Question Number 117960 by andilizhaa last updated on 14/Oct/20 Answered by mathmax by abdo last updated on 14/Oct/20 $$\mathrm{if}\:\mathrm{you}\:\mathrm{want}\:\mathrm{derivative}\:\mathrm{we}\:\mathrm{have} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{5x}^{\mathrm{4}} \:+\mathrm{x}\sqrt{\mathrm{x}}+\frac{\mathrm{6}}{\:\sqrt{\mathrm{x}}}\:−\mathrm{sinx}−\mathrm{2cosx}\:\Rightarrow \\ $$$$\mathrm{f}\left(\mathrm{x}\right)\:=\mathrm{5x}^{\mathrm{4}} \:+\mathrm{x}^{\frac{\mathrm{3}}{\mathrm{2}}}…
Question Number 117943 by bemath last updated on 14/Oct/20 $$\mathrm{solve}\:\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{sin}\:\mathrm{112}°}{\mathrm{16sin}\:\mathrm{7}°}\:−\mathrm{cos}\:\mathrm{7}°.\mathrm{cos}\:\mathrm{14}°.\mathrm{cos}\:\mathrm{28}°.\mathrm{cos}\:\mathrm{56}°\:=? \\ $$ Answered by TANMAY PANACEA last updated on 14/Oct/20 $${p}={cos}\mathrm{7}{cos}\mathrm{14}{cos}\mathrm{28}{cos}\mathrm{56} \\ $$$$\mathrm{2}{psin}\mathrm{7}={sin}\mathrm{14}{cos}\mathrm{14}{cos}\mathrm{28}{cos}\mathrm{56} \\ $$$$\mathrm{2}^{\mathrm{2}}…
Question Number 117938 by bemath last updated on 14/Oct/20 $$\left(\mathrm{1}\right)\:\frac{\mid{a}^{\mathrm{2}} −\mathrm{16}\mid}{\mathrm{4}−{a}}\:−\:\frac{\mid{a}^{\mathrm{2}} −\mathrm{9}\mid}{\mathrm{3}+{a}}\:−\:\frac{\mid\mathrm{4}−{a}^{\mathrm{2}} \mid}{\mathrm{2}−{a}}\:=? \\ $$$$\left(\mathrm{2}\right)\left(\frac{\mid\mathrm{x}\mid\:+\mathrm{x}\:}{\mathrm{x}−\mathrm{1}}\right)^{\mathrm{2}} −\frac{\mathrm{14x}}{\mathrm{x}−\mathrm{1}}\:+\:\mathrm{12}\:=\:\mathrm{0} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{log}\:_{\mathrm{4}} \left(\mathrm{2}^{\mathrm{2x}} −\sqrt{\mathrm{3}}\:\mathrm{cos}\:\mathrm{x}−\mathrm{6sin}\:^{\mathrm{2}} \mathrm{x}\:\right)\:=\:\mathrm{x} \\ $$$$\mathrm{where}\:\frac{\mathrm{5}\pi}{\mathrm{2}}\:\leqslant\mathrm{x}\leqslant\mathrm{4}\pi \\ $$$$\left(\mathrm{4}\right)\:\frac{\mathrm{2cos}\:^{\mathrm{2}}…
Question Number 117926 by bemath last updated on 14/Oct/20 $$\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{2x}}{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\right)\:+\:\mathrm{cot}^{−\mathrm{1}} \left(\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2x}}\right)\:=\frac{\mathrm{2}\pi}{\mathrm{3}} \\ $$$$\left(\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{x}\right)\right)^{\mathrm{2}} +\left(\mathrm{cot}^{−\mathrm{1}} \left(\mathrm{x}\right)\right)^{\mathrm{2}} =\frac{\mathrm{5}\pi}{\mathrm{8}} \\ $$$$ \\ $$ Answered…
Question Number 117852 by bemath last updated on 14/Oct/20 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\left(\mathrm{1}\right)\left(\mathrm{tan}\:\frac{\mathrm{7}\pi}{\mathrm{24}}+\mathrm{tan}\:\frac{\mathrm{5}\pi}{\mathrm{24}}\right).\mathrm{cos}\:\frac{\pi}{\mathrm{12}}\:+\:\mathrm{2}\:. \\ $$$$\left(\mathrm{2}\right)\:\sqrt[{\mathrm{4}\:}]{\frac{\mathrm{9}−\mathrm{4}\sqrt{\mathrm{5}}}{\mathrm{5x}}}\:.\left(\mathrm{5}\sqrt{\mathrm{x}}\:+\sqrt{\mathrm{20x}}\:\right)^{\mathrm{0}.\mathrm{5}} .\:\mathrm{2}^{−\mathrm{1}} \:=\:? \\ $$ Answered by bobhans last updated on 14/Oct/20…
Question Number 52082 by ajfour last updated on 03/Jan/19 Commented by ajfour last updated on 03/Jan/19 $${Express}\:\boldsymbol{\alpha}\:{in}\:{terms}\:{of}\:\boldsymbol{\theta}. \\ $$ Answered by mr W last updated…
Question Number 117606 by TANMAY PANACEA last updated on 12/Oct/20 $${find} \\ $$$${sina}+{sin}\left({a}+{b}\right)+{sin}\left({a}+\mathrm{2}{b}\right)++..+{sin}\left\{{a}+\left({n}−\mathrm{1}\right){b}\right\} \\ $$ Answered by Dwaipayan Shikari last updated on 12/Oct/20 $$\frac{\mathrm{1}}{\mathrm{2}{sin}\frac{{b}}{\mathrm{2}}}\left(\mathrm{2}{sinasin}\frac{{b}}{\mathrm{2}}+\mathrm{2}{sin}\left({a}+{b}\right){sin}\frac{{b}}{\mathrm{2}}+…..\mathrm{2}{sin}\left({a}+\left({n}−\mathrm{1}\right){b}\right){sin}\frac{{b}}{\mathrm{2}}\right) \\…
Question Number 117552 by sandy_delta last updated on 12/Oct/20 $$\mathrm{please}\:\mathrm{help} \\ $$$$\mathrm{cos}\:\frac{\pi}{\mathrm{7}}\:.\:\mathrm{cos}\:\frac{\mathrm{2}\pi}{\mathrm{7}}\:.\:\mathrm{cos}\:\frac{\mathrm{4}\pi}{\mathrm{7}}\:=\:? \\ $$ Commented by TANMAY PANACEA last updated on 12/Oct/20 $${find}\:{cos}\frac{\pi}{\mathrm{7}}+{cos}\frac{\mathrm{2}\pi}{\mathrm{7}}+{cos}\frac{\mathrm{4}\pi}{\mathrm{7}}\:\:{pls} \\ $$…
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Question Number 117497 by bemath last updated on 12/Oct/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{set}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{equation}\:\mathrm{sec}\:\mathrm{3}\theta\:=\:\mathrm{sec}\:\theta \\ $$ Answered by Dwaipayan Shikari last updated on 12/Oct/20 $$\frac{\mathrm{1}}{{cos}\mathrm{3}\theta}=\frac{\mathrm{1}}{{cos}\theta} \\ $$$${cos}\mathrm{3}\theta={cos}\theta…