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A-spring-stretches-by-15cm-when-a-mass-of-300g-hangs-down-from-it-if-the-spring-is-then-strethed-an-additional-10cm-and-realeased-calculate-a-the-spring-constant-b-Angular-velocity-c-The-ampli

Question Number 12517 by tawa last updated on 24/Apr/17 $$\mathrm{A}\:\mathrm{spring}\:\mathrm{stretches}\:\mathrm{by}\:\mathrm{15cm}\:\mathrm{when}\:\mathrm{a}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{300g}\:\mathrm{hangs}\:\mathrm{down}\:\mathrm{from}\:\mathrm{it}. \\ $$$$\mathrm{if}\:\mathrm{the}\:\mathrm{spring}\:\mathrm{is}\:\mathrm{then}\:\mathrm{strethed}\:\mathrm{an}\:\mathrm{additional}\:\mathrm{10cm}\:\mathrm{and}\:\mathrm{realeased},\:\mathrm{calculate} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{the}\:\mathrm{spring}\:\mathrm{constant} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{Angular}\:\mathrm{velocity} \\ $$$$\left(\mathrm{c}\right)\:\mathrm{The}\:\mathrm{amplitude}\:\mathrm{of}\:\mathrm{the}\:\mathrm{oscillation} \\ $$$$\left(\mathrm{d}\right)\:\mathrm{The}\:\mathrm{maximum}\:\mathrm{velocity} \\ $$$$\left(\mathrm{e}\right)\:\mathrm{The}\:\mathrm{maximum}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{the}\:\mathrm{mass} \\ $$$$\left(\mathrm{f}\right)\:\mathrm{The}\:\mathrm{period}\:\mathrm{T}\:\mathrm{and}\:\mathrm{frequency}\:\mathrm{f} \\…

If-a-body-of-2kg-mass-is-at-a-distance-of-7200km-from-the-centre-of-the-earth-What-would-the-acceleration-due-to-gravity-be-at-this-point-in-the-Earths-field-a-9-6m-s-2-b-10m-s-2-c-11-3m-s

Question Number 12419 by tawa last updated on 21/Apr/17 $$\mathrm{If}\:\mathrm{a}\:\mathrm{body}\:\mathrm{of}\:\mathrm{2kg}\:\mathrm{mass}\:\mathrm{is}\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{7200km}\:\mathrm{from}\:\mathrm{the}\:\mathrm{centre}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{earth}\:.\:\mathrm{What}\:\mathrm{would}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{due}\:\mathrm{to}\:\mathrm{gravity}\:\mathrm{be}\:\mathrm{at}\:\mathrm{this}\:\mathrm{point}\:\mathrm{in} \\ $$$$\mathrm{the}\:\mathrm{Earths}\:\mathrm{field}\:? \\ $$$$\left(\mathrm{a}\right)\:\mathrm{9}.\mathrm{6m}/\mathrm{s}^{\mathrm{2}} \:\left(\mathrm{b}\right)\:\mathrm{10m}/\mathrm{s}^{\mathrm{2}} \:\left(\mathrm{c}\right)\:\mathrm{11}.\mathrm{3m}/\mathrm{s}^{\mathrm{2}} \:\left(\mathrm{d}\right)\:\mathrm{12}.\mathrm{7m}/\mathrm{s}^{\mathrm{2}} \:\left(\mathrm{e}\right)\:\mathrm{15}.\mathrm{6m}/\mathrm{s}^{\mathrm{2}} \\ $$ Answered by ajfour…

Question-12331

Question Number 12331 by tawa last updated on 19/Apr/17 Answered by mrW1 last updated on 19/Apr/17 $${m}\frac{{v}^{\mathrm{2}} }{{r}}\leqslant\mu{mg} \\ $$$$\mu\geqslant\frac{{v}^{\mathrm{2}} }{{rg}}=\frac{\mathrm{5}^{\mathrm{2}} }{\mathrm{8}×\mathrm{9}.\mathrm{81}}=\mathrm{0}.\mathrm{32} \\ $$ Commented…

When-a-known-standard-resistor-of-2-0-is-connected-to-the-0-0-cm-end-of-a-meter-bridge-The-balance-point-is-found-to-be-at-55-0cm-What-is-the-value-of-the-resistor-

Question Number 12321 by tawa last updated on 19/Apr/17 $$\mathrm{When}\:\mathrm{a}\:\mathrm{known}\:\mathrm{standard}\:\mathrm{resistor}\:\mathrm{of}\:\mathrm{2}.\mathrm{0}\:\Omega\:\mathrm{is}\:\mathrm{connected}\:\mathrm{to}\:\mathrm{the}\:\mathrm{0}.\mathrm{0}\:\mathrm{cm}\:\mathrm{end}\:\mathrm{of} \\ $$$$\mathrm{a}\:\mathrm{meter}\:\mathrm{bridge}.\:\mathrm{The}\:\mathrm{balance}\:\mathrm{point}\:\mathrm{is}\:\mathrm{found}\:\mathrm{to}\:\mathrm{be}\:\mathrm{at}\:\mathrm{55}.\mathrm{0cm}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\: \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{resistor}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-12319

Question Number 12319 by tawa last updated on 19/Apr/17 Answered by chux last updated on 19/Apr/17 $$\frac{\mathrm{R}}{\mathrm{60}}=\frac{\mathrm{20}}{\mathrm{100}−\mathrm{60}} \\ $$$$\mathrm{R}=\frac{\mathrm{20}×\mathrm{60}}{\mathrm{40}}=\mathrm{30}\Omega \\ $$ Commented by tawa last…

What-is-the-acceleration-due-to-gravity-g-on-the-moon-if-g-is-10m-s-2-on-the-earth-

Question Number 12316 by tawa last updated on 18/Apr/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{due}\:\mathrm{to}\:\mathrm{gravity}\:,\:\mathrm{g},\:\mathrm{on}\:\mathrm{the}\:\mathrm{moon}\:,\:\mathrm{if}\:\mathrm{g}\:\mathrm{is}\:\mathrm{10m}/\mathrm{s}^{\mathrm{2}} \:\mathrm{on} \\ $$$$\mathrm{the}\:\mathrm{earth}. \\ $$ Answered by chux last updated on 18/Apr/17 $$\mathrm{since}\:\mathrm{gravity}\:\mathrm{in}\:\mathrm{moon}\:\mathrm{is}\:\frac{\mathrm{1}}{\mathrm{6}}\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{earth}'\mathrm{s}…

In-the-equation-B-0-H-0-M-why-is-the-polarization-of-the-vacuum-accounted-for-by-constant-0-if-the-vacuum-is-absolutely-empty-

Question Number 77845 by OTC-X1 last updated on 11/Jan/20 $$\boldsymbol{\mathrm{I}}\mathrm{n}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\:\boldsymbol{\mathrm{B}}=\mu_{\mathrm{0}} \boldsymbol{\mathrm{H}}×\mu_{\mathrm{0}} \boldsymbol{\mathrm{M}}\: \\ $$$$\mathrm{why}\:\mathrm{is}\:\mathrm{the}\:\mathrm{polarization}\:\mathrm{of}\:\mathrm{the}\:\mathrm{vacuum}\: \\ $$$$\mathrm{accounted}\:\mathrm{for}\:\mathrm{by}\: \\ $$$$\mathrm{constant}\:\mu_{\mathrm{0}} \\ $$$$\mathrm{if}\:\mathrm{the}\:\mathrm{vacuum}\:\mathrm{is}\:\mathrm{absolutely}\:\mathrm{empty}? \\ $$$$ \\…