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# calculate-0-arctan-3x-arctan-2x-x-dx-

Question Number 68240 by mathmax by abdo last updated on 07/Sep/19
$${calculate}\:\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left(\mathrm{3}{x}\right)−{arctan}\left(\mathrm{2}{x}\right)}{{x}}{dx} \\$$
Commented by mathmax by abdo last updated on 08/Sep/19
$${let}\:{I}\:=\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left(\mathrm{3}{x}\right)−{arctan}\left(\mathrm{2}{x}\right)}{{x}}{dx}\:{and} \\$$$${I}\left(\xi\right)\:=\int_{\mathrm{0}} ^{\xi} \:\frac{{arctan}\left(\mathrm{3}{x}\right)−{arctan}\left(\mathrm{2}{x}\right)}{{x}}{dx}\:{we}\:{have}\:{lim}_{\xi\rightarrow+\infty} {I}\left(\xi\right)={I} \\$$$${I}\left(\xi\right)\:=\int_{\mathrm{0}} ^{\xi} \:\frac{{arctan}\left(\mathrm{3}{x}\right)}{{x}}{dx}−\int_{\mathrm{0}} ^{\xi} \:\frac{{arctan}\left(\mathrm{2}{x}\right)}{{x}}{dx}\:{but} \\$$$$\int_{\mathrm{0}} ^{\xi} \:\frac{{arctan}\left(\mathrm{3}{x}\right)}{{x}}{dx}\:=_{\mathrm{3}{x}={t}} \:\:\:\int_{\mathrm{0}} ^{\mathrm{3}\xi} \:\frac{{arctan}\left({t}\right)}{\frac{{t}}{\mathrm{3}}}\frac{{dt}}{\mathrm{3}}\:=\int_{\mathrm{0}} ^{\mathrm{3}\xi} \:\frac{{arctan}\left({t}\right)}{{t}}{dt} \\$$$$\int_{\mathrm{0}} ^{\xi} \:\frac{{arctan}\left(\mathrm{2}{x}\right)}{{x}}{dx}\:=_{\mathrm{2}{x}={t}} \:\:\:\int_{\mathrm{0}} ^{\mathrm{2}\xi} \:\frac{{arctan}\left({t}\right)}{\frac{{t}}{\mathrm{2}}}\frac{{dt}}{\mathrm{2}}\:=\int_{\mathrm{0}} ^{\mathrm{2}\xi} \frac{{arctan}\left({t}\right)}{{t}}{dt}\:\Rightarrow \\$$$${I}\left(\xi\right)\:=\int_{\mathrm{0}} ^{\mathrm{3}\xi} \:\frac{{arctan}\left({t}\right)}{{t}}{dt}\:−\int_{\mathrm{0}} ^{\mathrm{2}\xi} \:\frac{{arctant}}{{t}}{dt}\:=\int_{\mathrm{2}\xi} ^{\mathrm{3}\xi} \:\:\frac{{arctan}\left({t}\right)}{{t}}{dt} \\$$$$\left.\exists\:{c}\:\in\right]\mathrm{2}\xi,\mathrm{3}\xi\left[\:/\:{I}\left(\xi\right)\:={arctan}\left({c}\right)\int_{\mathrm{2}\xi} ^{\mathrm{3}\xi} \:\frac{{dt}}{{t}\:}\:={arctan}\left({c}\right){ln}\left(\frac{\mathrm{3}\xi}{\mathrm{2}\xi}\right)\:\Rightarrow\right. \\$$$${lim}_{\xi\rightarrow+\infty} \:{I}\left(\xi\right)\:=\frac{\pi}{\mathrm{2}}{ln}\left(\frac{\mathrm{3}}{\mathrm{2}}\right)\:\:\Rightarrow\:{I}\:=\frac{\pi}{\mathrm{2}}{ln}\left(\frac{\mathrm{3}}{\mathrm{2}}\right). \\$$