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Category: Oscillation and Waves

we-know-the-equation-of-a-simple-harmonic-wave-going-to-left-to-right-is-y-asin-2pi-vt-x-if-we-put-t-0-and-x-0-we-get-y-0-and-if-we-put-t-0-and-x-0-25-we-get-y-a-But-How-could-thi

Question Number 152346 by n0y0n last updated on 27/Aug/21 $$\mathrm{we}\:\mathrm{know}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{a}\:\mathrm{simple}\:\mathrm{harmonic}\:\mathrm{wave} \\ $$$$\mathrm{going}\:\mathrm{to}\:\mathrm{left}\:\mathrm{to}\:\mathrm{right}\:\mathrm{is}, \\ $$$$\:\mathrm{y}=\mathrm{asin}\frac{\mathrm{2}\pi}{\lambda}\left(\mathrm{vt}−\mathrm{x}\right)\: \\ $$$$\:\mathrm{if}\:\mathrm{we}\:\mathrm{put}\:\mathrm{t}=\mathrm{0}\:\mathrm{and}\:\mathrm{x}=\mathrm{0}\:, \\ $$$$\mathrm{we}\:\mathrm{get}\:\mathrm{y}=\mathrm{0} \\ $$$$\mathrm{and}\:\mathrm{if}\:\mathrm{we}\:\mathrm{put}\:\mathrm{t}=\mathrm{0}\:\mathrm{and}\:\mathrm{x}=\mathrm{0}.\mathrm{25}\lambda\:, \\ $$$$\mathrm{we}\:\mathrm{get}\:\mathrm{y}=\:\mathrm{a}\:\:\:!! \\ $$$$\mathrm{But}\:\mathrm{How}\:\:\mathrm{could}\:\mathrm{this}\:\mathrm{be}\:\mathrm{possible}? \\…

Question-82768

Question Number 82768 by Lontum Hans last updated on 24/Feb/20 Commented by mr W last updated on 24/Feb/20 $${if}\:{there}\:{is}\:{no}\:{gravity}\:{force},\:{the}\:{pendulum} \\ $$$${will}\:{not}\:{move}\:{at}\:{all},\:{i}.{e}.\:{its}\:{period}\:{is} \\ $$$$\infty.\:{so}\:{we}\:{know}:\:{the}\:{weaker}\:{the}\:{gravity}, \\ $$$${the}\:{slower}\:{the}\:{pendulum}\:{or}\:{the}…

Ocean-waves-are-observed-to-travel-along-the-water-surface-during-a-developing-storm-A-Coast-Guard-weather-station-observes-that-there-is-a-vertical-distance-from-high-point-to-low-point-of-4-6-m

Question Number 140870 by jlewis last updated on 13/May/21 $${O}\mathrm{cean}\:\mathrm{waves}\:\mathrm{are}\:\mathrm{observed}\:\mathrm{to} \\ $$$$\mathrm{travel}\:\mathrm{along}\:\mathrm{the}\:\mathrm{water}\:\mathrm{surface} \\ $$$$\:\mathrm{during}\:\mathrm{a}\:\mathrm{developing}\:\mathrm{storm}. \\ $$$$\mathrm{A}\:\mathrm{Coast}\:\mathrm{Guard}\:\mathrm{weather}\:\mathrm{station} \\ $$$$\:\mathrm{observes}\:\mathrm{that}\:\mathrm{there}\:\mathrm{is}\:\mathrm{a}\:\mathrm{vertical}\: \\ $$$$\mathrm{distance}\:\mathrm{from}\:\mathrm{high}\:\mathrm{point}\:\mathrm{to}\:\mathrm{low} \\ $$$$\:\mathrm{point}\:\mathrm{of}\:\mathrm{4}.\mathrm{6}\:\mathrm{meters}\:\mathrm{and}\:\mathrm{horizontal} \\ $$$$\mathrm{distance}\:\mathrm{of}\:\mathrm{8}.\mathrm{6}\:\mathrm{meters}\:\mathrm{between}\: \\…

Question-132264

Question Number 132264 by Salman_Abir last updated on 12/Feb/21 Answered by physicstutes last updated on 12/Feb/21 $$\mathrm{frequency}\:=\:\mathrm{5}\:\mathrm{Hz} \\ $$$$\:\:\omega\:=\:\mathrm{2}\pi{f} \\ $$$$\Rightarrow\:\omega\:=\:\frac{\mathrm{2}\pi}{\mathrm{5}}\:\mathrm{rad}/\mathrm{s} \\ $$$$\:\mathrm{T}\:=\:\frac{\mathrm{1}}{\mathrm{5}}\:\mathrm{s} \\ $$…

Question-132265

Question Number 132265 by Salman_Abir last updated on 12/Feb/21 Answered by physicstutes last updated on 12/Feb/21 $$\mathrm{m}\:=\:\mathrm{4}\:\mathrm{kg},\:{k}\:=\:\mathrm{100}\:\mathrm{Nm}^{−\mathrm{1}} \\ $$$$\:{T}\:=\:\mathrm{2}\pi\sqrt{\frac{{m}}{{k}}}\:=\:\mathrm{2}\pi\sqrt{\frac{\mathrm{4}}{\mathrm{100}}}\: \\ $$$$\Rightarrow\:{T}\:=\:\frac{\mathrm{4}\pi}{\mathrm{25}}\:\mathrm{s} \\ $$$${f}\:=\:\frac{\mathrm{1}}{{T}}\:=\:\frac{\mathrm{25}}{\mathrm{4}\pi}\:\mathrm{Hz} \\ $$$${T}\:=\:\frac{\mathrm{2}\pi}{\omega}\:\Rightarrow\:\omega\:=\:\frac{\mathrm{2}\pi}{{T}}\:\:=\:\mathrm{2}\pi\:.\:\frac{\mathrm{25}}{\mathrm{4}\pi}\:=\:\frac{\mathrm{25}}{\mathrm{2}}\:\mathrm{rad}/\mathrm{s}…