Question Number 199480 by Abdullahrussell last updated on 04/Nov/23 Commented by mr W last updated on 04/Nov/23 $$=\frac{\mathrm{sin}\:\theta+\mathrm{sin}\:\mathrm{50}°+\mathrm{1}+\mathrm{sin}\:\mathrm{50}°}{\mathrm{cos}\:\theta+\mathrm{cos}\:\mathrm{50}°+\mathrm{0}−\mathrm{cos}\:\mathrm{50}°} \\ $$$$=\frac{\mathrm{sin}\:\theta+\mathrm{1}+\mathrm{2}\:\mathrm{sin}\:\mathrm{50}°}{\mathrm{cos}\:\theta} \\ $$ Terms of Service…
Question Number 199424 by cortano12 last updated on 03/Nov/23 $$\:\:\:\boldsymbol{{x}} \\ $$ Answered by Frix last updated on 04/Nov/23 $${f}\left({x}\right)=\frac{\mathrm{cos}\:{x}}{\mathrm{3}}\left(\mathrm{6sin}^{\mathrm{3}} \:{x}\:−\mathrm{4sin}^{\mathrm{2}} \:{x}\:+\mathrm{1}\right) \\ $$$${f}'\left({x}\right)=−\mathrm{sin}\:{x}\:\left(\mathrm{1}−\mathrm{2sin}\:{x}\right)\left(\mathrm{3}−\mathrm{4sin}^{\mathrm{2}} \:{x}\right)…
Question Number 199374 by cortano12 last updated on 02/Nov/23 Commented by cortano12 last updated on 02/Nov/23 $$\mathrm{prove}\:\mathrm{that}\:\:\cancel{\boldsymbol{{B}}} \\ $$ Commented by MathematicalUser2357 last updated on…
Question Number 199371 by cortano12 last updated on 02/Nov/23 Commented by Frix last updated on 02/Nov/23 $$\frac{\mathrm{1}}{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 199177 by cortano12 last updated on 29/Oct/23 Commented by yaslm last updated on 31/Oct/23 the name of book pleas Answered by a.lgnaoui last updated on 29/Oct/23 $$\mathrm{58}°…
Question Number 199005 by Safojon last updated on 26/Oct/23 Commented by mr W last updated on 29/Oct/23 $${i}\:{got}\:\frac{\mathrm{1}}{\mathrm{tan}\:\mathrm{1}°} \\ $$$${solution}\:{see}\:{Q}\mathrm{199226} \\ $$ Commented by Rasheed.Sindhi…
Question Number 198907 by a.lgnaoui last updated on 25/Oct/23 $$\mathrm{find}\:\mathrm{the}\:\mathrm{Area}\:\mathrm{betwen}\:\mathrm{Circle}\:\mathrm{1}\:\mathrm{and}\: \\ $$$$\mathrm{Circle2}. \\ $$ Commented by a.lgnaoui last updated on 25/Oct/23 Commented by Rasheed.Sindhi last…
Question Number 198900 by Safojon last updated on 25/Oct/23 $$\frac{\mathrm{2}{sin}\mathrm{2}°+\mathrm{4}{sin}\mathrm{4}°+…+\mathrm{180}{sin}\mathrm{180}°}{\mathrm{90}}=? \\ $$$${calculate}.{help}\:{me}\:{pleas}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198815 by a.lgnaoui last updated on 24/Oct/23 $$\mathrm{Determiner}\:\boldsymbol{\mathrm{x}} \\ $$ Commented by a.lgnaoui last updated on 24/Oct/23 Commented by cherokeesay last updated on…
Question Number 198761 by ajfour last updated on 24/Oct/23 Terms of Service Privacy Policy Contact: info@tinkutara.com