Question Number 54502 by math1967 last updated on 05/Feb/19 $${In}\:\bigtriangleup{ABC}\:\mathrm{cos}\:{A}+\mathrm{cos}\:{B}+\mathrm{cos}\:{C}=\frac{\mathrm{3}}{\mathrm{2}} \\ $$$${prove}\:{that}\:{trianle}\:{is}\:{equilateral} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 05/Feb/19 Commented by tanmay.chaudhury50@gmail.com last…
Question Number 185553 by Noorzai last updated on 23/Jan/23 Answered by Frix last updated on 23/Jan/23 $$\mathrm{3}{a}−\mathrm{5}{b}=\mathrm{0}\:\Rightarrow\:{b}=\frac{\mathrm{3}{a}}{\mathrm{5}} \\ $$$$\mathrm{2}{b}−\mathrm{3}{c}=\mathrm{0}\:\Rightarrow\:{c}=\frac{\mathrm{2}{b}}{\mathrm{3}}=\frac{\mathrm{2}{a}}{\mathrm{5}} \\ $$$$\frac{\mathrm{2}{a}−\frac{\mathrm{12}{a}}{\mathrm{5}}+\mathrm{2}{a}}{\frac{\mathrm{3}{a}}{\mathrm{5}}−\frac{\mathrm{6}{a}}{\mathrm{5}}}=−\frac{\mathrm{8}}{\mathrm{3}} \\ $$ Terms of…
Question Number 54457 by tanmay.chaudhury50@gmail.com last updated on 03/Feb/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 185517 by Noorzai last updated on 23/Jan/23 Answered by Ar Brandon last updated on 23/Jan/23 $$\Omega=\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{ln}{x}}{{x}^{\mathrm{6}} −\mathrm{1}}{dx}=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{ln}{x}}{{x}^{\mathrm{6}} −\mathrm{1}}{dx}+\int_{\mathrm{1}} ^{\infty}…
Question Number 185518 by Mastermind last updated on 23/Jan/23 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{convergence}\:\mathrm{of} \\ $$$$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\mathrm{ne}^{−\mathrm{n}^{\mathrm{2}} } \\ $$$$ \\ $$$$\mathrm{M}.\mathrm{m} \\ $$ Commented by aleks041103 last…
Question Number 185470 by Mastermind last updated on 22/Jan/23 $$\mathrm{Determine}\:\mathrm{whether}\:\mathrm{the}\:\mathrm{series} \\ $$$$\mathrm{U}_{\mathrm{n}} =\frac{\mathrm{1}+\mathrm{2n}^{\mathrm{2}} }{\mathrm{1}+\mathrm{n}^{\mathrm{2}} }\:\mathrm{is}\:\mathrm{convergent}\:\mathrm{or}\:\mathrm{not} \\ $$$$ \\ $$$$\mathrm{M}.\mathrm{m} \\ $$ Commented by mr W…
Question Number 185449 by Mastermind last updated on 22/Jan/23 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{first}\:\mathrm{four}\:\mathrm{terms}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{expansion}\:\mathrm{of}\:\frac{\mathrm{x}−\mathrm{3}}{\left(\mathrm{1}−\mathrm{x}^{\mathrm{2}} \right)^{\mathrm{2}} \left(\mathrm{2}+\mathrm{x}^{\mathrm{2}} \right)}\:\mathrm{in} \\ $$$$\mathrm{ascending}\:\mathrm{power}\:\mathrm{of}\:\mathrm{x}. \\ $$$$ \\ $$$$ \\ $$$$\mathrm{M}.\mathrm{m} \\ $$…
Question Number 185450 by Mastermind last updated on 22/Jan/23 $$\mathrm{Write}\:\mathrm{down}\:\mathrm{the}\:\mathrm{expansion}\:\mathrm{of}\: \\ $$$$\left(\mathrm{a}\right)\:\mathrm{cosx}\:\left(\mathrm{b}\right)\:\frac{\mathrm{1}}{\mathrm{l}+\mathrm{x}},\:\mathrm{and}\:\mathrm{hence}\:\mathrm{show} \\ $$$$\mathrm{that}\:\frac{\mathrm{cosx}}{\mathrm{1}+\mathrm{x}}\:=\:\mathrm{1}−\mathrm{x}+\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}−\frac{\mathrm{x}^{\mathrm{3}} }{\mathrm{2}}+\frac{\mathrm{13x}^{\mathrm{4}} }{\mathrm{24}}+… \\ $$$$ \\ $$$$ \\ $$$$\mathrm{M}.\mathrm{m} \\ $$…
Question Number 119866 by Dwaipayan Shikari last updated on 27/Oct/20 Commented by Ar Brandon last updated on 27/Oct/20 Where did you get this, bro ?���� Commented by Dwaipayan Shikari last updated…
Question Number 185401 by Mastermind last updated on 21/Jan/23 $$\mathrm{Show}\:\mathrm{that}\:\frac{\mathrm{1}+\mathrm{z}}{\mathrm{1}−\mathrm{z}}\:+\:\frac{\mathrm{1}+\bar {\mathrm{z}}}{\mathrm{1}−\bar {\mathrm{z}}}\:=\:\frac{\mathrm{2}\left(\mathrm{1}−\mid\mathrm{z}\mid^{\mathrm{2}} \right)}{\mid\mathrm{1}−\mathrm{z}\mid^{\mathrm{2}} } \\ $$$$\mathrm{Where}\:\mathrm{z}\:\mathrm{is}\:\mathrm{a}\:\mathrm{complex}\:\mathrm{number} \\ $$$$ \\ $$$$ \\ $$$$\mathrm{Help}! \\ $$ Commented…