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Question-14440

Question Number 14440 by christine last updated on 31/May/17 Answered by prakash jain last updated on 31/May/17 $$\mathrm{number}\:\mathrm{of}\:\mathrm{integer}\:\mathrm{1}\leqslant{n}\leqslant\mathrm{100} \\ $$$$\mathrm{divisible}\:\mathrm{by}\:\mathrm{4}\:=\lfloor\frac{\mathrm{100}}{\mathrm{4}}\rfloor=\mathrm{25} \\ $$$$\mathrm{divisible}\:\mathrm{by}\:\mathrm{6}\:=\lfloor\frac{\mathrm{100}}{\mathrm{6}}\rfloor=\mathrm{16} \\ $$$$\mathrm{divisible}\:\mathrm{by}\:\mathrm{by}\:\mathrm{4}\:\mathrm{and}\:\mathrm{6}\:=\lfloor\frac{\mathrm{100}}{\mathrm{12}}\rfloor=\mathrm{8} \\…

Select-the-correct-formulae-for-uniformly-accelerated-motion-along-a-straight-line-More-than-one-option-are-correct-1-v-u-at-2-s-u-v-2-t-3-s-vt-1-2-at-2-4-s-v-2-u-2

Question Number 14297 by Tinkutara last updated on 30/May/17 $$\mathrm{Select}\:\mathrm{the}\:\mathrm{correct}\:\mathrm{formulae}\:\mathrm{for} \\ $$$$\mathrm{uniformly}\:\mathrm{accelerated}\:\mathrm{motion}\:\mathrm{along}\:\mathrm{a} \\ $$$$\mathrm{straight}\:\mathrm{line}\:\left(\mathrm{More}\:\mathrm{than}\:\mathrm{one}\:\mathrm{option}\right. \\ $$$$\left.\mathrm{are}\:\mathrm{correct}\right) \\ $$$$\left(\mathrm{1}\right)\:{v}\:=\:{u}\:+\:{at} \\ $$$$\left(\mathrm{2}\right)\:{s}\:=\:\left(\frac{{u}\:+\:{v}}{\mathrm{2}}\right){t} \\ $$$$\left(\mathrm{3}\right)\:{s}\:=\:{vt}\:−\:\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$$$\left(\mathrm{4}\right)\:{s}\:=\:\frac{{v}^{\mathrm{2}} \:−\:{u}^{\mathrm{2}}…

Is-the-equation-correct-for-uniformly-accelerated-motion-along-a-straight-line-s-vt-1-2-at-2-

Question Number 14291 by Tinkutara last updated on 30/May/17 $$\mathrm{Is}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{correct}\:\mathrm{for}\:\mathrm{uniformly} \\ $$$$\mathrm{accelerated}\:\mathrm{motion}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight} \\ $$$$\mathrm{line}? \\ $$$${s}\:=\:{vt}\:−\:\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$ Commented by tawa tawa last updated on…

Question-14246

Question Number 14246 by tawa tawa last updated on 30/May/17 Commented by ajfour last updated on 30/May/17 Commented by ajfour last updated on 30/May/17 $${a}=\frac{{v}−{u}}{\Delta{t}}\:=\frac{\mathrm{25}−\mathrm{30}}{\mathrm{3}}=−\frac{\mathrm{5}}{\mathrm{3}}{m}/{s}^{\mathrm{2}}…