Question Number 54966 by Tawa1 last updated on 15/Feb/19 $$\mathrm{By}\:\mathrm{differentiating}\:\:\:\mathrm{x}\:\sqrt{\mathrm{1}\:+\:\mathrm{x}}\:\:\mathrm{with}\:\mathrm{respect}\:\mathrm{to}\:\mathrm{x}\:, \\ $$$$\mathrm{Evaluate},\:\:\:\:\int_{\:\mathrm{0}} ^{\:\mathrm{2}} \:\frac{\mathrm{x}}{\:\sqrt{\mathrm{1}\:+\:\mathrm{x}}}\:\:\mathrm{dx} \\ $$ Commented by maxmathsup by imad last updated on 17/Feb/19…
Question Number 186026 by Michaelfaraday last updated on 31/Jan/23 Answered by mr W last updated on 31/Jan/23 $$\left({b}\right) \\ $$$${T}_{{A}−{B}} =\mu{m}_{{A}} {g}=\mathrm{0}.\mathrm{35}×\mathrm{25}=\mathrm{8}.\mathrm{75}\:{N}\:\checkmark \\ $$$${T}_{{B}−{C}} =\mu{m}_{{A}}…
Question Number 185996 by Noorzai last updated on 30/Jan/23 Answered by Rasheed.Sindhi last updated on 30/Jan/23 $$\mathrm{M}×\mathrm{3}=\mathrm{18}\Rightarrow\mathrm{M}=\mathrm{6} \\ $$$$\mathrm{2L}+\mathrm{1}=\mathrm{5},\mathrm{15}\Rightarrow\mathrm{L}=\mathrm{2},\mathrm{7}\Rightarrow\mathrm{K}=\mathrm{2},\mathrm{1} \\ $$$$\mathrm{K}+\mathrm{L}+\mathrm{M}=\mathrm{2}+\mathrm{2}+\mathrm{6}=\mathrm{10} \\ $$$$\mathrm{Or} \\ $$$$\mathrm{1}+\mathrm{7}+\mathrm{6}=\mathrm{14}\:\:\:\:\:…
Question Number 185900 by Mingma last updated on 29/Jan/23 Answered by mr W last updated on 29/Jan/23 $${say}\:{AB}={BC}={a} \\ $$$$\angle{ABQ}=\mathrm{15}° \\ $$$${DQ}={a}\left(\mathrm{1}−\mathrm{tan}\:\mathrm{15}°\right) \\ $$$${DR}=\frac{{DQ}}{\mathrm{tan}\:\mathrm{15}°} \\…
Question Number 54825 by Tawa1 last updated on 12/Feb/19 Answered by tanmay.chaudhury50@gmail.com last updated on 12/Feb/19 $${v}_{\mathrm{0}} ={volume}\:{of}\:{glass}\:{bottle}\:{before}\:{heating} \\ $$$${v}_{\mathrm{0}} \left(\mathrm{1}+\gamma_{{g}} \bigtriangleup{T}\right)={volume}\:{of}\:{glass}\:{bottle}\:{after}\:{heating} \\ $$$${v}_{\mathrm{0}} \left(\mathrm{1}+\gamma_{{m}}…
Question Number 120331 by Dwaipayan Shikari last updated on 30/Oct/20 Commented by Dwaipayan Shikari last updated on 30/Oct/20 $${Old}\:{unanswered}\:{Question}.{But}\:{i}\:{want}\:{to}\:{discuss}\:{it} \\ $$ Commented by MJS_new last…
Question Number 54790 by Anju last updated on 11/Feb/19 $${differenciatethefollowing} \\ $$$$\left.{i}\right){x}^{{x}} +\left({sinx}\right)^{{lnx}} = \\ $$$$\left.{ii}\right){sin}^{−\mathrm{1}} \left({tanhx}\right)= \\ $$$$\left.{iii}\right)\sqrt{\mathrm{1}+{x}^{\mathrm{2}} /\mathrm{1}−{x}^{\mathrm{2}} =} \\ $$ Commented by…
Question Number 185847 by Mingma last updated on 28/Jan/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 54770 by Tawa1 last updated on 10/Feb/19 $$\mathrm{A}\:\mathrm{glass}\:\mathrm{bottle}\:\mathrm{full}\:\mathrm{of}\:\mathrm{mercury}\:\mathrm{has}\:\mathrm{mass}\:\mathrm{500g}.\:\mathrm{On}\:\mathrm{being}\:\mathrm{heated}\:\mathrm{through} \\ $$$$\mathrm{35}°\mathrm{C},\:\:\mathrm{2}.\mathrm{43g}\:\mathrm{of}\:\mathrm{mercury}\:\mathrm{are}\:\mathrm{expelled}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{mercury} \\ $$$$\mathrm{remaining}\:\mathrm{in}\:\mathrm{the}\:\mathrm{bottle}.\:\left(\mathrm{Cubic}\:\mathrm{expansivity}\:\mathrm{of}\:\mathrm{mercury}\:\mathrm{is}\:\:\mathrm{1}.\mathrm{8}\:×\:\mathrm{10}^{−\mathrm{4}} \:\mathrm{K}^{−\mathrm{1}} \:,\right. \\ $$$$\mathrm{linear}\:\mathrm{expansivity}\:\mathrm{of}\:\mathrm{glass}\:\mathrm{is}\:\:\mathrm{8}.\mathrm{0}\:×\:\mathrm{10}^{−\mathrm{6}} \mathrm{K}^{−\mathrm{1}} \:. \\ $$ Terms of Service…
Question Number 54767 by pieroo last updated on 10/Feb/19 $$\mathrm{A}\:\mathrm{stone}\:\mathrm{is}\:\mathrm{thrown}\:\mathrm{vertically}\:\mathrm{upwards} \\ $$$$\mathrm{from}\:\mathrm{a}\:\mathrm{cliff}\:\mathrm{20m}\:\mathrm{high}.\:\mathrm{After}\:\mathrm{a}\:\mathrm{time}\:\mathrm{of}\:\mathrm{3}\:\mathrm{s} \\ $$$$\mathrm{it}\:\mathrm{passes}\:\mathrm{the}\:\mathrm{edge}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cliff}\:\mathrm{on}\:\mathrm{its}\:\mathrm{way} \\ $$$$\mathrm{down}.\:\mathrm{Calculate} \\ $$$$\left.\mathrm{a}\right)\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{projection} \\ $$$$\left.\mathrm{b}\right)\:\mathrm{the}\:\mathrm{speed}\:\mathrm{when}\:\mathrm{it}\:\mathrm{hits}\:\mathrm{the}\:\mathrm{ground} \\ $$$$\left.\mathrm{c}\right)\:\mathrm{the}\:\mathrm{times}\:\mathrm{when}\:\mathrm{it}\:\mathrm{is}\:\mathrm{10m}\:\mathrm{above}\:\mathrm{the} \\ $$$$\mathrm{top}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cliff} \\…