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Question-131554




Question Number 131554 by Salman_Abir last updated on 06/Feb/21
Commented by EDWIN88 last updated on 06/Feb/21
A−B=  [((−2       1       1)),((   2        1       6)) ]  A×B^T  =  [((2     3      4)),((1     5      7)) ] [((4      −1)),((2         4)),((3         1)) ]                 =   [((8+6+12       −2+12+4)),((4+10+21      −1+20+7)) ]
$$\mathrm{A}−\mathrm{B}=\:\begin{bmatrix}{−\mathrm{2}\:\:\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\mathrm{1}}\\{\:\:\:\mathrm{2}\:\:\:\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\mathrm{6}}\end{bmatrix} \\ $$$$\mathrm{A}×\mathrm{B}^{\mathrm{T}} \:=\:\begin{bmatrix}{\mathrm{2}\:\:\:\:\:\mathrm{3}\:\:\:\:\:\:\mathrm{4}}\\{\mathrm{1}\:\:\:\:\:\mathrm{5}\:\:\:\:\:\:\mathrm{7}}\end{bmatrix}\begin{bmatrix}{\mathrm{4}\:\:\:\:\:\:−\mathrm{1}}\\{\mathrm{2}\:\:\:\:\:\:\:\:\:\mathrm{4}}\\{\mathrm{3}\:\:\:\:\:\:\:\:\:\mathrm{1}}\end{bmatrix} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\:\begin{bmatrix}{\mathrm{8}+\mathrm{6}+\mathrm{12}\:\:\:\:\:\:\:−\mathrm{2}+\mathrm{12}+\mathrm{4}}\\{\mathrm{4}+\mathrm{10}+\mathrm{21}\:\:\:\:\:\:−\mathrm{1}+\mathrm{20}+\mathrm{7}}\end{bmatrix} \\ $$

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