Question Number 126572 by sdfg last updated on 22/Dec/20 Answered by liberty last updated on 22/Dec/20 $$\:\mid\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\mid^{\mathrm{2}} =\:\mid\overset{\rightarrow} {{a}}\mid^{\mathrm{2}} +\mid\overset{\rightarrow} {{b}}\mid^{\mathrm{2}} +\mathrm{2}\mid\overset{\rightarrow} {{a}}\mid\mid\overset{\rightarrow}…
Question Number 192024 by Shlock last updated on 05/May/23 Answered by a.lgnaoui last updated on 05/May/23 $$\boldsymbol{\mathrm{The}}\:\boldsymbol{\mathrm{shaded}}\:\boldsymbol{\mathrm{Area}}\:\boldsymbol{\mathrm{betwen}} \\ $$$$\left[\boldsymbol{\mathrm{y}}=\mathrm{0},\boldsymbol{\mathrm{y}}=\sqrt{\mathrm{25}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} }\:−\mathrm{3}\:\:;\boldsymbol{\mathrm{y}}=\sqrt{\mathrm{4}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} \:}\right] \\ $$$$\int_{\mathrm{0}} ^{\mathrm{4}} \left(\sqrt{\mathrm{25}−\boldsymbol{\mathrm{x}}^{\mathrm{2}}…
Question Number 192023 by Shlock last updated on 05/May/23 Answered by a.lgnaoui last updated on 06/May/23 $$\boldsymbol{\mathrm{graphe}}\left(\mathrm{1}\right) \\ $$$$\boldsymbol{\mathrm{y}}\:_{\mathrm{1}} \:\:\:\boldsymbol{\mathrm{represente}}\:\boldsymbol{\mathrm{raphe}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{quart}}\:\boldsymbol{\mathrm{circle}}\:\left(\boldsymbol{\mathrm{radius}}\:\mathrm{2}\right)\:\boldsymbol{\mathrm{centre}}\left(\mathrm{0},\mathrm{0}\right) \\ $$$$\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{y}}^{\mathrm{2}} =\mathrm{4}\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}<\boldsymbol{\mathrm{x}}<\mathrm{2}\:\:\:\boldsymbol{\mathrm{y}}_{\mathrm{1}} =\sqrt{\mathrm{4}−\boldsymbol{\mathrm{x}}^{\mathrm{2}}…
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Question Number 125672 by mathocean1 last updated on 12/Dec/20 $${N}={x}\mathrm{32}{y}\:{in}\:{base}\:\mathrm{10}.\: \\ $$$${N}\equiv\mathrm{0}\left[\mathrm{3}\right]\:{and}\:{N}\equiv\mathrm{0}\left[\mathrm{4}\right]. \\ $$$${N}>\mathrm{8329} \\ $$$${N}\:{has}\:{four}\:{digits}. \\ $$$${Determinate}\:{N}. \\ $$ Answered by JDamian last updated…
Question Number 191104 by Mingma last updated on 18/Apr/23 Answered by witcher3 last updated on 18/Apr/23 $$\mathrm{n}=\mathrm{m}=\mathrm{0}\Rightarrow\sqrt{\mathrm{0}}=\mathrm{0}\in\mathrm{Q} \\ $$ Commented by mehdee42 last updated on…
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