Question Number 68660 by aliesam last updated on 14/Sep/19
$$\int{e}^{{x}+{e}^{{x}} } \:{dx} \\ $$
Commented by aliesam last updated on 14/Sep/19
$${perfect} \\ $$
Commented by Prithwish sen last updated on 14/Sep/19
$$\int\mathrm{e}^{\mathrm{x}} \mathrm{e}^{\mathrm{e}^{\mathrm{x}} } \mathrm{dx}\:\:\:\:\:\:\mathrm{put}\:\mathrm{e}^{\mathrm{x}} =\mathrm{t}\Rightarrow\mathrm{e}^{\mathrm{x}} \mathrm{dx}\:=\:\mathrm{dt} \\ $$$$\int\mathrm{e}^{\mathrm{t}} \mathrm{dt}=\mathrm{e}^{\mathrm{t}} +\mathrm{c}=\:\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{x}}} } +\boldsymbol{\mathrm{c}}\:\:\boldsymbol{\mathrm{please}}\:\boldsymbol{\mathrm{check}} \\ $$