Question Number 15737 by tawa tawa last updated on 13/Jun/17 $$\mathrm{Sir}\:\:\:\mathrm{mrW1}\:\mathrm{and}\:\mathrm{Ajfour},\:\mathrm{please}\:\mathrm{which}\:\mathrm{advance}\:\mathrm{or}\:\mathrm{physics}\:\mathrm{textbook}\:\mathrm{pdf}\:\mathrm{can}\:\mathrm{i}\:\mathrm{get} \\ $$ Commented by arnabpapu550@gmail.com last updated on 13/Jun/17 $$\mathrm{In}\:\mathrm{which}\:\mathrm{class}\:\mathrm{do}\:\mathrm{you}\:\mathrm{read}\:\mathrm{Tawa}\:? \\ $$ Commented by…
Question Number 15734 by chux last updated on 13/Jun/17 $$\mathrm{An}\:\mathrm{elastic}\:\mathrm{cord}\:\mathrm{can}\:\mathrm{be}\:\mathrm{stretched}\:\mathrm{to} \\ $$$$\mathrm{its}\:\mathrm{elastic}\:\mathrm{limit}\:\mathrm{by}\:\mathrm{a}\:\mathrm{load}\:\mathrm{of}\:\mathrm{2N}.\mathrm{If}\: \\ $$$$\mathrm{a}\:\mathrm{35cm}\:\mathrm{lemgth}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cord}\:\mathrm{is} \\ $$$$\mathrm{extended}\:\mathrm{0}.\mathrm{6cm}\:\mathrm{by}\:\mathrm{a}\:\mathrm{force}\:\mathrm{of}\:\mathrm{0}.\mathrm{5N}, \\ $$$$\mathrm{what}\:\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cord} \\ $$$$\mathrm{when}\:\mathrm{the}\:\mathrm{stretching}\:\mathrm{force}\:\mathrm{is}\:\mathrm{2}.\mathrm{5N}? \\ $$$$\left(\mathrm{a}\right)\mathrm{350}.\mathrm{8cm} \\ $$$$\left(\mathrm{b}\right)\mathrm{352}.\mathrm{8cm} \\…
Question Number 15623 by tawa tawa last updated on 12/Jun/17 Answered by ajfour last updated on 12/Jun/17 Commented by ajfour last updated on 12/Jun/17 $$\:\:{BD}^{\mathrm{2}}…
Question Number 15610 by RasheedSoomro last updated on 12/Jun/17 $$\mathrm{The}\:\mathrm{temperature}\:\mathrm{of}\:\mathrm{some}\:\mathrm{100}\:\mathrm{litres} \\ $$$$\mathrm{is}\:\mathrm{80}°\mathrm{C}.\:\:\mathrm{10}\:\mathrm{litres}\:\mathrm{water},\mathrm{whose}\:\mathrm{temperature} \\ $$$$\mathrm{is}\:\mathrm{100}°\mathrm{C}\:\mathrm{is}\:\mathrm{mixed}\:\mathrm{in}\:\mathrm{it}.\mathrm{What}\:\mathrm{will}\:\mathrm{be}\:\mathrm{the} \\ $$$$\mathrm{temperature}\:\mathrm{of}\:\mathrm{mixed}\:\mathrm{water}? \\ $$ Commented by RasheedSoomro last updated on 12/Jun/17…
Question Number 15599 by Tinkutara last updated on 12/Jun/17 $$\mathrm{Two}\:\mathrm{paper}\:\mathrm{screens}\:{A}\:\mathrm{and}\:{B}\:\mathrm{are} \\ $$$$\mathrm{separated}\:\mathrm{by}\:\mathrm{100}\:\mathrm{m}\:\mathrm{distance}.\:\mathrm{A}\:\mathrm{bullet} \\ $$$$\mathrm{pierces}\:{A}\:\mathrm{and}\:\mathrm{then}\:{B}.\:\mathrm{The}\:\mathrm{hole}\:\mathrm{in}\:{B}\:\mathrm{is} \\ $$$$\mathrm{10}\:\mathrm{cm}\:\mathrm{below}\:\mathrm{the}\:\mathrm{hole}\:\mathrm{in}\:{A}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{bullet} \\ $$$$\mathrm{is}\:\mathrm{travelling}\:\mathrm{horizontally}\:\mathrm{at}\:{A},\:\mathrm{calculate} \\ $$$$\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bullet}\:\mathrm{at}\:{A}. \\ $$$$\left(\mathrm{Neglecting}\:\mathrm{the}\:\mathrm{types}\:\mathrm{of}\:\mathrm{frictional}\right. \\ $$$$\left.\mathrm{forces}\right) \\…
Question Number 81124 by TawaTawa last updated on 09/Feb/20 Answered by Rio Michael last updated on 10/Feb/20 $$\left.\mathrm{b}\right)\:\left(\mathrm{i}\right)\:\mathrm{Energy}\:\mathrm{output}\:=\:\mathrm{work}\:\mathrm{done}\:\mathrm{in}\: \\ $$$$\mathrm{lifting}\:\mathrm{cement}\:\mathrm{to}\:\mathrm{the}\:\mathrm{height}\:\mathrm{B}\:=\:{mgsin}\theta×\mathrm{5} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{50}{sin}\mathrm{60}×\mathrm{5}\:=\:\mathrm{216}.\mathrm{5}{J} \\ $$$$\left.\mathrm{ii}\right)\:\mathrm{Energy}\:\mathrm{input}\:=\:{Fd}\:=\:\mathrm{500}\:×\:\mathrm{5}\:=\:\mathrm{2500}{J} \\…
Question Number 15591 by Tinkutara last updated on 12/Jun/17 $$\mathrm{A}\:\mathrm{projectile}\:\mathrm{projected}\:\mathrm{from}\:\mathrm{the}\:\mathrm{ground} \\ $$$$\mathrm{has}\:\mathrm{its}\:\mathrm{direction}\:\mathrm{of}\:\mathrm{motion}\:\mathrm{making}\:\mathrm{an} \\ $$$$\mathrm{angle}\:\frac{\pi}{\mathrm{4}}\:\mathrm{with}\:\mathrm{the}\:\mathrm{horizontal}\:\mathrm{at}\:\mathrm{a}\:\mathrm{height} \\ $$$$\mathrm{40}\:\mathrm{m}.\:\mathrm{Its}\:\mathrm{initial}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{projection}\:\mathrm{is} \\ $$$$\mathrm{50}\:\mathrm{m}/\mathrm{s},\:\mathrm{the}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{projection}\:\mathrm{is}? \\ $$ Answered by mrW1 last updated…
Question Number 81115 by Ak5060 last updated on 09/Feb/20 $$\mathrm{e}^{\mathrm{x}} \int\frac{\mathrm{2}{csec}^{\mathrm{2}} \theta\:{d}\theta}{\left[\mathrm{4}+\left(\mathrm{2}{tan}\theta\right)^{\mathrm{2}} \right]^{\mathrm{3}/\mathrm{2}} }\:\:= \\ $$$$\mathrm{e}^{\mathrm{x}} \int\frac{\mathrm{2}{csec}^{\mathrm{2}} \theta\:{d}\theta}{\left[\mathrm{4}+\left(\mathrm{2}{tan}\theta\right)^{\mathrm{2}} \right]^{\mathrm{3}/\mathrm{2}} }\:\:= \\ $$ Terms of Service…
Question Number 146621 by 777316 last updated on 14/Jul/21 $$\int_{\mathrm{0}} ^{\:\infty} \:\frac{{xsin}\left(\mathrm{4}{x}\right)}{\mathrm{9}\:+\:\mathrm{4}{x}^{\mathrm{2}} }{dx}\:=\: \\ $$ Answered by mathmax by abdo last updated on 14/Jul/21 $$\Psi=\int_{\mathrm{0}}…
Question Number 15539 by tawa tawa last updated on 11/Jun/17 Terms of Service Privacy Policy Contact: info@tinkutara.com