Question Number 219491 by OmoloyeMichael last updated on 26/Apr/25 $$\boldsymbol{{if}}\:\boldsymbol{{x}}''−\mathrm{2}\boldsymbol{{x}}'+\mathrm{10}\boldsymbol{{x}}=\boldsymbol{{e}}^{\mathrm{2}\boldsymbol{{t}}} ,\:\boldsymbol{{at}}\:\boldsymbol{{t}}=\mathrm{0},\boldsymbol{{x}}=\mathrm{0}\:\boldsymbol{{and}}\:\boldsymbol{{x}}'=\mathrm{1} \\ $$$$\boldsymbol{{find}}\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)\:\boldsymbol{{using}}\:\boldsymbol{{laplace}}\:\boldsymbol{{transform}} \\ $$ Answered by mahdipoor last updated on 26/Apr/25 $${Laplace}\:\Rightarrow \\ $$$$\left({Xs}^{\mathrm{2}}…
Question Number 219427 by Nicholas666 last updated on 24/Apr/25 Commented by mr W last updated on 24/Apr/25 $$\Rightarrow{Q}\mathrm{206879} \\ $$ Commented by Nicholas666 last updated…
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Question Number 219289 by Nicholas666 last updated on 22/Apr/25 $$ \\ $$$$\:\:\:\:{if}\:\:\:\:\:\:\:\:\:\:\:{a},{b},{c}\:\in\:\mathbb{Z}\:\:\:, \\ $$$$\:\:\:\:\:{and}\:\:\:\:\:\:\:\:\:\:\:\:{a}^{\mathrm{2}} \:+\:{b}^{\mathrm{2}} \:=\:\:{c}^{\mathrm{2}} \:\:\:, \\ $$$$\:\:\:\:\:\:\:\:{then}\:\:\:\:\:\:\mathrm{3}\mid\left({ab}\right)\:=\:? \\ $$$$ \\ $$ Commented by…
Question Number 219211 by Jubr last updated on 20/Apr/25 Answered by Nicholas666 last updated on 20/Apr/25 $$\bullet{the}\:{magnitude}\:{of}\:{the}\:{Resultant}\:{force}\:{is}\:\mathrm{3}{N},\:\:\:\:\:\:\:\: \\ $$$$ \\ $$$$\bullet{the}\:{resultant}\:{force}\:{acts}; \\ $$$${located}\:\:\mathrm{28}{cm}\:{from}\:{B}, \\ $$$$\:{on}\:{the}\:{extension}\:{of}\:{the}\:{line}\:{AB}\:{on}\:{the}\:{side}\:{of}\:{B}\:…
Question Number 219055 by lengad last updated on 19/Apr/25 Commented by mr W last updated on 19/Apr/25 $${please}\:{post}\:{clear}\:{and}\:{properly}\: \\ $$$${cropped}\:{picture}\centerdot \\ $$ Terms of Service…
Question Number 219017 by Nicholas666 last updated on 18/Apr/25 Commented by Nicholas666 last updated on 18/Apr/25 https://www.quora.com/How-do-You-solve-f-x-1-frac-3-x-frac-7-x-2-frac-17-x-3-frac-41-x-4-frac-99-x-5-frac-239-x-6-dots-f-left-frac-3-sqrt-13-2-right/answer/Bekicot-5?ch=10&oid=1477743855612858&share=66e3ed2c&srid=5Xg5SU&target_type=answer Terms of Service Privacy Policy Contact: info@tinkutara.com