Question Number 63845 by gunawan last updated on 10/Jul/19 $$\underset{{r}=\mathrm{0}} {\overset{{n}} {\sum}}\:^{{n}} {C}_{{r}} \:\frac{\mathrm{1}+{r}\:\mathrm{log}_{{e}} \:\mathrm{10}}{\left(\mathrm{1}+\:\mathrm{log}_{{e}} \:\mathrm{10}^{{n}} \right)^{{r}} }=… \\ $$ Commented by gunawan last updated…
Question Number 63596 by Tawa1 last updated on 05/Jul/19 $$\mathrm{The}\:\mathrm{surnames}\:\mathrm{of}\:\mathrm{40}\:\mathrm{students}\:\mathrm{in}\:\mathrm{a}\:\mathrm{class}\:\mathrm{were}\:\mathrm{arranged}\:\mathrm{in} \\ $$$$\mathrm{alphabetical}\:\mathrm{order}.\:\mathrm{16}\:\mathrm{of}\:\mathrm{the}\:\mathrm{surnames}\:\mathrm{begin}\:\mathrm{with}\:\mathrm{O}\:\mathrm{while} \\ $$$$\mathrm{9}\:\mathrm{of}\:\mathrm{the}\:\mathrm{surnames}\:\mathrm{begin}\:\mathrm{with}\:\mathrm{A}.\:\:\mathrm{14}\:\mathrm{of}\:\mathrm{the}\:\mathrm{letters}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{alphabet}\:\mathrm{do}\:\mathrm{not}\:\mathrm{appear}\:\mathrm{as}\:\mathrm{the}\:\mathrm{first}\:\mathrm{letter}\:\mathrm{of}\:\mathrm{any}\:\mathrm{surname}. \\ $$$$ \\ $$$$\left(\mathrm{i}\right)\:\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{the}\:\mathrm{surname}\:\mathrm{of}\:\mathrm{a}\:\mathrm{child}\:\mathrm{picked} \\ $$$$\mathrm{at}\:\mathrm{random}\:\mathrm{from}\:\mathrm{the}\:\mathrm{class}\:\mathrm{begins}\:\mathrm{with}\:\mathrm{either}\:\mathrm{A}\:\mathrm{or}\:\mathrm{O} \\ $$$$\left(\mathrm{ii}\right)\:\:\mathrm{If}\:\mathrm{more}\:\mathrm{than}\:\mathrm{one}\:\mathrm{surname}\:\mathrm{begins}\:\mathrm{with}\:\mathrm{a}\:\mathrm{letter}\:\mathrm{besides}\:\mathrm{A} \\…
Question Number 63246 by Tawa1 last updated on 01/Jul/19 $$\mathrm{Arrange}\:\mathrm{these}\:\mathrm{digits}:\:\:\:\:\:\:\mathrm{1}\:\:\mathrm{1}\:\:\mathrm{2}\:\:\mathrm{2}\:\:\mathrm{3}\:\:\mathrm{3}\:\:\mathrm{4}\:\:\mathrm{4} \\ $$$$\:\:\:\:\:\:\mathrm{So}\:\mathrm{that}\:\mathrm{the}\:\mathrm{1}'\mathrm{s}\:\mathrm{are}\:\mathrm{four}\:\mathrm{digit}\:\mathrm{apart} \\ $$$$\:\:\:\:\:\:\mathrm{So}\:\mathrm{that}\:\mathrm{the}\:\mathrm{2}'\mathrm{s}\:\mathrm{are}\:\mathrm{three}\:\mathrm{digit}\:\mathrm{apart} \\ $$$$\:\:\:\:\:\:\mathrm{So}\:\mathrm{that}\:\mathrm{the}\:\mathrm{3}'\mathrm{s}\:\mathrm{are}\:\mathrm{two}\:\mathrm{digit}\:\mathrm{apart} \\ $$$$\:\:\:\:\:\:\mathrm{So}\:\mathrm{that}\:\mathrm{the}\:\mathrm{4}'\mathrm{s}\:\mathrm{are}\:\mathrm{one}\:\mathrm{digit}\:\mathrm{apart} \\ $$$$ \\ $$ Commented by mr…
Question Number 62022 by Tawa1 last updated on 14/Jun/19 Answered by MJS last updated on 14/Jun/19 $$\mathrm{3}. \\ $$$$\mathrm{even}:\:\mathrm{2}×\mathrm{6}=\mathrm{12} \\ $$$$\mathrm{uneven}:\:\mathrm{3}×\mathrm{2}=\mathrm{6} \\ $$$$\mathrm{12}+\mathrm{6}=\mathrm{18} \\ $$$$\mathrm{4}.…
Question Number 62014 by Tawa1 last updated on 14/Jun/19 Answered by MJS last updated on 14/Jun/19 $$\mathrm{1} \\ $$$$\mathrm{5}×\mathrm{6}=\mathrm{30} \\ $$$$\mathrm{2} \\ $$$$\mathrm{4}×\mathrm{3}×\mathrm{2}=\mathrm{24} \\ $$…
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Question Number 61860 by Tawa1 last updated on 10/Jun/19 $$\mathrm{simplify}:\:\:\:\:\overset{\mathrm{n}\:+\:\mathrm{1}} {\:}\mathrm{C}_{\mathrm{r}} \:−\:\overset{\mathrm{n}\:−\:\mathrm{1}} {\:}\mathrm{C}_{\mathrm{r}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 61377 by Tawa1 last updated on 01/Jun/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{multinomial}\:\mathrm{coefficient}:\:\:\:\:\:\:\begin{pmatrix}{\:\:\:\:\:\:\:\mathrm{9}}\\{\mathrm{3},\:\mathrm{5},\:\mathrm{1},\:\mathrm{0}}\end{pmatrix} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 192256 by Red1ight last updated on 13/May/23 $$\mathrm{given}\:{f}\left({x}\right)={cx}\left({x}−\mathrm{20}\right)\:\mathrm{and}\:{A}=\left(\mathrm{2},\mathrm{5}\right) \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{nearst}\:\mathrm{point}\:\mathrm{to}\:{A}\:\mathrm{on}\:\mathrm{the}\:\mathrm{graph} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 191934 by Rupesh123 last updated on 04/May/23 Answered by mehdee42 last updated on 04/May/23 $${C}_{\:\mathrm{6}} ^{\:\mathrm{3}} \:×\mathrm{3}!×\mathrm{5}!=\mathrm{14400} \\ $$ Commented by mehdee42 last…