Question Number 13578 by tawa tawa last updated on 21/May/17 Answered by ajfour last updated on 21/May/17 Commented by tawa tawa last updated on 21/May/17…
Question Number 79111 by mathocean1 last updated on 22/Jan/20 $$\mathrm{Show}\:\mathrm{that} \\ $$$$\mathrm{E}=\left\{\left({x},\mathrm{y},{z}\right)\:\in\:\mathbb{R}^{\mathrm{3}} \:\:/\:\:{x}−\mathrm{2}{y}+{z}=\mathrm{0}\right\} \\ $$$$\mathrm{is}\:\mathrm{a}\:\mathrm{subspace}\:\mathrm{vector}\:\mathrm{of}\:\mathrm{which}\:\mathrm{we} \\ $$$$\mathrm{will}\:\mathrm{determine}\:\mathrm{one}\:\mathrm{base}. \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{sirs}… \\ $$ Commented by mathmax by…
Question Number 13570 by Tinkutara last updated on 21/May/17 $$\mathrm{A}\:\mathrm{motor}\:\mathrm{boat}\:\mathrm{going}\:\mathrm{downstream} \\ $$$$\mathrm{overcomes}\:\mathrm{a}\:\mathrm{float}\:\mathrm{at}\:\mathrm{a}\:\mathrm{point}\:{A}.\:\mathrm{60}\:\mathrm{minutes} \\ $$$$\mathrm{later}\:\mathrm{it}\:\mathrm{turns}\:\mathrm{and}\:\mathrm{after}\:\mathrm{some}\:\mathrm{time}\:\mathrm{passes} \\ $$$$\mathrm{the}\:\mathrm{float}\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{12}\:\mathrm{km}\:\mathrm{from} \\ $$$$\mathrm{the}\:\mathrm{point}\:{A}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{stream} \\ $$$$\left(\mathrm{assuming}\:\mathrm{constant}\:\mathrm{velocity}\:\mathrm{for}\:\mathrm{the}\right. \\ $$$$\left.\mathrm{boat}\:\mathrm{in}\:\mathrm{still}\:\mathrm{water}\right) \\ $$ Answered…
Question Number 13563 by Tinkutara last updated on 21/May/17 Commented by Tinkutara last updated on 21/May/17 $$\mathrm{36}.\:\mathrm{The}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{at}\:\mathrm{a} \\ $$$$\mathrm{distance}\:{x}\:\mathrm{from}\:\mathrm{origin}\:\mathrm{is} \\ $$$$\left(\mathrm{1}\right)\:{u}\:+\:{kx} \\ $$$$\left(\mathrm{2}\right)\:{u}\:−\:{kx} \\ $$$$\left(\mathrm{3}\right)\:{kx}…
Question Number 144618 by sdfg last updated on 27/Jun/21 Commented by sdfg last updated on 27/Jun/21 $${please}\:{help} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 79079 by ketto255 last updated on 22/Jan/20 Answered by mr W last updated on 22/Jan/20 $${x}\geqslant\mathrm{1}.\mathrm{5} \\ $$$${x}\geqslant\mathrm{3}{y} \\ $$$$\mathrm{3}{x}\leqslant{y}+\mathrm{6} \\ $$$$ \\…
Question Number 13510 by Tinkutara last updated on 20/May/17 $$\mathrm{A}\:\mathrm{body}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{2}\:\mathrm{kg}\:\mathrm{has}\:\mathrm{an}\:\mathrm{initial}\:\mathrm{velocity} \\ $$$$\mathrm{of}\:\mathrm{3}\:\mathrm{ms}^{−\mathrm{1}} \:\mathrm{along}\:{OE}\:\mathrm{and}\:\mathrm{it}\:\mathrm{is}\:\mathrm{subjected} \\ $$$$\mathrm{to}\:\mathrm{a}\:\mathrm{force}\:\mathrm{of}\:\mathrm{4}\:\mathrm{newton}\:\mathrm{in}\:{OF}\:\mathrm{direction} \\ $$$$\mathrm{perpendicular}\:\mathrm{to}\:{OE}.\:\mathrm{The}\:\mathrm{distance}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{body}\:\mathrm{from}\:{O}\:\mathrm{after}\:\mathrm{4}\:\mathrm{second}\:\mathrm{will}\:\mathrm{be} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{12}\:\mathrm{m} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{28}\:\mathrm{m} \\ $$$$\left(\mathrm{c}\right)\:\mathrm{20}\:\mathrm{m}…
Question Number 13478 by Tinkutara last updated on 20/May/17 $$\mathrm{The}\:\mathrm{initial}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{a}\:\mathrm{particle}\:\mathrm{is}\:{u} \\ $$$$\left(\mathrm{at}\:{t}\:=\:\mathrm{0}\right)\:\mathrm{and}\:\mathrm{acceleration}\:{f}\:\mathrm{is}\:\mathrm{given}\:\mathrm{by} \\ $$$${f}\:=\:{at}\:\mathrm{where}\:{t}\:\mathrm{is}\:\mathrm{time}\:\mathrm{and}\:'{a}'\:\mathrm{is}\:\mathrm{a}\:\mathrm{constant}. \\ $$$$\mathrm{Which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{relations}\:\mathrm{is} \\ $$$$\mathrm{valid}? \\ $$$$\left(\mathrm{1}\right)\:{v}\:=\:{u}\:+\:{at}^{\mathrm{2}} \\ $$$$\left(\mathrm{2}\right)\:{v}\:=\:{u}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\:{at}^{\mathrm{2}} \\ $$$$\left(\mathrm{3}\right)\:{v}\:=\:{u}\:+\:{at} \\…
Question Number 79015 by ajfour last updated on 22/Jan/20 $${Rigorously}\:{over}\:{one}\:{month}'{s} \\ $$$${time},\:{I}\:{developed}\:{a}\:{formula}\:{for} \\ $$$${general}\:{cubic}. \\ $$$${x}^{\mathrm{3}} +{ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0} \\ $$$${let}\:\:{x}=\frac{{pt}+{q}}{{t}+\mathrm{1}} \\ $$$$\boldsymbol{{pq}}=\boldsymbol{{m}},\:\boldsymbol{{p}}+\boldsymbol{{q}}=\boldsymbol{{s}} \\ $$$$\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\…