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Question Number 57931 by Jaiden2019 last updated on 14/Apr/19 $$\mathrm{What}\:\mathrm{is}\:\mathrm{2}^{\mathrm{3}} +\mathrm{6}×\mathrm{4} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 123460 by Dwaipayan Shikari last updated on 25/Nov/20 $${sinh}^{−\mathrm{1}} \left(\mathrm{1}\right)+{sinh}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }\right)+{sinh}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }\right)+{sinh}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{4}^{\mathrm{2}} }\right)+…. \\ $$$$ \\ $$ Commented by Dwaipayan…
Question Number 188954 by Mastermind last updated on 09/Mar/23 $$\mathrm{Solve}\:: \\ $$$$\mathrm{sin}\left(\mathrm{x}\right)\:+\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{tan}\left(\mathrm{x}\right)\:=\:\mathrm{3x} \\ $$$$ \\ $$$$\mathrm{Hey}! \\ $$ Commented by mr W last updated…
Question Number 57873 by 786786AM last updated on 13/Apr/19 $$\mathrm{If}\:\alpha\:+\:\beta+\:\gamma\:=\mathrm{180}°,\:\mathrm{show}\:\mathrm{that}\:\mathrm{cos}\:\frac{\alpha}{\mathrm{2}}\:+\:\mathrm{cos}\:\frac{\beta}{\mathrm{2}}+\:\mathrm{cos}\:\frac{\gamma}{\mathrm{2}}\:=\:\mathrm{4}\:\mathrm{cos}\:\frac{\beta\:+\:\gamma}{\mathrm{4}}\:\:\mathrm{cos}\:\frac{\gamma\:+\:\alpha}{\mathrm{4}}\:\mathrm{cos}\:\frac{\alpha\:+\:\beta}{\mathrm{4}}. \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 13/Apr/19 $${recheck}\:{the}\:{question}…{pls} \\ $$ Answered by math1967…
Question Number 188937 by Tawa11 last updated on 09/Mar/23 A body of mass 20kg lies on a horizontal floor and is acted on by constant…
Question Number 188927 by Math453266 last updated on 09/Mar/23 Answered by integralmagic last updated on 09/Mar/23 $${indution} \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 188926 by Math453266 last updated on 09/Mar/23 Answered by qaz last updated on 10/Mar/23 $${x}_{{n}} =\mathrm{1}+{C}_{{n}} ^{\mathrm{3}} +{C}_{{n}} ^{\mathrm{6}} +… \\ $$$${y}_{{n}} ={C}_{{n}}…
Question Number 57840 by pete last updated on 13/Apr/19 $$\mathrm{A}\:\mathrm{uniform}\:\mathrm{rod}\:\mathrm{ABC},\:\mathrm{weight}\:\mathrm{50N}\:\mathrm{and}\: \\ $$$$\mathrm{length}\:\mathrm{4m}\:\mathrm{rests}\:\mathrm{with}\:\mathrm{one}\:\mathrm{end}\:\mathrm{A}\:\mathrm{on}\:\mathrm{rough} \\ $$$$\mathrm{horizontal}\:\mathrm{ground}\:\mathrm{and}\:\mathrm{is}\:\mathrm{supported}\:\mathrm{by}\: \\ $$$$\mathrm{a}\:\mathrm{smooth}\:\mathrm{peg}\:\mathrm{at}\:\mathrm{B}\:\mathrm{where}\:\mathrm{AB}=\mathrm{2}.\mathrm{5m}. \\ $$$$\mathrm{The}\:\mathrm{peg}\:\mathrm{is}\:\mathrm{2m}\:\mathrm{from}\:\mathrm{the}\:\mathrm{ground}.\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{reactions}\:\mathrm{at}\:\mathrm{A}\:\mathrm{and}\:\mathrm{at}\:\mathrm{the}\:\mathrm{peg}. \\ $$ Terms of Service…
Question Number 57839 by pete last updated on 13/Apr/19 $$\mathrm{A}\:\mathrm{uniform}\:\mathrm{rod}\:\mathrm{AB},\:\mathrm{3m}\:\mathrm{long}\:\mathrm{and}\:\mathrm{weght} \\ $$$$\mathrm{120N},\:\mathrm{rests}\:\mathrm{in}\:\mathrm{equilibrium}\:\mathrm{with}\:\mathrm{end}\:\mathrm{A} \\ $$$$\mathrm{on}\:\mathrm{a}\:\mathrm{rough}\:\mathrm{horizontal}\:\mathrm{table}\:\mathrm{and}\:\mathrm{supported}\: \\ $$$$\mathrm{by}\:\mathrm{a}\:\mathrm{force}\:\mathrm{P}\:\mathrm{applied}\:\mathrm{at}\:\mathrm{its}\:\mathrm{end}\:\mathrm{B}\:\mathrm{at}\:\mathrm{right} \\ $$$$\mathrm{angles}\:\mathrm{to}\:\mathrm{the}\:\mathrm{rod}.\:\mathrm{The}\:\mathrm{rod}\:\mathrm{makes}\:\mathrm{an}\:\mathrm{angle} \\ $$$$\mathrm{of}\:\mathrm{3o}°\:\mathrm{with}\:\mathrm{the}\:\mathrm{table}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{force}\:\mathrm{P}, \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{reaction}\:\mathrm{at}\:\mathrm{the}\:\mathrm{floor}. \\ $$ Terms…