Question Number 142765 by mr W last updated on 05/Jun/21 $${A}\:{class}\:{has}\:\mathrm{13}\:{children}.\:{To}\:{play}\:{a} \\ $$$${game}\:{one}\:{child}\:{is}\:{the}\:{referee}\:{and}\:{the} \\ $$$${other}\:{children}\:{are}\:{divided}\:{in}\:{three}\: \\ $$$${teams}\:{with}\:{four}\:{children}\:{in}\:{each}\:{team}. \\ $$$${In}\:{how}\:{many}\:{ways}\:{can}\:{the}\:{class}\:{play} \\ $$$${the}\:{game}? \\ $$ Commented by…
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Question Number 77199 by Boyka last updated on 04/Jan/20 Commented by Boyka last updated on 04/Jan/20 $$\left.\mathrm{A}\left.\right)\left.\mathrm{4}\left.\mathrm{05}\:\:\:\:\:\:\mathrm{B}\right)\mathrm{404}\:\:\:\:\:\:\:\mathrm{C}\right)\mathrm{403}\:\:\:\:\:\:\:\:\:\mathrm{D}\right)\mathrm{401} \\ $$ Commented by Boyka last updated on…
Question Number 142691 by SLVR last updated on 04/Jun/21 $${The}\:{number}\:{of}\:{distributions}\:{of}\:\mathrm{52} \\ $$$${cards}\:{divided}\:{equally}\:{to}\:\mathrm{4}\:{persons}\:{so} \\ $$$${as}\:{each}\:{gets}\:\mathrm{4}\:{cards}\:{of}\:{same}\:{suit} \\ $$$${taken}\:{away}\:{from}\:\mathrm{3}{suits}\left(\mathrm{4}×\mathrm{3}=\mathrm{12}\right)\wp \\ $$$${remaining}\:{card}\:{from}\:{remaining} \\ $$$$\mathrm{4}\:{th}\:{suit}\:{is} \\ $$ Commented by SLVR…
Question Number 77117 by necxxx last updated on 03/Jan/20 $${Interview}\:{indicates}\:{that}\:{all}\:{the}\:\mathrm{4}\:{maths} \\ $$$${students},\mathrm{5}\:{physics}\:{and}\:\mathrm{7}\:{chemistry} \\ $$$${students}\:{who}\:{applied}\:{for}\:{a}\:{scholarship} \\ $$$${in}\:{their}\:{respective}\:{disciplines}\:{qualified} \\ $$$${for}\:{an}\:{award}.\:{In}\:{how}\:{many}\:{ways}\:{the}\:{aeard} \\ $$$${can}\:{be}\:{made}\:{if}; \\ $$$$\left({i}\right){only}\:{one}\:{scholarship}\:{is}\:{available}\:{in} \\ $$$${each}\:{of}\:{the}\:{disciplines} \\…
Question Number 142630 by iloveisrael last updated on 03/Jun/21 $$\:{Given}\:{f}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{1}+\mathrm{2}^{{x}} } \\ $$$${find}\:{the}\:{value}\:{of} \\ $$$${f}\left(\frac{\mathrm{1}}{\mathrm{2018}}\right)×{f}\left(\frac{\mathrm{3}}{\mathrm{2018}}\right)×{f}\left(\frac{\mathrm{2015}}{\mathrm{2018}}\right)×{f}\left(\frac{\mathrm{2017}}{\mathrm{2018}}\right)=? \\ $$ Commented by MJS_new last updated on 03/Jun/21 $$\mathrm{no}\:“\mathrm{nice}''\:\mathrm{value}…
Question Number 142618 by iloveisrael last updated on 03/Jun/21 $$\:\:\:{In}\:{how}\:{many}\:{ways}\:{can}\:{committee} \\ $$$${of}\:\mathrm{5}\:{be}\:{formed}\:{from}\:{a}\:{group}\: \\ $$$${of}\:\mathrm{11}\:{people}\:{consisting}\:{of}\:\mathrm{4}\:{teachers} \\ $$$${and}\:\mathrm{7}\:{students}\:{if}\:{there}\:{is}\:{no}\: \\ $$$${restriction}\:{in}\:{the}\:{selection}\:? \\ $$$$\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ $$ Commented by som(math1967)…
Question Number 11425 by tawa last updated on 25/Mar/17 Answered by mrW1 last updated on 25/Mar/17 $$\left(\mathrm{1}\right)\:\mathrm{12}{C}\mathrm{5}=\mathrm{792} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{9}{C}\mathrm{5}+\mathrm{3}×\left(\mathrm{9}{C}\mathrm{4}\right)+\mathrm{3}×\left(\mathrm{9}{C}\mathrm{3}\right)=\mathrm{126}+\mathrm{3}×\mathrm{126}+\mathrm{3}×\mathrm{84}=\mathrm{756} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{10}{C}\mathrm{5}+\mathrm{10}{C}\mathrm{3}=\mathrm{252}+\mathrm{120}=\mathrm{372} \\ $$ Commented by…
Question Number 11384 by tawa last updated on 22/Mar/17 $$\mathrm{Out}\:\mathrm{of}\:\mathrm{5}\:\mathrm{accountants}\:\mathrm{and}\:\mathrm{7}\:\mathrm{bankers},\:\mathrm{a}\:\mathrm{committee}\:\mathrm{consisting}\:\mathrm{of}\: \\ $$$$\mathrm{2}\:\mathrm{accountants}\:\mathrm{and}\:\mathrm{3}\:\mathrm{bankers}\:\mathrm{is}\:\mathrm{to}\:\mathrm{be}\:\mathrm{formed}.\:\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{this} \\ $$$$\mathrm{be}\:\mathrm{done}\:\mathrm{if} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{Any}\:\mathrm{acountant}\:\mathrm{and}\:\mathrm{any}\:\mathrm{bankers}\:\mathrm{must}\:\mathrm{be}\:\mathrm{included} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{One}\:\mathrm{particular}\:\mathrm{banker}\:\mathrm{must}\:\mathrm{be}\:\mathrm{included} \\ $$$$\left(\mathrm{c}\right)\:\mathrm{2}\:\mathrm{accountant}\:\mathrm{cannot}\:\mathrm{be}\:\mathrm{in}\:\mathrm{the}\:\mathrm{committee} \\ $$ Answered by sandy_suhendra…
Question Number 11382 by tawa last updated on 22/Mar/17 $$\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{24}\:\mathrm{different}\:\mathrm{articles}\:\mathrm{be}\:\mathrm{divided}\:\mathrm{into}\:\mathrm{groups}\:\mathrm{of} \\ $$$$\mathrm{12},\:\mathrm{8}\:\mathrm{and}\:\mathrm{4}\:\mathrm{articles}\:\mathrm{respectively} \\ $$ Commented by sandy_suhendra last updated on 23/Mar/17 $$\mathrm{24C12}\:×\:\mathrm{12C8}\:×\:\mathrm{4C4} \\ $$ Commented…