# 1-3-y-5-2-6-y-1-3-y-3-

Question Number 133669 by Study last updated on 23/Feb/21
$$\frac{\mathrm{1}}{\mathrm{3}}{y}−\mathrm{5}\left\{−\mathrm{2}\left[\mathrm{6}\left({y}−\frac{\mathrm{1}}{\mathrm{3}}−{y}\right]\right\}\boldsymbol{\div}\mathrm{3}=?\right. \\$$
Commented by Ar Brandon last updated on 23/Feb/21
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Commented by Study last updated on 23/Feb/21
$${if}\:{you}\:{can}\:{solve}\:{then}\:{solve}\:{i}'{m}\:{not}\:{need} \\$$$${to}\:{extra}\:{speaking}. \\$$
Answered by Raxreedoroid last updated on 23/Feb/21
$$\mathrm{you}\:\mathrm{missed}\:\mathrm{a}\:\mathrm{bracket} \\$$$$\mathrm{I}\:\mathrm{will}\:\mathrm{assume}\:\mathrm{the}\:\mathrm{bracket}'\mathrm{s}\:\mathrm{place}\:\mathrm{is}\:\mathrm{like}\:\mathrm{the}\:\mathrm{following}: \\$$$$\frac{\mathrm{1}}{\mathrm{3}}{y}−\mathrm{5}\left\{−\mathrm{2}\left[\mathrm{6}\left({y}−\frac{\mathrm{1}}{\mathrm{3}}\right)−{y}\right]\right\}\boldsymbol{\div}\mathrm{3}=? \\$$$$\frac{{y}−\mathrm{5}\left(−\mathrm{2}\left(\mathrm{6}{y}−\mathrm{2}−{y}\right)\right)}{\mathrm{3}}=? \\$$$$\frac{{y}−\mathrm{5}\left(−\mathrm{10}{y}+\mathrm{4}\right)}{\mathrm{3}}=? \\$$$$\frac{{y}+\mathrm{50}{y}−\mathrm{20}}{\mathrm{3}}=? \\$$$$\frac{\mathrm{51}{y}−\mathrm{20}}{\mathrm{3}}=\mathrm{17}{y}−\frac{\mathrm{20}}{\mathrm{3}} \\$$
Commented by Study last updated on 24/Feb/21
$${thanks}\:{sir} \\$$