Question Number 134145 by EDWIN88 last updated on 28/Feb/21
![](https://www.tinkutara.com/question/19149.png)
Commented by Ñï= last updated on 28/Feb/21
![Any time any 2 hands no coincide.I remember.](https://www.tinkutara.com/question/Q134149.png)
$${Any}\:{time}\:{any}\:\mathrm{2}\:{hands}\:{no}\:{coincide}.{I}\:{remember}. \\ $$
Commented by mr W last updated on 28/Feb/21
![please explain what you mean sir!](https://www.tinkutara.com/question/Q134155.png)
$${please}\:{explain}\:{what}\:{you}\:{mean}\:{sir}! \\ $$
Answered by mr W last updated on 28/Feb/21
![assumed the hands move uniformly. say x minutes past 2. position of hour hand: 10+(x/(60))×5 position of minute hand: x 10+(x/(60))×5=x x=((120)/(11))=10((10)/(11)) ⇒(a)](https://www.tinkutara.com/question/Q134148.png)
$${assumed}\:{the}\:{hands}\:{move}\:{uniformly}. \\ $$$${say}\:{x}\:{minutes}\:{past}\:\mathrm{2}. \\ $$$${position}\:{of}\:{hour}\:{hand}:\:\mathrm{10}+\frac{{x}}{\mathrm{60}}×\mathrm{5} \\ $$$${position}\:{of}\:{minute}\:{hand}:\:{x} \\ $$$$\mathrm{10}+\frac{{x}}{\mathrm{60}}×\mathrm{5}={x} \\ $$$${x}=\frac{\mathrm{120}}{\mathrm{11}}=\mathrm{10}\frac{\mathrm{10}}{\mathrm{11}} \\ $$$$\Rightarrow\left({a}\right) \\ $$
Commented by mr W last updated on 28/Feb/21
![old style clocks have hands which don′t move uniformly, but stepwise, see Q17449](https://www.tinkutara.com/question/Q134154.png)
$${old}\:{style}\:{clocks}\:{have}\:{hands}\:{which} \\ $$$${don}'{t}\:{move}\:{uniformly},\:{but}\:{stepwise}, \\ $$$${see}\:{Q}\mathrm{17449} \\ $$
Commented by EDWIN88 last updated on 28/Feb/21
![yes..thanks](https://www.tinkutara.com/question/Q134161.png)
$$\mathrm{yes}..\mathrm{thanks} \\ $$
Answered by bobhans last updated on 28/Feb/21
![∴The time when hands be together = (5×n×((60)/(55))) mins past n o′clock Here n=2 = 5×2×((60)/(55)) = ((120)/(11)) = 10 ((10)/(11)) mins past 2](https://www.tinkutara.com/question/Q134160.png)
$$\therefore\mathrm{The}\:\mathrm{time}\:\mathrm{when}\:\mathrm{hands}\:\mathrm{be}\:\mathrm{together} \\ $$$$=\:\left(\mathrm{5}×\mathrm{n}×\frac{\mathrm{60}}{\mathrm{55}}\right)\:\mathrm{mins}\:\mathrm{past}\:\mathrm{n}\:\mathrm{o}'\mathrm{clock} \\ $$$$\mathrm{Here}\:\mathrm{n}=\mathrm{2} \\ $$$$=\:\mathrm{5}×\mathrm{2}×\frac{\mathrm{60}}{\mathrm{55}}\:=\:\frac{\mathrm{120}}{\mathrm{11}}\:=\:\mathrm{10}\:\frac{\mathrm{10}}{\mathrm{11}}\:\mathrm{mins}\:\mathrm{past}\:\mathrm{2} \\ $$
Commented by EDWIN88 last updated on 28/Feb/21
![thanks](https://www.tinkutara.com/question/Q134162.png)
$$\mathrm{thanks} \\ $$