Question Number 26078 by ktomboy1992 last updated on 19/Dec/17 $$\mathrm{x}^{\mathrm{2}} −\mathrm{x}−\mathrm{42}\:\mathrm{factorise} \\ $$ Answered by kaivan.ahmadi last updated on 19/Dec/17 $$\left(\mathrm{x}−\mathrm{7}\right)\left(\mathrm{x}+\mathrm{6}\right) \\ $$ Terms of…
Question Number 91613 by M±th+et+s last updated on 01/May/20 $${solve}\:{without}\:{using}\:{l}'{hopital} \\ $$$$\underset{{x}\rightarrow{e}} {{lim}}\frac{{ln}\left({x}\right)−\mathrm{1}}{\frac{{e}}{{x}}−\mathrm{1}} \\ $$ Commented by abdomathmax last updated on 01/May/20 $${changement}\:\:\frac{{e}}{{x}}={t}\:{give}\:\:\:\frac{{x}}{{e}}=\frac{\mathrm{1}}{{t}}\:\Rightarrow{x}\:=\frac{{e}}{{t}} \\ $$$${lim}_{{x}\rightarrow{e}}…
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Question Number 91588 by M±th+et+s last updated on 01/May/20 $${what}\:{is}\:{f}^{−\mathrm{1}} \:{for}\:{f}\left({x}\right)=\lfloor{x}\rfloor?? \\ $$ Commented by mr W last updated on 01/May/20 $${x}\rightarrow\lfloor{x}\rfloor\:{is}\:{a}\:{function},\:{but} \\ $$$$\lfloor{x}\rfloor\rightarrow{x}\:{is}\:{not}\:{a}\:{function},\:{because}\:{an} \\…
Question Number 26046 by ktomboy1992 last updated on 19/Dec/17 $${x}^{\mathrm{3}} +\:\frac{\mathrm{1}}{{x}^{\mathrm{3}} }=\mathrm{18}\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{valu}\:\mathrm{of}\:{x}+\frac{\mathrm{1}}{{x}} \\ $$ Answered by $@ty@m last updated on 19/Dec/17 $${Given} \\ $$$${x}^{\mathrm{3}} +\frac{\mathrm{1}}{{x}^{\mathrm{3}}…
Question Number 26047 by ajfour last updated on 18/Dec/17 Commented by ajfour last updated on 18/Dec/17 $${Initially}\:{a}\:{chain}\:{lies}\:{on}\:{a} \\ $$$${frictionless}\:{table}\:{top}\:{with}\:{length} \\ $$$$\boldsymbol{{h}}\:{hanging}\:{such}\:{that}\:{end}\:{B}\:{touches} \\ $$$${the}\:{ground}.\:{If}\:{released},\:{with}\:{what} \\ $$$${speed}\:{does}\:{end}\:{A}\:{slip}\:{of}\:{the}\:{table}…
Question Number 26031 by mubeen897@hotmail.com last updated on 18/Dec/17 $${calculate}\:{the}\:{number}\:{of}\:{protons}\:{which}\:{would}\:{have}\:{a}\:{charge}\:{of}\:{one}\:{coulomb}\:{charge}\left({Proton}\:{Charge}=\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} {C}\right). \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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