Category: Others

Question Number 14079 by Tinkutara last updated on 27/May/17 Commented by ajfour last updated on 27/May/17 $${tbreshold}\:{frequency}\:= \\ $$$$\:\:\:\:\:\:\:\left({speed}\:{of}\:{e}.{m}.\:{wave}\right)/\left({threshold}\:{wavelength}\right) \\ $$$$\boldsymbol{\nu}_{\mathrm{0}} =\frac{\boldsymbol{{c}}}{\boldsymbol{\lambda}_{\mathrm{0}} }\:=\frac{\left(\mathrm{3}×\mathrm{10}^{\mathrm{8}} {m}/{s}\right)}{\left(\mathrm{6800}×\mathrm{10}^{−\mathrm{10}} {m}\right)}…

Question Number 14025 by tawa tawa last updated on 26/May/17 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{number}\:\mathrm{of}\:\mathrm{orders}\:\mathrm{vissible}\:\mathrm{with}\:\mathrm{a}\:\mathrm{diffraction}\:\mathrm{grating} \\ $$$$\mathrm{of}\:\mathrm{500}\:\mathrm{lines}\:\mathrm{per}\:\mathrm{milimitres}\:\:\mathrm{using}\:\mathrm{light}\:\mathrm{of}\:\mathrm{wavelenght}\:\mathrm{600nm}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 14015 by tawa tawa last updated on 26/May/17 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 13965 by tawa tawa last updated on 25/May/17 $$\mathrm{A}\:\mathrm{cathode}\:\mathrm{ray}\:\mathrm{beam}\:\mathrm{is}\:\mathrm{bent}\:\mathrm{in}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{of}\:\mathrm{radius}\:\:\mathrm{2cm}\:\mathrm{by}\:\mathrm{uniform}\:\mathrm{field}\:\mathrm{with} \\ $$$$\mathrm{B}\:=\:\mathrm{4}.\mathrm{5}\:×\:\mathrm{10}^{−\mathrm{3}} \:\mathrm{T}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{electrons}\:??. \\ $$ Answered by sandy_suhendra last updated on 26/May/17 $$\mathrm{mass}\:\mathrm{of}\:\mathrm{electron}\:=\:\mathrm{m}\:=\:\mathrm{9}.\mathrm{1}×\mathrm{10}^{−\mathrm{31}} \:\mathrm{kg}…

Question Number 13886 by tawa tawa last updated on 24/May/17 Answered by ajfour last updated on 24/May/17 $$\mathrm{2}. \\ $$$${F}=\frac{{e}^{\mathrm{2}} }{\mathrm{4}\pi\epsilon_{\mathrm{0}} {r}^{\mathrm{2}} } \\ $$$$\:{r}^{\mathrm{2}}…