Question Number 133669 by Study last updated on 23/Feb/21
![(1/3)y−5{−2[6(y−(1/3)−y]}÷3=?](https://www.tinkutara.com/question/Q133669.png)
$$\frac{\mathrm{1}}{\mathrm{3}}{y}−\mathrm{5}\left\{−\mathrm{2}\left[\mathrm{6}\left({y}−\frac{\mathrm{1}}{\mathrm{3}}−{y}\right]\right\}\boldsymbol{\div}\mathrm{3}=?\right. \\ $$
Commented by Ar Brandon last updated on 23/Feb/21
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Commented by Study last updated on 23/Feb/21
$${if}\:{you}\:{can}\:{solve}\:{then}\:{solve}\:{i}'{m}\:{not}\:{need} \\ $$$${to}\:{extra}\:{speaking}. \\ $$
Answered by Raxreedoroid last updated on 23/Feb/21
![you missed a bracket I will assume the bracket′s place is like the following: (1/3)y−5{−2[6(y−(1/3))−y]}÷3=? ((y−5(−2(6y−2−y)))/3)=? ((y−5(−10y+4))/3)=? ((y+50y−20)/3)=? ((51y−20)/3)=17y−((20)/3)](https://www.tinkutara.com/question/Q133739.png)
$$\mathrm{you}\:\mathrm{missed}\:\mathrm{a}\:\mathrm{bracket} \\ $$$$\mathrm{I}\:\mathrm{will}\:\mathrm{assume}\:\mathrm{the}\:\mathrm{bracket}'\mathrm{s}\:\mathrm{place}\:\mathrm{is}\:\mathrm{like}\:\mathrm{the}\:\mathrm{following}: \\ $$$$\frac{\mathrm{1}}{\mathrm{3}}{y}−\mathrm{5}\left\{−\mathrm{2}\left[\mathrm{6}\left({y}−\frac{\mathrm{1}}{\mathrm{3}}\right)−{y}\right]\right\}\boldsymbol{\div}\mathrm{3}=? \\ $$$$\frac{{y}−\mathrm{5}\left(−\mathrm{2}\left(\mathrm{6}{y}−\mathrm{2}−{y}\right)\right)}{\mathrm{3}}=? \\ $$$$\frac{{y}−\mathrm{5}\left(−\mathrm{10}{y}+\mathrm{4}\right)}{\mathrm{3}}=? \\ $$$$\frac{{y}+\mathrm{50}{y}−\mathrm{20}}{\mathrm{3}}=? \\ $$$$\frac{\mathrm{51}{y}−\mathrm{20}}{\mathrm{3}}=\mathrm{17}{y}−\frac{\mathrm{20}}{\mathrm{3}} \\ $$
Commented by Study last updated on 24/Feb/21
$${thanks}\:{sir} \\ $$