Question Number 209529 by mr W last updated on 13/Jul/24 Commented by mr W last updated on 13/Jul/24 $${find}\:{u}_{{min}} \:{such}\:{that}\:{the}\:{ball}\:{can}\:{fly} \\ $$$${out}\:{of}\:{the}\:{well}. \\ $$$$\left({collisions}\:{with}\:{the}\:{wall}\:{are}\:{elastic}\right)\: \\…
Question Number 209358 by peter frank last updated on 08/Jul/24 Commented by mr W last updated on 08/Jul/24 $${if}\:{the}\:{bowl}\:{is}\:{smooth},\:{why}\:{should}\:{the}\: \\ $$$${small}\:{block}\:{rotate}\:{with}\:{the}\:{bowl}\:{and} \\ $$$${not}\:{fall}\:{to}\:{the}\:{middle}\:{of}\:{the}\:{bowl}? \\ $$…
Question Number 209359 by peter frank last updated on 08/Jul/24 Commented by mr W last updated on 08/Jul/24 $$“{with}\:{a}\:{vertical}\:{velocity}\:{v}''\:{should}\:{be} \\ $$$$“{with}\:{a}\:{velocity}\:{v}''. \\ $$$${answer}\:\frac{{v}^{\mathrm{2}} −{g}^{\mathrm{2}} {x}^{\mathrm{2}}…
Question Number 209352 by Spillover last updated on 07/Jul/24 Answered by mr W last updated on 08/Jul/24 $${L}={mr}^{\mathrm{2}} \omega={constant} \\ $$$$\omega_{{max}} =\frac{{L}}{{mr}_{{min}} ^{\mathrm{2}} }=\frac{{L}}{{m}\left({a}−{c}\right)^{\mathrm{2}} }…
Question Number 209161 by Spillover last updated on 02/Jul/24 Commented by klipto last updated on 03/Jul/24 $$ \\ $$$$\boldsymbol{\mathrm{F}}_{\boldsymbol{\mathrm{net}}} =−\left(\boldsymbol{\mathrm{F}}_{\mathrm{g}} +\boldsymbol{\mathrm{P}}\right) \\ $$$$\boldsymbol{\mathrm{ma}}=−\left(\boldsymbol{\mathrm{mg}}+\mathrm{0}.\mathrm{2}\boldsymbol{\mathrm{v}}^{\mathrm{2}} \right) \\…
Question Number 209125 by Spillover last updated on 02/Jul/24 Answered by mr W last updated on 03/Jul/24 Commented by mr W last updated on 05/Jul/24…
Question Number 209124 by Spillover last updated on 02/Jul/24 Answered by Spillover last updated on 02/Jul/24 Answered by Spillover last updated on 02/Jul/24 Answered by…
Question Number 209122 by Spillover last updated on 02/Jul/24 Answered by Spillover last updated on 02/Jul/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 209121 by Spillover last updated on 02/Jul/24 Answered by Spillover last updated on 04/Jul/24 $${r}={r}_{\mathrm{0}} {e}^{{k}\theta} \\ $$$${In}\:{central}\:{force}\:{field}, \\ $$$${the}\:{angular}\:{momentum}\:{L}\:{is}\:{conserved} \\ $$$${L}={mr}^{\mathrm{2}} \frac{{d}\theta}{{dt}}\:\:\:\:\:{where}\:{m}={mass}\:{of}\:{the}\:{particle}…
Question Number 209098 by Spillover last updated on 01/Jul/24 Answered by A5T last updated on 02/Jul/24 $$\mathrm{4}=\frac{{v}_{\mathrm{0}} ^{\mathrm{2}} {sin}^{\mathrm{2}} \theta}{\mathrm{2}{g}}\Rightarrow{sin}\theta=\frac{\sqrt{\mathrm{8}{g}}}{{v}_{\mathrm{0}} } \\ $$$${R}={v}_{\mathrm{0}} {cos}\theta×\mathrm{2}{t}={v}_{\mathrm{0}} \sqrt{\mathrm{1}−\frac{\mathrm{8}{g}}{{v}_{\mathrm{0}}…