Menu Close

Category: Others

e-x-1-x-2-x-3-2-dx-

Question Number 26909 by sorour87 last updated on 31/Dec/17 $$\int\frac{{e}^{{x}} \left(\frac{\mathrm{1}}{{x}}−\frac{\mathrm{2}}{{x}^{\mathrm{3}} }\right)}{−\mathrm{2}}{dx} \\ $$ Answered by prakash jain last updated on 31/Dec/17 $$\int{e}^{{x}} \left(−\frac{\mathrm{1}}{\mathrm{2}{x}}+\frac{\mathrm{1}}{{x}^{\mathrm{3}} }\right){dx}…

a-3-b-6-a-b-

Question Number 26839 by Samar khan last updated on 30/Dec/17 $$\mathrm{a}=\mathrm{3}\:\mathrm{b}=\mathrm{6} \\ $$$$\mathrm{a}−\mathrm{b}=? \\ $$ Answered by Rasheed.Sindhi last updated on 30/Dec/17 $$\mathrm{a}−\mathrm{b}=\mathrm{3}−\mathrm{6}=−\mathrm{3} \\ $$…

0-1-dx-1-3x-1-3x-

Question Number 92344 by 675480065 last updated on 06/May/20 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{dx}}{\:\sqrt{\mathrm{1}+\mathrm{3x}}−\sqrt{\mathrm{1}−\mathrm{3x}}} \\ $$ Commented by john santu last updated on 06/May/20 $$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\frac{\sqrt{\mathrm{1}+\mathrm{3}{x}}\:+\:\sqrt{\mathrm{1}−\mathrm{3}{x}}}{\mathrm{6}{x}}\:\:{dx}\:…

Question-26686

Question Number 26686 by Rasheed.Sindhi last updated on 28/Dec/17 Commented by Rasheed.Sindhi last updated on 28/Dec/17 $$\mathrm{Question}#\mathrm{26312}\:\mathrm{by}\:\mathrm{Mr}\:\mathrm{Shivram198922} \\ $$$$\mathrm{reposted}\:\mathrm{here}\:\mathrm{to}\:\mathrm{refocus}\:\mathrm{the}\:\mathrm{question}. \\ $$ Answered by Rasheed.Sindhi last…

f-R-R-R-such-that-f-x-iy-x-2-y-2-Then-f-is-a-many-one-and-into-function-b-one-one-and-onto-function-c-many-one-and-onto-function-d-one-one-and-into-function-

Question Number 26681 by Tanveer48 last updated on 28/Dec/17 $${f}:{R}×{R}\rightarrow{R}\:{such}\:{that}\:{f}\left({x}+{iy}\right)=\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} .} \\ $$$${Then}\:{f}\:{is} \\ $$$$\left.{a}\right)\:{many}−{one}\:{and}\:{into}\:{function} \\ $$$$\left.{b}\right)\:{one}−{one}\:{and}\:{onto}\:{function} \\ $$$$\left.{c}\right)\:{many}−{one}\:{and}\:{onto}\:{function} \\ $$$$\left.{d}\right)\:{one}−{one}\:{and}\:{into}\:{function} \\ $$ Commented…