Question Number 588 by shaleen last updated on 03/Feb/15
![(a+b=10) (a+c=24) (b+c=20) find a b c](https://www.tinkutara.com/question/Q588.png)
$$\left({a}+{b}=\mathrm{10}\right)\:\left({a}+{c}=\mathrm{24}\right)\:\left({b}+{c}=\mathrm{20}\right) \\ $$$${find}\:{a}\:{b}\:{c} \\ $$
Answered by prakash jain last updated on 03/Feb/15
![a+b=10⇒b=10−a a+c=24⇒c=24−a b+c=20 ⇒10−a+24−a=20 ⇒a=7 b=10−a=10−7=3 c=24−a=24−7=17 Solution a=7, b=3, c=17](https://www.tinkutara.com/question/Q589.png)
$${a}+{b}=\mathrm{10}\Rightarrow{b}=\mathrm{10}−{a} \\ $$$${a}+{c}=\mathrm{24}\Rightarrow{c}=\mathrm{24}−{a} \\ $$$$ \\ $$$${b}+{c}=\mathrm{20} \\ $$$$\Rightarrow\mathrm{10}−{a}+\mathrm{24}−{a}=\mathrm{20} \\ $$$$\Rightarrow{a}=\mathrm{7} \\ $$$${b}=\mathrm{10}−{a}=\mathrm{10}−\mathrm{7}=\mathrm{3} \\ $$$${c}=\mathrm{24}−{a}=\mathrm{24}−\mathrm{7}=\mathrm{17} \\ $$$$\mathrm{Solution}\:{a}=\mathrm{7},\:{b}=\mathrm{3},\:{c}=\mathrm{17} \\ $$