Question Number 3517 by Tinku Tara last updated on 14/Dec/15
$$\mathrm{App}\:\mathrm{has}\:\mathrm{been}\:\mathrm{updated}\:\mathrm{today}\:\mathrm{to}\:\mathrm{fix} \\$$$$\mathrm{intermittent}\:\mathrm{scrolling}\:\mathrm{problem}\:\mathrm{while} \\$$$$\mathrm{answering}\:\mathrm{or}\:\mathrm{commenting}. \\$$$$\mathrm{Filup},\:\mathrm{please}\:\mathrm{let}\:\mathrm{us}\:\mathrm{know}\:\mathrm{if}\:\mathrm{this}\:\mathrm{addresses} \\$$$$\mathrm{your}\:\mathrm{concerns}. \\$$
Commented by Filup last updated on 14/Dec/15
$$\mathrm{Its}\:\mathrm{fixed}!\:{Yahoo}\sim! \\$$
Commented by Rasheed Soomro last updated on 16/Dec/15
$${When}\:{we}\:{are}\:{trying}\:{to}\:{change}\:{colour}\:{of} \\$$$${already}\:{written}\:\boldsymbol{{compound}}\:\boldsymbol{{expression}} \\$$$$\left({which}\:{consists}\:{of}\:{some}\:\boldsymbol{{subexpression}}/\boldsymbol{{s}}\right) \\$$$${the}\:{colour}\:{changing}\:{is}\:\boldsymbol{{partialy}}.{For}\:{example} \\$$$$\frac{{a}}{{b}}\rightarrow\frac{{a}}{{b}}\:,\:\sqrt{{ax}^{\mathrm{2}} +{b}}\rightarrow\sqrt{{ax}^{\mathrm{2}} +{b}}\:\:,{ax}^{\mathrm{2}} +{b}\rightarrow{ax}^{\mathrm{2}} +{b}\:{etc}. \\$$$${A}\:{more}\:{complicated}\:{expression}\:{requires}\:{more} \\$$$${steps}\:{for}\:{changing}\:{color}.\:{Pl}\:{fix}\:{the}\:{problem}. \\$$
Commented by Tinku Tara last updated on 16/Dec/15
$$\mathrm{understood}.\:\mathrm{will}\:\mathrm{look}\:\mathrm{into}\:\mathrm{it}. \\$$
Commented by Tinku Tara last updated on 17/Dec/15
$$\mathrm{This}\:\mathrm{issue}\:\mathrm{has}\:\mathrm{been}\:\mathrm{addressed}. \\$$