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Question Number 25655 by rita1608 last updated on 12/Dec/17 $${use}\:{lagranges}\:{mean}\:{value}\:{theorem}\:{to} \\ $$$${prove}\:{that}\: \\ $$$${x}<{sin}^{−\mathrm{1}} {x}<\frac{{x}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }},\mathrm{0}<{x}<\mathrm{1}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 25656 by rita1608 last updated on 12/Dec/17 $${trace}\:{the}\:{curve}\: \\ $$$${y}^{\mathrm{2}} \left({x}+\mathrm{1}\right)={x}^{\mathrm{2}} \left(\mathrm{3}−{x}\right) \\ $$$${clearly}\:{stating}\:{all}\:{the}\:{properties}\:{used} \\ $$$${for}\:{tracing}. \\ $$ Commented by ajfour last updated…
Question Number 25634 by rita1608 last updated on 12/Dec/17 $${find}\:{the}\:{equation}\:{of}\:{the}\:{tangent}\:{to}\: \\ $$$${the}\:{curve}\:\sqrt{{x}}+\sqrt{{y}}=\sqrt{{a}}\:{at}\:{any}\:{point} \\ $$$$\left({x},{y}\right){on}\:{it}. \\ $$ Answered by mrW1 last updated on 13/Dec/17 $$\frac{{dx}}{\mathrm{2}\sqrt{{x}}}+\frac{{dy}}{\mathrm{2}\sqrt{{y}}}=\mathrm{0} \\…
Question Number 25635 by rita1608 last updated on 12/Dec/17 $${let}\:{f}\:{be}\:{the}\:{function}\:{defined}\:{on} \\ $$$$\left[−\mathrm{1},\mathrm{1}\right]\:{by} \\ $$$${f}\left({x}\right)=\left\{\begin{cases}{−\mathrm{1},{if}\:{x}\:{is}\:{rational}}\\{\mathrm{1},{if}\:{x}\:{is}\:{irrational}.}\end{cases}\right. \\ $$$${find}\:{U}\left({P},{f}\right)\:{and}\:{L}\left({P},{f}\right).{f}\:{is}\:{integrable} \\ $$$${or}\:{not}\:? \\ $$ Commented by rita1608 last updated…
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Question Number 25630 by tawa tawa last updated on 12/Dec/17 Answered by jota@ last updated on 13/Dec/17 $${m}_{{B}} {g}−{T}={m}_{{B}} {a} \\ $$$${T}={m}_{{A}} {a}.\:{Then} \\ $$$${m}_{{B}}…
Question Number 91149 by Rio Michael last updated on 28/Apr/20 $$\mathrm{A}\:\mathrm{particle}\:\mathrm{starts}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{and}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line}\:\mathrm{on}\:\mathrm{a}\:\mathrm{smooth}\: \\ $$$$\mathrm{horizontal}\:\mathrm{surface}.\:\mathrm{Its}\:\mathrm{acceleration}\:\mathrm{at}\:\mathrm{time}\:{t}\:\mathrm{seconds}\:\mathrm{is}\:\mathrm{given}\:\mathrm{by} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{k}\left(\mathrm{4}{v}\:+\:\mathrm{1}\right)\:\mathrm{ms}^{−\mathrm{2}} \\ $$$$\mathrm{where}\:{k}\:\mathrm{is}\:\mathrm{a}\:\mathrm{positve}\:\mathrm{constant}\:\mathrm{and}\:{v}\:\mathrm{ms}^{−\mathrm{1}} \:\mathrm{is}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}. \\ $$$$\mathrm{Given}\:\mathrm{that}\:{v}\:=\:\frac{{e}^{\mathrm{2}} −\mathrm{1}}{\mathrm{4}}\:\mathrm{when}\:{t}\:=\:\mathrm{1}.\:\:\mathrm{show}\:\mathrm{that}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{v}\:=\:\frac{\mathrm{1}}{\mathrm{4}}\left({e}^{\mathrm{2}{t}} −\mathrm{1}\right) \\…
Question Number 25578 by adityapratap2585@gmail.com last updated on 11/Dec/17 $$\mathrm{3}\:\mathrm{men}\:\mathrm{A},\mathrm{B}\:\mathrm{and}\:\mathrm{C}\:\mathrm{can}\:\mathrm{complete}\:\mathrm{a} \\ $$$$\mathrm{work}\:\mathrm{in}\:\mathrm{such}\:\mathrm{a}\:\mathrm{way}\:\mathrm{that}\:\mathrm{A}\:\mathrm{works}\:\mathrm{for} \\ $$$$\mathrm{all}\:\mathrm{the}\:\mathrm{days},\:\mathrm{B}\:\mathrm{works}\:\mathrm{for}\:\mathrm{1st}\:\mathrm{and}\:\mathrm{2nd} \\ $$$$\mathrm{day}\:\mathrm{and}\:\mathrm{C}\:\mathrm{works}\:\mathrm{for}\:\mathrm{3rd},\:\mathrm{4th}\:\mathrm{and}\:\mathrm{5th} \\ $$$$\mathrm{day}.\:\mathrm{If}\:\mathrm{B}\:\mathrm{and}\:\mathrm{C}\:\mathrm{can}\:\mathrm{do}\:\mathrm{as}\:\mathrm{much}\:\mathrm{work} \\ $$$$\mathrm{in}\:\mathrm{two}\:\mathrm{days}\:\mathrm{as}\:\mathrm{a}\:\mathrm{alone}\:\mathrm{does}\:\mathrm{in}\:\mathrm{3}\:\mathrm{days}. \\ $$$$\mathrm{If}\:\mathrm{B}\:\mathrm{and}\:\mathrm{C}\:\mathrm{can}\:\mathrm{complete}\:\mathrm{the}\:\mathrm{work}\: \\ $$$$\mathrm{without}\:\mathrm{tbe}\:\mathrm{help}\:\mathrm{of}\:\mathrm{A}\:\mathrm{in}\:\mathrm{6}\:\mathrm{days}\:\mathrm{then}\: \\…
Question Number 91119 by talminator2856791 last updated on 28/Apr/20 $$\: \\ $$$$\:\int_{\mathrm{0}} ^{\:\int_{\mathrm{0}} ^{\:{k}} \:\left(\mathrm{1}\:+\:\frac{\mathrm{1}}{{x}}\right)^{{x}} {dx}} \:\mathrm{sin}\:\left({x}^{{e}} \right)\:{dx}\:=\:\frac{\pi}{{e}} \\ $$$$\:{k}\:=\:? \\ $$ Terms of Service…