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Category: Trigonometry

Question-193205

Question Number 193205 by Rupesh123 last updated on 07/Jun/23 Commented by a.lgnaoui last updated on 08/Jun/23 Answered by a.lgnaoui last updated on 07/Jun/23 $$\bigtriangleup\boldsymbol{\mathrm{ABC}}\:\:\:\:\measuredangle\boldsymbol{\mathrm{ABC}}=\boldsymbol{\alpha}\:\:\:\measuredangle\boldsymbol{\mathrm{ACB}}=\boldsymbol{\beta} \\…

Question-193203

Question Number 193203 by Mingma last updated on 07/Jun/23 Answered by som(math1967) last updated on 07/Jun/23 $$\frac{{DB}}{{DC}}=\frac{{BE}}{{EC}}\:\:\left[{DE}\:{is}\:{bisector}\:{of}\angle{BDC}\right] \\ $$$$\:\frac{{DB}}{{DC}}=\frac{\mathrm{1}}{\mathrm{2}}\: \\ $$$${Sin}\angle{DCB}={Sin}\mathrm{30} \\ $$$$\angle{DCB}=\mathrm{30} \\ $$$$\:\frac{{DB}}{{BC}}={tan}\mathrm{30}…

Question-130632

Question Number 130632 by bramlexs22 last updated on 27/Jan/21 Answered by EDWIN88 last updated on 27/Jan/21 $$\mathrm{cos}\:\mathrm{4095}°\:=\:\mathrm{cos}\:\left(\mathrm{360}°×\mathrm{11}+\mathrm{135}°\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:−\frac{\sqrt{\mathrm{2}}}{\mathrm{2}} \\ $$$${then}\:\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{cos}\:\mathrm{4095}°\right)=\mathrm{sin}\:\left(−\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\right) \\ $$$$\:=−\frac{\pi}{\mathrm{4}} \\…

Prove-the-identity-tan-1-x-cot-1-x-pi-2-

Question Number 130589 by bramlexs22 last updated on 27/Jan/21 $$\:\mathrm{Prove}\:\mathrm{the}\:\mathrm{identity}\:\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{x}\right)+\mathrm{cot}^{−\mathrm{1}} \left(\mathrm{x}\right)=\pi/\mathrm{2} \\ $$ Answered by EDWIN88 last updated on 27/Jan/21 $$\:{If}\:{f}\left({x}\right)=\mathrm{tan}^{−\mathrm{1}} \left({x}\right)+\mathrm{cot}^{−\mathrm{1}} \left({x}\right) \\…

If-a-1-a-2-a-3-are-in-AP-and-d-is-the-common-difference-then-tan-1-d-1-a-1-a-2-tan-1-d-1-a-2-a-3-

Question Number 130581 by bramlexs22 last updated on 27/Jan/21 $$\mathrm{If}\:\mathrm{a}_{\mathrm{1}} ,\mathrm{a}_{\mathrm{2}} \:,\mathrm{a}_{\mathrm{3}} \:\mathrm{are}\:\mathrm{in}\:\mathrm{AP}\:\mathrm{and}\:\mathrm{d}\:\mathrm{is}\:\mathrm{the}\:\mathrm{common} \\ $$$$\mathrm{difference}\:\mathrm{then}\:\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{d}}{\mathrm{1}+\mathrm{a}_{\mathrm{1}} \mathrm{a}_{\mathrm{2}} }\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{d}}{\mathrm{1}+\mathrm{a}_{\mathrm{2}} \mathrm{a}_{\mathrm{3}} }\right)=? \\ $$ Answered by…