm{are} \\ $$$$\mathrm{there}\:\mathrm{of}\:\mathrm{4}\:\mathrm{letters}\:\mathrm{chosen}\:\mathrm{from}\: \\ $$$$\mathrm{the}\:\mathrm{word}\:{COMMUNICATION} \\ $$ Commented by Rasheed.Sindhi last updated on 11/Feb/18 $$\mathrm{4096} \\…
Question Number 160689 by Tawa11 last updated on 04/Dec/21 Answered by TheSupreme last updated on 04/Dec/21 $${v}_{\mathrm{1}} {t}_{\mathrm{1}} +{v}_{\mathrm{2}} {t}_{\mathrm{2}} ={d} \\ $$$${t}_{\mathrm{1}} +{t}_{\mathrm{2}} ={T}…
Question Number 29607 by tawa tawa last updated on 10/Feb/18 $$\mathrm{Prove}\:\mathrm{the}\:\mathrm{convergence}\:\mathrm{of}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{sequence} \\ $$$$\left(\mathrm{i}\right)\:\:\left\{\frac{\mathrm{n}\:−\:\mathrm{1}}{\mathrm{n}}\right\}_{\mathrm{n}\:=\:\mathrm{1}} ^{\infty} \:\:\:\:\:\:\:\:\left(\mathrm{ii}\right)\:\:\:\left\{\frac{\mathrm{1}}{\:\sqrt[{\mathrm{n}}]{\mathrm{2}}}\right\}_{\mathrm{n}\:=\:\mathrm{1}} ^{\infty} \:\:\:\:\:\:\left(\mathrm{iii}\right)\:\:\:\:\left\{\frac{\mathrm{n}\:+\:\mathrm{1}}{\mathrm{n}}\right\}_{\mathrm{n}\:=\:\mathrm{1}} ^{\infty} \\ $$ Terms of Service Privacy Policy…